If you think you are good at math or know how to code, please !!

Well, that's interesting.

Programming is simple and comes out in seconds.

Because there are fewer possible combinations, only 9! /3！, i.e., 60,480 combinations, and then verify them one by one to draw conclusions.

However, programming is no way to do it, and pen arithmetic can exercise thinking, let me take a look at pen arithmetic.

I have been doing it for a long time without an answer, but one thing can be proven, one of the denominators must be more than a dozen.

If it's difficult, you have to think about how to deal with the denominator when programming.

EF is the midpoint of AB, AC.

EF BC, and EF = BC 2

A for AD BC to BC to D, F for FG BC to BC for G, over CH EF, over EF extension line to H

ch=fgfg/ad=cf/ac=1/2

s△abc=ad*bc/2

s△cef=ef*ch/2=[(bc/2)*(ad/2)]/2=s△abc/4=6

1. Because EF is the midpoint of both sides, 2. The area of AEC: 24 2=12 (cm) The area of equal base and equal height is equal.

3. The area of EFC: 12 2=6 (cm)....The area of equal base and contour is equal.

Obviously, the area of the triangular BCE is half the area of the triangular ABC, which is 12 square centimeters. (Same bottom, half as high).

In addition, the area of the triangular CEF is half that of the triangular BCE, which is 6 square centimeters. (Same as high and half at the bottom).

EFC is the same height as AEF, and the area of the shaded part is equal to the area of AEF, and it can be seen from the median line that the area of AEF accounts for 1 4 of the total area, so the area sought is 6

Because EF is the midline on the side AC of the triangle AEC, the area of the triangle AFE and the triangle EFC are equal, (because the AF and FC sides of the two triangles can be regarded as the bottom edges respectively, then their bottom edges are equal, and the height on the bottom edge is high) In the same way, the area of the triangle AEC and the triangle CEB are equal, in summary, the area of the shadow part EFC is equal to half of the area of the triangle AEC, and AEC is equal to half of the area of the triangle ABC, So the area of EFC is equal to 1 4 of the area of the triangle ABC, which is equal to 6.

is 1 4 total area 24 4 = 6 square centimeters.

6.The shaded part is half the height and bottom edge of the triangular ABC, so the area is 1 4

157 23/156

23 and 23 156

168/169 67

66 and 102 169

132 and 1 130/131

1 and 1 130

51 and 2/3 5/3 + 71 and 3/4 7/4 + 91 and 4/5 9/5 9

358 358 and 358/359

The first person 50*80%=40 points.

The second person 80*80%=64 points.

The usual grades given by the teacher are full marks. That's 20 points.

So the first person is 40+20

The second person is 64+20

60 points are not from 50 + 10 points, it is 50 * 80% + 20 points, and 84 points are 80 * 80% + 20 points, not directly 80 + 4 points.

The first person, the practical score: 50, the usual score: 100, the second person, the practical score: 80, the usual score: 100, you can calculate the total score by yourself, and it will be clear.

Both of them usually score 20 points, just do a simple calculation.

Usually the score is 20 points out of 20, and the teacher gives everyone a full score, so there is no relatively much and relatively little.

Answer: The questions are not clearly expressed and need to be improved.

1. The median is 74

2. Median average height.

The median is ranked from smallest to largest.

Set x days for both teams to be completed at the same time.

x／60 ＋ x／40＝ 1；Core x 24;

Team A repaired 24 15 60 6 km of roads.

Yiqing shouted that the team repaired 24 15 40 9 kilometers of Yumai wild road.

A holds (2a squared + 1) shares, B holds (2a squared + 1) - (a-1) shares C shares:

5a squared - 3a - 2) - (2a squared + 1) - [2a squared + 1) - (a-1)].

5a 2-3a-2-2a 2-1-[(2a squared +1)-(a-1)].

3a 2-3a-3-[(2a squared + 1)-(a-1)] = 3a 2-3a-3-2a 2-1+a-1=a 2-2a-5

C** is worth MX (A 2-2A-5).

Dividends MX(A 2-2A-5)x18%.

Removing the tax, we get mx(a 2-2a-4)x18%x(1-20%)=mx(a 2-2a-4)x(18 125) =m(a 2-2a-4)x144%

Solution: A: 2 A 2 + 1 shares.

B: 2 a 2 +1-(a-1).

2a 2-a +2 shares.

C: [5a 2 - 3a - 2] -2 a 2+1] -2a 2-a+2].

A 2 -2a - 5 shares.

C should be: [a 2 -2a - 5] * m * 18% * [1-20%] = * m * a 2 -2a - 5].