Question 8 how to do it, the detailed process, question 8 how to do it, what are the steps

（1+sin10) +1-sin10)

sin5^2+cos5^2+2sin5cos5)+√sin5^2+cos5^2-2sin5cos5)

abs(sin5+cos5)+abs(sin5-cos5) because 5 is in the fourth quadrant, i.e., sin5<0, cos5>0 and 3 2*pi<5<7 4*pi, then abs(sin5) > abs(cos5).

Therefore (1+sin10) +1-sin10)=abs(sin5+cos5)+abs(sin5-cos5)=-sin5-cos5-sin5+cos5=-2sin5

（1+sin10）+√1-sin10）

sin^2 5 + 2 sin5 cos 5 + cos^2 5) +sin^2 5 + 2 sin5 cos 5 + cos^2 5)

sin 5 + cos 5)^2 + sin 5 - cos 5)^2

In the case of an angle system, (sin 5 + cos 5) > 0, (sin 5 - cos 5) < 0

The above equation becomes (sin 5 + cos 5) -sin 5 - cos 5) = 2 cos 5

Apply to the trigonometric identities sin 2 x + cos 2 x = 1 and sin 2x = 2 sin x cos x

Hope it helps.

Pretty simple, d

The process, as the buddy above said, is very comprehensive.

Debit: Bank deposit 1410

Credit: Long-term equity investment shed shouting capital - cost 3600 * 25% = 900 - loss chain socks profit adjustment 960 * 25% = 240

Changes in other equity seepage 600 * 25% = 150

Investment income 120 option A

A speed 40, ran for 15 seconds, used up 3 8, corresponding to 3 8 running the track. That is, B ran 5 8 of the runway in 15 seconds, then B speed is 15 divided by 5 8, which is equal to 24 seconds!

A and B run in the opposite direction, then the total speed is added, the total speed is 40 + 24 64 A and B run in the same direction, then the total speed is subtracted, the total speed is 40 24 16 when running in the same direction when meeting time 64 15 16 60.

Learn to use the relationship between the two total speeds. This is not the same as the situation of A and B at the same time!

s=1 2, the area of a semicircle with a diameter of 6 meters.

Solution: If the chief engineer is set as a unit of 1, then A does 1 12 every day, and B does 1 18 every dayShejia did it for x days.

That is, Lushan: B then does the rest: (1-1 12) 1-1 12) Dabu (1 18) + x = 16 solution : x = 4 then B does 16-4 = 12 days.

A: A did it for 4 days and B for 12 days.

The shortest straight line between two points.

That is, A to B is the shortest to go directly along the half surface.

Calculate the circumference of the base circle by half.

If you have a high, you can calculate it.

Form a rectangle along a busbar, and the diagonal is the find.

This question is a diagonal of a rectangle.