Chemistry topics for senior 2, chemistry for senior 2 topics

CL2 is required

Chlorine is required. Chlorine is required for CHCL3.

Chlorine is required for CCL4.

The chlorination reaction is to provide a halide atom and drag away a hydrogen atom to produce a hydrogen halide.

I've done this question no less than 5 times, so I'm still pretty sure!Select C!

When alkanes and chlorine gas are substituted, one molecule of chlorine gas is used for each hydrogen atom replaced.

Methane is a total of carbon elements, so the substitution products of the amount of the four same substances obtained are each different.

Where: CH3Cl requires chlorine:

CH2Cl2 requires chlorine:

Chlorine is required for CHCL3.

Chlorine is required for CCL4.

So the total amount of chlorine needed = ( = hehe, use me to make it.

Let the four quantities be x

cl2+ch4→ch3cl+hcl

cl2+ch3cl→ch2cl2+hcl

cl2 + ch2cl2→chcl3+hclcl2 + chcl3→ccl4+hcl

The solution is x=, so cl2 is required.

Summary. Related Extension] Hydrocarbon A is completely burned to obtain 8molCO2 and 4molH2O, then the molecular formula of A is C8H8, and the molecule contains a mole of carbon-carbon double bond, and the addition reaction occurs, and the reaction is to remove 2 molecules HBR2 from molecule BTry the product of the polymerization reaction of a, as long as it is judged that a contains carbon.

Carbon double bond then the polyaddition reaction is easier to write, A and the show element addition reaction, the generation of BB in the reaction with sodium hydroxide ethanol solution, then this is a elimination reaction, at this time to eliminate two molecules of rust hydrogen to produce E is containing carbon-carbon triple bond of phenylacetylene, because F is required to contain methyl group, so A and rust hydrogen addition reaction, the generated d bromine atom to be connected to the intermediate carbon atom 3Just determine the structure of A. Then these two reaction equations are easier to write 4

The design of the synthesis route is relatively comprehensive, including the addition reaction of Xining, the hydrolysis reaction of halogenated hydrocarbons, the catalytic oxidation of alcohols, the catalytic oxidation of aldehydes, and the elimination reaction of alcohols.

See you again, are you there, send me the title.

Question 4 Teacher.

I'll keep you waiting.

Don't forget to ask if you don't understand.

Related Extension] Hydrocarbon A is completely burned to obtain 8molCO2 and 4molH2O, then the molecular formula of A is C8H8, and the molecule contains a mole of carbon-carbon double bonds, and the addition reaction occurs, and the reaction is to eliminate 2 molecules HBR2 from the molecule BTry the product of the polymerization reaction of a, as long as it is judged that a contains carbon. Carbon double bond then the polyaddition reaction is easier to write, A and the show element addition reaction, the generation of BB in the reaction with sodium hydroxide ethanol solution, then this is a elimination reaction, at this time to eliminate two molecules of rust hydrogen to produce E is containing carbon-carbon triple bond of phenylacetylene, because F is required to contain methyl group, so A and rust hydrogen addition reaction, the generated d bromine atom to be connected to the intermediate carbon atom 3

Just determine the structure of A. Then these two reaction equations are easier to write 4The design of the synthesis route is more comprehensive, including the addition reaction in Xining, the hydrolysis reaction of halogenated hydrocarbons, the catalytic oxidation of alcohols, the catalytic oxidation of aldehydes, and the elimination reaction of alcohols.

1.Wrong, such as 3O2== Discharge ==2O3.

It is not oxidation that also carries the original reaction,,

In summary, all the transformations between allotropic forms have elemental participation in the reaction, and there are also elemental formations, all of which are non-redox reactions.

Gas, NaCl solution, KNO3 solids, CO2, molten KOH, graphite, sucrose, alcohol, sulfur, aluminum, BaSO4 solids.

Conductive --- NaCl solution, molten Koh, aluminum, graphite.

Electrolytes --- HCl, KNO3 solids, molten Koh, BaSO4 solids.

Non-electrolyte ---CO2..., sucrose, alcohol.

1. Not true. Counter-example 3O2=2O3, O is 0 price, no price change. Not a redox sizzle reaction.

Substances capable of conducting electricity: NaCl solution, molten Koh, graphite, aluminum.

Electrolytes --- KNO3 solids, molten KOH, BaSO4 solids.

Non-excitatory electrolytes are lead --- HCl gas, CO2, sucrose, alcohol.

1 is correct.

The ants that can conduct electricity are: NACL dissolves and bumps stupidly noisy nuclear fluid.

Koh graphite in molten form. Aluminium.

Electrolyte. KNO3 solids.

molten koh

Baso4 solids.

Non-electrolyte: HCl gas.

CO2 graphite.

Cane sugar. Alcohol. Sulfur. Aluminium.

No, for example, when oxygen is in the jungle, it will only generate ozone, and the valency of oxygen is 0, unchanged.

2. The substances that can conduct electricity are NaCl solution, molten KOH, graphite, and aluminum.

It belongs to electrolytes - HCl gas, -KNO3 solids, molten KOH, BaSO4 solids.

It is a non-electrolyte, CO2, sucrose, alcohol

Don't do it.

3O2==(Discharge bend)==2O3

Electrically conductive: NaCl solution, molten Koh, graphite, aluminum.

Electrolytes: HCl gas, KNO3 solids, molten KOH, BaSO4 solids.

Non-con electrolytes: Everything else.

At the beginning of the reaction, the concentration of carbon monoxide and water vapor is one mole per liter, k = 1 = [CO2] [H2] [H2o] [CO], according to the reaction [CO2] = [H2] = x, [H2O] = [Co] = (1-x) so x = then the conversion rate is 50%.

Fe + O2 = Ignition = Fe3O4

4fe+3o2==2

2fe+3cl2==2fecl3

Fe + 2Fe2 +) + H2 gas ———Fe + 2HCl = FeCl2 + H2Fe2O3 + 6H + = = 2Fe3 +) + 3H2O (2Fe3+) + Fe = = 3Fe2 +

2fe2+)+cl2==2fe3+

Fe3+)+3OH-)=Fe(OH)3 (precipitation)Fe(OH)3+3H+==FE3+)+3H2O(Fe2+)+2OH-)=Fe(OH)2 (precipitation)Fe(OH)2+2H+==FE2+)+2H2O4FE(OH)2+O2+2H2O==4Fe(OH)32Fe(OH)3=(Heating)=Fe2O3+3H2O

3Fe+2O2==(ignition) Fe3O4

4fe+3o2==2fe2o3

fe2o3+6hcl==fecl3+3h2o2fecl3+fe==3fecl2

2fecl2+cl2==2fecl3

FeCl3+3NaOH==Fe(OH)3 (precipitation)+3NaClFeCl2+2NaOH==Fe(OH)2 (complex)+2NaCl2Fe(OH)2+O2+H2O==2Fe(OH)32Fe(OH)3=(heating)=Fe2O3+3H2ofe(OH)3+3HCl==FeCl3+3H2ofe(OH)2+2HCl==FeCl2+2H2O

Laboratory ammonia can only be prepared by mixing ammonium chloride with calcium hydroxide, and the rest of the preparation methods are not laboratory methods.

Air pollutants mainly include sulfur dioxide, carbon monoxide and ammonia oxides, so carbon dioxide is not an air pollutant.

1.It can be obtained by heating concentrated ammonia or by coheating with ammonium chloride and calcium hydroxide.

2.Carbon dioxide.

1. Ammonium chloride and calcium hydroxide are mixed and heated to produce ammonia.

2. Ammonia, sulfur dioxide, and carbon monoxide can all pollute the air, and although carbon dioxide does not pollute the air, it has a greenhouse effect.