The application problem of the system of equations also needs answers

c=100+ yd=(1-t)y;c=100+ with the rubber brother base into y=c+i+g=100+ y= Li Liang carefully uses the formula of the first question y=c+i+g=100+; The multiplier of g is 100 36 = 25 9 fiscal surplus = t-tr-g = t=, dust deficit c = 100+ y = c + i + g = 100 +, y = 800 , multiplier 1

The application of a system of equations is as follows:

1. A unit goes out to visit. If there are 45 people in each car, then 15 people have no seats: if there are 60 people in each car, then there is exactly one car free, how many cars are needed, and how many people are in the unit?

2. If a person walks on a circular track with a circumference of 400 meters, if two people walk in the opposite direction from the same place at the same time, they will meet after 2 minutes, and if two people walk in the same direction from the same place at the same time, then after 20 minutes, the two people will meet after 20 minutes, and the speed of the two-year-old nuclear man will be faster.

3. The number of basketballs is 3 times less than the number of volleyballs, the ratio of the number of footballs to the number of volleyballs is 2:3, and there are 41 of the three kinds of balls.

4. Floating on the water, waiting for the passengers to find out, the ship immediately a passenger ship against the water, a passenger on the ship dropped a buried item, turned around to chase, it is known that the ship from the U-turn to catch up with a total of 5 minutes, ask the passenger lost the item, is it found a few minutes later?

6. When a boat is found to be leaking, some water has entered, and the water enters the boat at a uniform speed, if 10 people can wash the water, it can be finished in 3 hours, 5 people can be washed in 8 hours, and if the water is finished in 2 hours, how many people are needed to wash the water.

7. There is a pasture, the grass grows evenly every day (the amount of grass grows every day is equal), if 24 cattle are grazing, the grass will be eaten in 6 days, and if 21 cattle are grazing, the grass will be eaten in 8 days, and the amount of grass eaten by each cow is equal

1) If you graze 16 cows, can you eat the grass in a few days?

2) How many cows can you graze at most so that you never run out of pasture?

Because the square of a number and the absolute value of a number must be greater than or equal to 0. 2x+y-1=0

3y-x=0

x=3/7y=1/7

x+4y =1

Because |a|+a=0

Then a is not positive at all times.

So a=-1

1, a student took a car from home to the Grand Theater to listen to **, when the speed of the car was 20 kilometers when he went to the town, the road should be blocked when he returned to the source, and the car had to take a detour, so he walked 12 kilometers more than when he went, although the speed of the car increased by 4 kilometers, but it took 15 minutes more than when he went, and asked the student how far away from the Grand Theater.

Solution: Let students go to the Grand Theater is xkmRule.

x 20+15 60=(x+12) (20+4) so x=30

(1) Solution: If the amount of A is x, then the amount of B is 68-x6%x+(68-x)*5%=

6%x+1%x=

x=42b:68-42=26

2) Solution: If the ten digits are x, then the single digit is 2x(2x*10+x)-(10x+2x)=3620x+x-10x-2x=36

9x=36x=4, the single digit is: 4*2=8

3) Solution: If you go to A, you will be 20-x people, and if you go to B, you will be 27+x=*2

27+x=78-2x

3x=51x=17

Then to B: 20-17=3

4) Solution: If x people are enrolled in the seventh grade this year, the first year of high school is 500-x people x (1 + 20%) + 500-x (1 + 15%) = 500 (1 + 18%) x = 300

Then the first year of high school is: 500-300=200

Next year's 7th grade: 300*

Next year's first year of high school: 200*

will be opportunistic, and if you have this mind, you might as well study hard.

Set: X tons for large trucks and Y tons for small trucks.

Solution: {2(2x+5y)=36 1 { 4x+10y=36 15(3x+2y)=80 2 15x+10y=80 22 minus 1 to get: 11x=44 x=4 Substituting x=4 into 1 gets:

4×4+10y=36

16+10y=36 10y=20 y=2 x=4 (tons of hours) y = 2 (tons of hours).

Verification: 2 (2 4+5 2)=2 18=36;

A: Large trucks carry 4 tons per hour and small trucks carry 2 tons per hour. (The title says 2 hours, 5 hours, so the calculation should be calculated based on the number of tons per hour.) ）

If the big truck is A, the small truck is B.

2a+5b=18

3a+2b=16

a=4，b=2

Let the big car be x and the small car be y.

2（2x+5y）=36

5（3x+2y）=80

Solution. x=4

y=2A: The big car transports 4 tons and the small cart transports 2 tons.

Little pot friend,You don't have to go so hard to get it and ask.。。。 You can just ask someone about this... oh my god

Solution: Let the volume of large trucks be x and small trucks be y

2（2x+5y）=36

5（3x+2y）=80

The solution yields x=4 and y=2

Let the large truck be a and the small truck be b, 2a + 5b = 36 2

3a+2b=80÷5