How much power transformer is required for a load of 2900kw

1. If the electrical load is 2900kw, the power factor.

Assuming yes, the apparent capacity under this load is:

s1 = active power power factor = 2900

2. The efficiency of the transformer is generally the highest at about 70% when the "copper loss = iron loss", so the capacity of the transformer is optional

s2=s1/s1=1529/

3. Therefore, you should choose a 4500kva transformer, and consider a few issues in the actual choice, if it is a two-part electricity price, it is a basic electricity fee, so the capacity can be smaller, such as choosing 3500kva, if it is a single electricity price, it will be developed in the future, you can choose a larger one, such as 4000kva.

Your question is vague and lacks a few necessary conditions kw is one device, or all devices; 2. If it is all equipment, what is the power of the main equipment? How many are used at the same time? 3. What is the nature of the factory?

Whether it's a continuous load or an interstitial load) you have to figure out those before you can decide on the transformer.

Let me teach you a few practical formulas:

Metallurgical textile cement plant, kilowatt is kilovolt ampere;

machinery manufacturing and processing plant, kilowatt and half kilovolt ampere;

The rest of the light industry and chemical plants, kilowatts are seven folds of kVA.

You have too few conditions for this problem, I don't know what the load is, and I don't know the utilization rate, and I don't know the high voltage and low voltage, but I generally calculate that at least 4000kva transformer, such a capacity transformer 10kv voltage is relatively small, or use 35kv or 110kv.

How much power can a 200kva transformer carry, and how to calculate it? Today is a long time to see.

The power of the equipment with the economic operation energy of the 200kva transformer is 80% of the 200kva, that is, 160kw, of course, it can also be overloaded in a short time (2-3 hours), and it can be greater than the nominal 20% that is, 240kw.

The voltage level is 10 0 4kV and the capacity of the transformer is 200kva with a rated current of 200

If you want to ask how many kW can be driven, this must depend on the power factor, however, generally take, about 160kW.

If you use a single multi-strand copper core cable of the national standard, 95 square is enough (safe current carrying capacity 325 345A), if you choose a combination cable, 120 square is enough.

Our company is a casino transformer is 200kva The three currents are A (210A) B (188A) C (165A) We run 8-9 hours a day Ask for high fingers to point out whether our transformer can withstand How to calculate Please tell me more details I am a novice and want to develop this aspect I should start learning where thank you.

Answer: The rated current of the transformer is i=s (.

The three-phase current of your company is item A (210A) B item (188A) C item (165A), which does not exceed 288A, so you can use it with confidence.

How many air conditioners can be brought with one and a half horses.

Since 200 kWa is the maximum limit of the total power of the transformer, the conversion of energy consumption into secondary effective power output, the most appropriate load below 160 kW is calculated by 20%.

The formula for calculating the rated current of the transformer is:

Input Rated Current: Capacity 3 Input Voltage Efficiency.

Output Rated Current: Capacity 3 Output Voltage.

So 200kva transformer:

The maximum rated current on the high-voltage side is 12A.

The maximum rated current on the low-voltage side is 288A.

PrincipleThe transformer is a device that uses the principle of electromagnetic induction to change the AC voltage, and the main components are the primary coil, the secondary coil and the core (core). In electrical equipment and wireless circuits, it is often used as voltage increase, impedance matching, safety isolation, etc.

The 200kva box-type transformer is able to withstand a load of 130-160kw

200kVA box-type (distribution) 400V output transformer, the maximum output of 290A (three-phase) current, the sum of the current of all loads can not exceed 290A, the load power can be borne depends on the power factor of the load, the power factor of the load is high (above), can withstand 180KW, the power factor of the load is low (below) can not exceed 160KW.

The power factor of an electric heating (resistive) appliance is close to 1, while the electric motor (inductive) is around it.

Three 330kw compressor units share a 1600kva transformer, if approved by the power supply bureau. 6 units need 2 sets of 1600kva transformers. Two sets of 1600kva each have a section of low-voltage bus, and a liaison is set between the two sections of low-voltage busbar for high-voltage metering.

1. Based on the user's average power Shisen factor, the apparent capacity required for 2000kw active equipment is: s=p cos =2000.

2. So you can choose a transformer with a total capacity of 2500 3150kva, and you can also choose a combination of: 1250kva+1250kva, 1000kva+1600kva, 800kva+1600kva, 630kva+2000kva, 500kva+2000kva and other five options.

To determine how big a transformer is needed, you need to know the voltage and current plexus of the electrical equipment. Assuming that the voltage of the electrical equipment is 220V, the power of 2000kW corresponds to the current of the stove is i=p v=2000000 220=. According to the formula of a transformer, the capacity of a transformer is directly proportional to the ratio of input and output currents, and the capacity is inversely proportional to the ratio of input voltage to output voltage.

Suppose the input voltage of the transformer is 220V and the output voltage is 10kV, then the capacity of the transformer is:

Capacity = Input Current Output Current * Input Voltage Output Voltage = 10kV 220V) =

Therefore, a transformer with a capacity of 200kVA is required. In the same way, for a 200kw electrical equipment, assuming that the voltage is 220V and the current is i=p v=200000 220=, according to the same formula, a transformer with a permeability capacity of 20kVA is required.

Summary. 1. Based on the average power factor of the user, the apparent capacity required by the 2000kw active equipment is: s=p cos =2000.

2. So you can choose a transformer with a total capacity of 2500 3150kva, and you can also choose a combination of: 1250kva+1250kva, 1000kva+1600kva, 800kva+1600kva, 630kva+2000kva, 500kva+2000kva and other five options.

How much capacity 10kv transformer is allocated for 2000kw electricity consumption?

1. Based on the user's average power factor, the apparent capacity required for the 2000kw active equipment is: s=p cos =2000. 2. So you can choose a transformer with a total capacity of 2500 3150kva, or you can choose a combination of:

1250kva+1250kva, 1000kva+1600kva, 800kva+1600kva, 630kva+2000kva, 500kva+2000kva and other five options.

The function of the core is to strengthen the magnetic coupling between the two coils. In order to reduce eddy currents and hysteresis losses in the iron, the core is made of painted silicon steel sheets. There is no electrical connection between the two coils, and the coils are wound by insulated copper wire (or aluminum wire). One coil connected to the AC power supply is called the primary coil (or the original coil), and the other coil is connected to the electrical appliance called the secondary coil (or secondary coil).

The actual transformer is very complex, and there are inevitably copper loss (coil resistance heating), iron loss (core heating), and magnetic flux leakage (magnetic induction wire closed by air), etc., so in order to simplify the discussion, only the ideal transformer will be introduced. The conditions for the establishment of an ideal transformer are: ignoring the leakage flux, ignoring the resistance of the primary and secondary coils, ignoring the loss of the core, and ignoring the no-load current (the current in the primary coil coil of the secondary coil is open).

For example, a power transformer may be operating at full load (the output of the subcoil is rated power), i.e. close to the ideal transformer condition.

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To configure a transformer, you must first find out what the power of its load is, and secondly, understand the nature of these loads (i.e., power factor), and then the working conditions of the load (e.g., the probability of simultaneous operation).

For example, the total power of the transformer load is 200kw, the average power factor is , and the working rate is at the same time.

80%, then the calculation formula:

Transformer power = (total load power power factor) x simultaneous working rate loading factor.

Loading factor: that is, the transformer cannot work at 100% load for a long time, and usually runs at 75% load rate

So. Transformer power = (200kw x 80% 75% = 237kva

Conclusion: The power level of the transformer can be selected from 250kva.

The power is 200kw, and a transformer greater than 200kVA is required.

It is not enough to determine how much transformer is needed based on the electrical power alone, but also to determine the KVA number of the transformer in combination with the "need factor", "simultaneous rate", etc.

Dear, hello, I am glad to answer for you: how big is the transformer for the load of 1900kw Answer: The load power factor of 1900 kw is The transformer of 2000 kva can be used.

If the load of 1900 kW is dominated by an electric motor, then the power factor is taken and 1900 kW kva is required, and a transformer with a nominal value of 2500 kVA can be used for the empty fiber. The choice of transformer does not depend on your installed capacity, but also on the size of the operating power (there are some standby facilities), but also on the maximum power and maximum power of the motor at the same time.