How to analyze math question types, math analysis questions?

I'll talk about it from my high school experience, I don't know if it's useful.

As your teacher said, the questions are always the same, and they always focus on a fixed method to solve the problem, but the difference is the data of the question.

First of all, there is a law to solve the problem: the higher order will be the second, the multivariate elimination, the constant separation, and the variable concentration. There are many ways to expand around this sentence:

For example, the "constant separation method" and "commutation method" in the problem of solving inequality inequality. Another very important sentence is that solving the problem is actually the process of transformation, bringing the desired and the conditions closer to the problem, finding the relationship between the conditions of the problem and the problem according to the verification, and then looking for the proof method.

The second is the question type and method. Methods are divided into mathematical ideas and common problem-solving techniques, which can be easily found by looking for relevant books in bookstores. The question type is divided into analytic geometry, solid geometry, trigonometric functions, etc., these more test papers can master the relevant laws, the important thing for each question is to see the method behind it, such as the function summation problem, which can be split and eliminated, or can be summed in reverse order, the question is used to consolidate the mathematical knowledge that has been learned, when a certain method has been mastered, you can find other types of questions to practice, until you master all the methods.

In another 10 days of college entrance examination, let's encourage you.

Analytical math problem type is to find the common point in various problems, although many problems look different, but the core method is the same, for example, at the end of the list of some similar equations to solve!!

There are many types of math problems, and the key is what knowledge you can derive according to the conditions, and the knowledge that comes out of the conditions is related to what you are looking for.

You don't need to deliberately memorize how to solve this type of problem, otherwise it will be imitation, not training your mathematical thinking.

There are two ways, the first is to slowly master what to do in the process of doing more questions. Extreme - Sea tactics.

The second is to summarize the various types of practices. Extreme - Crash hard back.

Both methods are feasible, the key is that you have to think about the problem when you encounter it, and the connection between the conditions and the result is related to your usual thinking habits and knowledge mastery.

The quadratic function should first focus on the approximate type of the image, and draw a sketch (find the key points, the relationship between the binomial coefficients and the image, etc.).

Because <0, 2>f(x)dx itself is a definite integral, and the result is constant.

Then on [0, 2] the integral is a constant multiplied by 2. Chunchang.

The answer is as follows: Brother Shen Li envy and filial piety.

The entrapment method is adopted.

The original < 1 [n*(n-1)]+1 [(n(n+1)]+1 [(2n-1)*2n].

1/(n-1)-1/(2n)……Type 1.

Original formula: 1 [n*(n+1)]+1 [(n+1)*(n+2)]+1 [(2n+1)*2n].

1/n-1/(2n+1)……Type 2.

When n approaches infinity, both 1 and 2 tend to 0

So the limit of the original formula is equal to 0

2) Adopt the same loose sail principle.

Original 1 [(n 2+1)+(1 n*1 2) 2] hail 2) 2].

1/[n+1/n*1/2]+1/[n+1/n*2/2]+…1/[n+1/n*n/2]

1/[n+1/2]+1/[n+1/2]+…1 [n+1 2]=n [n+1 know-sell2].

The original < 1 n+1 n+1 n+......1/n

n n = 1, so the limit of the original formula is 1 when x approaches infinity

Summary. Hello, can you take a look at this question, let me see if it will?

Hello, can you take a look at this question, let me see if it will?

Summary. The concept of indefinite integrals assumes that f(x) is an original function of f(x) on a certain interval i, then the whole original function f(x) + c (c is an arbitrary constant) is said to be the indefinite integral of the function f(x) on the interval i. and is represented by the notation fxdx, i.e.:

fxdx=fx+c where the notation is called the integral sign, f(x) is called the integrand, f(x)dx is called the integrative expression, x is called the integral variable, and c is the integral constant. Finding the indefinite integral of the function f(x) is to find the whole original function of f(x), so you only need to ask for a primitive function f(x) of f(x) and add any constant c to get the indefinite integral of f(x).

Hello, what is the analysis topic? I'll see if I can answer it for you.

The concept of indefinite integrals is that f(x) is an original function of f(x) on a certain interval i, then the whole original function f(x) + c (c is an arbitrary constant) is called the indefinite integral of the function f(x) on the interval i. It is represented by the symbol fxdx, i.e., fxdx=fx+c where the symbol is called the integral sign, f(x) is called the integrand, f(x)dx is called the integrand expression, x is called the integral variable, and c is the integral constant.

To find the indefinite integral of the silver function f(x) is to find the whole original function of f(x), so only the slag you need to find the original function f(x) of f(x), and add any constant c to get the indefinite integral of f(x).

The second question can be searched by the little ape.

Summary. The definition of an indefinite integral is to find the original function f(x) for a given function f(x). That is, if f(x) is the derivative of f(x) on an interval, then f(x) is a primitive function of f(x) on that interval.

Now to prove the indefinite integral in the problem: let u = x + x +a), then du dx = 1 + x (x +a) replace 1 + x (x +a) in du dx with f(x), and we can see that dx (x +a) is the form u+c. So we have:

dx/√(x² +a²) ln|x + x² +a²)|c where c is a constant, |x + x² +a²)|The value is taken absolutely. Certification.

Dear, please provide complete information about the topic.

The Li bury definition of the indefinite suppression deficit integral is that for a given function f(x), find the original function f(x) for a given function. That is, if f(x) is the derivative of f(x) on an interval, then f(x) is a primitive function of f(x) on that interval. Now to prove the indefinite integral in the problem:

Let u = x + x +a), then du dx = 1 + x (x +a) and replace 1 + x (x +a) in du dx with f(x), then you can see that dx (x +a) is the form of u+c. Therefore, we have: dx (x +a ) ln|x + x² +a²)|c where c is a constant, |x + x² +a²)|The value is taken absolutely.

Certification. Write these two clearly.

Because of the stupid macro rent, this original formula can be simplified to [1,3]1 (1+x)dx = ln|1+x| |1,3] =ln(4) -ln(2) =ln(2) Therefore, the value of the original limit is ln(2).

Summary. Kiss, please provide us with your <> topic

Kiss, please provide us with your <> topic

Kiss, please describe your problem more specifically and talk to the teacher in detail, so that the teacher can better help you.

Okay, just wait a minute, I'll answer the <> right away

Students, you can understand <> by looking at it

This title gives a proof.

I look at this example problem, it should be proved by the definition of that limit, that is, for any small number, I can always find a value of n, so that the value of this formula is smaller than that small number, this problem is very clear.