Elementary 21 to math problems solving with inequality equations .

There are 3 teams in a workshop that plan to produce 500 products within 10 days (each team produces the same amount every day), according to the original production speed, can not complete the task, if each team produces 1 more product per day than the original, can complete the task in advance, how many products per day each team originally produced?

So the answer should be:

Solution: Each team used to produce x products per day.

According to the title, you can get 3*10x<500

3*10（x+1）>500

The value of 15 and 2/3 x should be an integer, x = 16 Answer: Each group used to produce 16 products per day.

Each team used to produce x products per day.

3x*10<500

3(x+1)*10>500

Solve 47 3 Because x is an integer, x=16

Solution: Each team used to produce x products per day.

According to the meaning of the question, the group of inequalities can be obtained:

3*10x<500 --1)

3*10（x+1）>500 --2)

Solution: again x should be an integer, so x=16

A: Each group used to produce 16 products per day.

Solution: Each team used to produce x products per day.

Title: 3x 10 500

3(x＋1)×10≥500

Solution: x 50 3

x≥47/3

x=16A: Each group originally produced 16 products per day.

Give it to me!

Summary. Please send me the title.

Please send me the title.

Hold on. Your x don't write like that.

And count the reels [Eat Whales].

You'll see how I write it later.

You'll be there. You got the first inequality wrong.

Your handwriting is too hard to read<>

1 solution: Let the number on the single digit be x, and the number on the ten digit number is x+3

50x+(x+3)*10<60

The solution is 11 20 x = 2, x + 3 = 5

A: This two-digit number is 52

2 solution: Let the velocity of B be xkm h

x*1≤25+5

x*solution yields 25 x 30

A: B's speed should be controlled between 25km h and 30km h.

1. If the two-digit number is greater than 50 and less than 60, the ten-digit number is 5 digits, and the ten-digit number is 3 less than the ten-digit number, then the single-digit number is 2

So this two-digit number is 52

After h, the distance difference between A and B is 5*5=25km, and the speed of B is v

Then v*1 25+5=30

v*, get v 25

Therefore, B's speed should be controlled between [25,30].

1.Let the single digit be a and the ten digit be b, according to the question a=b-3....1), 50 (2), (1) bring in (2) to get 50<11b-3<60, because b is an integer, b=5, then a=2, the two-digit number is 52

2.Let the speed of B be x (in km h), and the time it takes for B to catch up with car A is tThen x*t=5*5+5*t,t=25 (x-5), and 1<=t<=, i.e., 1<=25 (x-5)<=,25<=x<=30

1.Let the number of tens be x, then the single digit is (x-3), and this number is 10x+(x-3)10x+(x-3)>50

10x+(x-3)<60

It's good to ask for it again.

Solution: If the price of 300 is 50% of the higher purchase price, then the purchase price is 300 (1+50%) 200 yuan, if the price of 300 is 100% of the higher purchase price, then the purchase price is 300 (1+100%) 150 yuan, so the purchase price of clothing is between 150 yuan and 200 yuan. Let our counteroffer be $x, then the inequality group can be listed as follows:

150 (1+20%) x 200 (1+20%) solves: 180 x 240

So you should make a counteroffer between 180 yuan and 240 yuan.

From the 50% and 100% of the higher purchase price, it can be seen that the purchase price of this garment is 150 200 yuan, and a 20% increase in the price can make a profit, so the counter-offer range is: 180 240 yuan.

Solve by inequality: Let the purchase price be $x, then 300-x>=, and 300-x<=x.

Solution, 150<=x<=200

So, 180 < = < = 240

The counteroffer range is 240 300.

1. （1-a）x+1＞2

1-a）x＞1

When 1-a 0, x 1 1-a (non-conforming).

When 1-a 0, x 1 1-a so, -a -1 so, a 1

2 3m(x+1)+1=m(3-x)-5x3mx+3m+1-3m+mx+5x=0

4mx+1+5x=0

4m+5)x=-1 because x 0 so 4m+5 0 so m -5 4

3 2x+y=m-1 ＝ 4x+2y= 2m-2(4x+2y)-(3x+2y)=(2m-2)-(m+1)x=m-3

Same as above, y=5-m

Because x y so m-3 5-m so m 4

Solution: If the price of 300 is 50% of the higher purchase price, then the purchase price of this year is 300 (1 + 50%) 200 yuan, if the price of 300 is 100% of the high purchase price, then the purchase price of hunger is 300 (1 + 100%) 150 yuan, so the purchase price of the clothing is between 150 yuan and 200 yuan. Let our counteroffer be $x, then the inequality group can be listed as follows:

150 (1+20%) x 200 (1+20%) solves: 180 x 240

So you should make a counteroffer between 180 yuan and 240 yuan.

x+y=2k

x-y=4 is obtained by .

x=y+4 substitutes for .

y+4+y=2k

2y=2k-4

y=k-2 substitutes y=k-2 into the ante at which age.

x=k-2+4

x=k+2 so original.

The solution of the equation. is {x=k+2

y=k-2 because x 1, y 1

So k+2 1

k-2 1 solution -1 k 3

3x-5y=k

2x+y=-5

The solution yields {x=k 5-1

y=-3-(2k)/5

x,y is the negative celery number.

k muffled 5-1 0

3-(2k) 5 0 solution.

Set rented x cars, because the last one was not empty and dissatisfied.

So there are 30x>213

30(x-1)<213

So they rented 8 cars.

Set up to rent x cars.

30x>213 according to the title

Answer: They rented 8 cars.