An arithmetic problem! Urgent, high score offered.

Natural numbers cannot be infinite solutions, use the equation 265x+238y+233z=2114983 to solve x+y+z=n

Take the smallest 233, then the equation is (233x+32x)+(233y+5y)+233z=2114983

That is, 233 (x+y+z)+32x+5y=2114983 233n+32x+5y=2114983

All that remains is to bring any natural number into xy (x+y is less than or equal to n), and then remove the calculated n from the natural number.

9 -10 -1/6 0 -10/3 -10

It is recommended that you use a computer later.

The difference is 10,000.

You fine-tune the unit price of the first one and try it.

For example, if the previous unit price was, it would be changed to.

7 days. Solution: On the first day, I climbed 5 meters up and 2 meters down, so I climbed 3 meters.

On the second day, I climbed another 5 meters up and slid down 2 meters, so 3 meters on the first day plus 3 meters on the second day equals 6 meters.

On the third day, I climbed another 5 meters up and slid down 2 meters, so the 6 meters in the first two days plus 3 meters on the third day equals 9 meters.

On the fourth day, I climbed another 5 meters up and slid down 2 meters, so 9 meters on the first three days plus 3 meters on the fourth day equals 12 meters.

On the fifth day, I climbed another 5 meters up and slid down 2 meters, so 12 meters on the first four days plus 3 meters on the fifth day equals 15 meters.

On the sixth day, I climbed another 5 meters and slid down 2 meters, so 15 meters on the first five days plus 3 meters on the fifth day equals 18 meters.

On the seventh day, because it was an ascent from 18 meters, 18 + 5 23 (m) 23 21, it took 7 days.

This type of question generally does not have an arithmetic, and the answer is written directly after reasoning on scratch paper.

3. Assuming that the number of people in class A is 80 and 10 people are transferred to class B, then the number of people in both classes is equal to 70, then the original number of people in class B is 70-10 = 60, and the number of people in class B is 60 80 = 75% of class A

4. Fifteen percent of the planned electricity consumption is regarded as a unit 1; The actual electricity consumption saved is 15% of the planned electricity consumption; The actual electricity consumption is 85% of the planned electricity consumption.

5. Decimal: 3 4, 25% of the true fraction, 3 4, 25% of the size.

1. The number of participants in the science and technology group is the percentage of the total number of students in the whole grade: 32 200 = 16%, and the number of people participating in the painting group is the percentage of the total number of students in the whole grade: 27 200 =

3. Assuming that the number of people in class A is 80 and 10 people are transferred to class B, then the number of people in both classes is equal to 70, then the original number of people in class B is 70-10 = 60, and the number of people in class B is 60 80 = 75% of class A

4. Fifteen percent of the planned electricity consumption is regarded as a unit 1; The actual electricity consumption saved is 15% of the planned electricity consumption; The actual electricity consumption is 85% of the planned electricity consumption.

5. Decimal: 3 4, 25 percentage, 3 4

Xiao Li spent a total of 216540 + 16530-8750 = 224320

Xiao Wang spent a total of 183400 + 8750-16530 = 175620

Need to make up (224320-175620) 2=24350 yuan.

Xiao Wang should give Xiao Li 24,350 yuan.

Let the quantity A and the quantity B be b, and the total ** is 3000A+36000B, so that it is close to and less than 230000

It is easy to see that buying a piece of B** is equivalent to 12 pieces of A, so the quantity of buying B can be completely replaced by the quantity of 12A. The topic is easy to see as buying a close to not more than 230000, 230000 3000 76··· 2000 so there are 7 answers, and the balance is 2000

76a 0b

64a 1b

52a 2b

40a 3b

28a 4b

16a 5b

4a 6b