Seek help! An arithmetic problem is in a hurry!

Updated on educate 2024-02-09
10 answers
  1. Anonymous users2024-02-05

    I wrapped myself in, and the personal money went into the personal pocket boss discounted 25 yuan, and in fact, after taking out 10, I found 1 yuan back, and I paid 9 yuan. The 9 yuan includes the 2 yuan for the accommodation and waiter. Wouldn't it be a repetition if you added that?!

  2. Anonymous users2024-02-04

    I'm bored, solution: according to the topic.

    30 "Money for Three People Together" -5 "Boss Returned" + 2 "Waiter's Hidden" + 3 "Three People Divided" = 30 yuan.

  3. Anonymous users2024-02-03

    The 5 yuan that the boss will come from will not talk about it first, and so on will explain. In this case, the accommodation fee for the three of them should be 25 yuan in total, so it is equivalent to saying (25 yuan 3 people = each person paid yuan) to the boss, right! Next, let's analyze the returned 5 yuan, the waiter hid 2 yuan + returned 3 yuan = 5 yuan, right!

    The returned 3 yuan 3 people = 1 yuan per person), the waiter hid 2 yuan, it should also be theirs, right? That is, (the decimal point is ignored) [(person] is about equal to 30 yuan! According to my algorithm, in fact, there is no statement that there is less than 1 yuan at all.

    If I want to say that, the 1 yuan is actually mixed in with the 25 yuan for the boss and the 2 yuan hidden by the waiter!

  4. Anonymous users2024-02-02

    If it's a coin, it must be stuffed into that machine and exchanged for a set.

  5. Anonymous users2024-02-01

    In step (x+2)(2x-1)-2(x+2)=(x+2)(2x-3), (x+2) is used as the common factor to extract the pin.

    x+2)(2x-1-2)=(x+2)(2x-3), also filial piety is that there are (x+2) losses on both sides can be extracted, and then the rest on both sides will be calculated normally.

  6. Anonymous users2024-01-31

    x+2) (Cong Han x-1)-2 (Seeping Sakura laughing x+2) uses the multiplication associative law, and it is enough to turn x+2 as a number, and the polynomial becomes.

    x+2)[(x-1)-2]

    x+2)(x-1-2)

    x+2)(x-3)

  7. Anonymous users2024-01-30

    7 copies. Elimination method, the sum of the two books costs 92, first assume that "Interesting Mathematical Problems" bought 1 copy, then "Intellectual Challenge" bought (92-8) 18, not an integer, elimination, and so on.

  8. Anonymous users2024-01-29

    Use 1,2,3 to substitute, because it can only be an integer, so it is 7

  9. Anonymous users2024-01-28

    2 intellectual challenges and 7 others.

  10. Anonymous users2024-01-27

    =1/5x^3y^4z^4

    1/5 times x to the 3rd power, y to the 4th power, z to the 4th power.

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