Two questions for a function, one question for a quadratic function?

1. If the point A(1+M,2M-1) is on the X-axis, then 2M-1=0, M=1 2, the point A is (3 2,0), the point P(3M+3,4M) is brought into M to get P(9 2,2), and the symmetry point about Y is (-9 2,2).

2. According to the definition of a circle, this point should be a circle, and the equation for a circle is (x-3) 2+y 2=25

Point a(1+m,2m-1) is on the x-axis, so 2m-1=0,m=1 2p(9 2,2) With respect to the y-axis symmetry point m(-9 2,2) Let the coordinates of the found point be (x,y).

From the distance formula there is, (x-3) 2+y 2=25 so the coordinates of all points satisfy (x-3) 2+y 2=25 on the coordinate axis, find all points with the point p( at a distance of 5.

Since a is on the x-axis, then 2m-1=0

m=, 2)

About the point of y-symmetry (, 2).

x-3)^2+y^2=5^2

1.aOn the x-axis, find m=1 2

p(9 2,2) with respect to the y-axis symmetry point m(-9 2,2).

According to the equation given to the world, we can get the value of the function at the point a as 1:

The value of the function at 1 = 2) 2 * a + 6 * 2) -a = 4a - 12 point b is k 2 - a:

k^2 - a = 1

Subtract the right side of the equation between the two equations to get :

k^2 - 4a - 12) =0

Transform the demeanor Jane to get:

k^2 = 4a + 12

Since the value of the function at point b on the image of y1 is k2 - a, and when y1 > 0, the value of this function must be greater than 0. Therefore, we can derive the following inequality:

k^2 - a > 0

i.e.: 4a + 12 - a > 0

Simplification yields: a > 3

Therefore, when a searches for -3 >, the value of the independent variable x is in the range of all real numbers.

Solution: The ordinate of the m point is y=4 c-b 2 4 2 8 1 (2a-4) 2 4=(8a-4 2-16 16 ) 4=a 2 106a-4 The ordinate of the vertex is in a parabola The quadratic coefficient of the parabola is 1 "Quemin 0 The image opening has a maximum value downward, and the oldest value is the maximum value of the vertex parabola, ymax=4ac-b 2 4 = 4x(-1)x(a4)-36 4(x(-1)=5

y=8(x<=3)

y=(x-3)*>3)

2) Because of "8 yuan", it should be brought into 2 formulas, that is, to get the solution of the stove shoot suspicion x=7 scheme He Liangyi, y=( get y=

Scheme. 2. Concealed hand y=(get y=.)

Hello, yangxin3468707

1. (1) Y is proportional to x.

Let the analytic formula of the function between y and x be: y=kx

When x=1, y=

The analytic formula for the function between k= y and x is: y=

2) The image of the primary function y=kx+b passes through the points (2,5) and (-3,-5), 2k+b=5

3k+b=-5

The solution is k=2 and b=1

The analytic formula of the function is: y=2x+1

Solution: From the data in the table, it can be seen that y and x are a one-time function.

Let the relationship between y and x be: y=kx+b

Substitute the data in the table to obtain.

2k+b=-5

1k+b=-2

The solution yields k = 3 and b = 1

The relationship between y and x is: y=3x+1

2) From (1), we can see that the relationship between y and x is: y=3x+1 when x=25, y=3 25+1=76

When y=25, i.e., 25=3x+1, the solution is x=8

Solution: (1) As can be seen from the figure, 10,000-2,000=8,000 cubic meters of natural gas were injected on Sunday;

2) When x>= , let the analytic formula of the function of the gas storage capacity y (cubic meter) and the time x (hour) in the gas storage tank be:

y=kx+b ( is constant, and k≠0 ), and its image passes through the point (,10000) ,8000) and the solution is k=-200

b=10100

Therefore, the analytical formula of the function is y=-200x+10100

3) can be 18 cars to refill the gas need 18 * 20 = 360 (cubic meters), gas storage capacity is 10000-360 = 9640 (cubic meters), so there are: 9640 = -200x + 10100, the solution: x = , and from 8:00 to 10:30 difference hours, obviously have: < Therefore, the 18th car can be refilled before 10:30 on the same day

4)-200x+10100 ≥8000

200x≥-2100

x< = 8,000 cubic meters of gas in the gas storage tank of the gas station on Sunday (8:00--18:30).

1.United.

L1 and L2 linear equations, the resulting solution is the coordinates of the intersection point.

Falls in the fourth quadrant.

The parabola y=x2+bx+c crosses the origin, so c=0; y=x 2+bx The distance between the parabola and the two intersections of the x-axis is 3, and since one intersection is the origin, the other is (3,0) or (-3,0).

y=x2+bx intersects (0,0) (b,0) with x-axis, so b=3 or -3

The analytic formula is y=x 2+3x or y=x 2-3x