A few basic high school chemistry problems, urgent!!

1.Aluminum powder reacts with NaOH to form sodium metaaluminate (Naalo2), which does not form alkali.

2.This is mainly the oxidizing property of chlorine, which can oxidize Fe2+, which itself is reduced to Cl-3Magnesium combustion is essentially a chemical reaction, hydrogen has only one electron at the outermost, magnesium has only two, and the two cannot be combined.

4.No, chlorine is an acidic gas that does not react with concentrated sulfuric acid, so it can be dried with concentrated sulfuric acid.

1. Because AL is amphoteric hydroxide, it will react with strong alkalis.

2, because Cl2 is more oxidizing than FeCl2.

3. Hydrogen is more reducible than magnesium.

4, no,

1.Because Al(OH)3 formed by the reaction of Al and NaOH reacts with NaOH to form NaALO2, which is dissolved in water, so that Al(OH)3 does not adhere to Al and hinders the progress of the reaction.

2al+2h2o+2naoh=2naalo2+3h2↑2.Because Fe3+ is more oxidizing than Cl2, Fe2+ can be oxidized by Cl2 to Fe3+

3.Because it is difficult for MG to react with H2 to form MGH2, metal hydrides are only limited to alkali metals (the first main group) and Ca, Sr, and Ba in the second main group

4.No.

AL +2NAOH = 2NAaio + 2H2 gas arrows.

2. Chlorine is a strong oxidizing agent.

3. I really don't know about this.

4. No, because the laboratory uses concentrated sulfuric acid and manganese dioxide to react to produce chlorine.

1.If aluminum hydroxide is generated, aluminum hydroxide will also react with sodium hydroxide, 2Chlorine gas has strong oxidizing property and divalent iron ions are reducible, so the two undergo redox reaction.

3.Hydrogen has no oxidizing properties.

4.Not.

1. Al(OH)3 is produced, but it reacts with excess NaOH immediately after its production to form Naalo2

2. Redox reaction... There is nothing to say, the price is marked, and the line bridge is drawn.

3. Combustion is a redox reaction, all the metals you have learned are reducing agents, and hydrogen is also a good reducing agent, so it does not react.

4. I'm not sure, it doesn't seem to work.

4 grams of sodium hydroxide is, so sodium ions are also, hydroxide is also, the ratio of the number of ions of sodium ions to the number of water molecules is 1:100, then the amount of substances of water molecules is 10mol; Hydroxide is also, hydrogen ions are required naturally, corresponding to sulfuric acid, the molar mass of sulfuric acid is 98g mol, and the mass is.

The amount of water is 10mol, hydroxide ions, hydrogen ions, sulfuric acid is needed, that is, 49 grams of sulfuric acid!

Since you don't give the temperature of the initial and the two states after pressing into the vacuum bottle, we consider this to be an isothermal process, 1) according to p1v1=p2v2, p2=p1v1 v2, hydrogen partial pressure: p=

Partial pressure of oxygen: p=

Partial pressure of nitrogen: p=

2) Total pressure p=

3) Since the temperature of the three gases is the same and the volume is the same, according to PV=NRT, the molar fraction is proportional to the respective partial pressure, ie.

Hydrogen mole fraction: x=

Oxygen molarity fraction: x=

Nitrogen molarity fraction: x=

1. Partial pressure is the pressure at which each gas occupies the entire container individually. The temperature before and after the front and back is unchanged, and the result can be obtained by using PV=NRT.

2. According to Dalton's partial pressure law, the sum of the partial pressures of each gas is the total pressure.

3. Still use pv=nrt to calculate.

High school models are all based on ideal models. This is a question of calculating all the problems entirely in terms of pressure. Which of the following answers I agree with?

According to the chemical equation, it is known that for every 2L CO2 reaction to produce 1L O2, the gas in the container is reduced by 1L, and the gas in the container is reduced by (V-W)L, then the CO2 participating in the reaction is 2(V-W)L. The answer is C

The two react, and every liter of carbon dioxide consumed produces half a liter of oxygen, and that's the idea, and I think you know the answer.

Fe2O3 mass is calculated by itself. 2Al+Fe203===AlCl3+2Fe This is the reason why the 3-valent patch in iron oxide becomes 2-valent iron. Since the question stem gives the condition that the cation is only a finch and there is Fe2+, the above equation in Al is over the amount of collapse shed.

Then the original substance is Al, Fe, Al2O3Then the reactions carried out are 2Al+2NaOH+2H20===2NaAl02+3H2 and Al203+2NaOH===2NaAl02+H20, and it is not difficult to find that a part of sodium hydroxide reacts with an aluminum atom to form a part of sodium metaaluminate. That is, a sodium hydroxide reaction with an aluminum reaction is 1 to 1

Since the aluminum atoms in alumina are all derived from aluminium elementals. The second package can be obtained: the reaction is hydrogen ion with Al,Al203,Fe reaction2Al+6HCl===2AlCl3+3H2 and Al203+6HCl===2ALCI3+3H20, it can be found that both the aluminum element and the aluminium in the alumina are one aluminum atom and react with 3 parts HCl. There is a first reaction to get aluminium for can get a second part of al with al203 total consumption of hydrogen ions for moles.

The remaining molar hydrogen atom (stem given).Then the remaining molar hydrogen ions are reacted with iron element, and 1 iron and 2 hydrogen react to obtain molar iron, so the age of iron oxide contains mol. But this is the amount of one serving, so multiply by 2

2 gas is 2al+2naoh+2h20===2naal02+3h2 hydrogen is only produced in this reaction, the key is to calculate the mass of aluminum elemental after the reaction. Since the amount of iron oxide is known to be mol2al+fe203===alcl3+2fe, then the consumption of aluminum is moles, and the remaining aluminum is moles. Moles of hydrogen are produced.

Please point out any errors.

Supplementary Servant Wang replied: Liang Zai.