The Olympiad Spring Cup has started, and when I came back, the child said that there were a few ques

The most important thing in early childhood mathematics education is to stimulate children's interest in mathematics.

First of all, it is necessary to establish mathematical cognition for children, make mathematics life-like, game-oriented, child-like, and most importantly, interesting.

1. Mathematics enlightenment through games.

Learning mathematics through games is the most appropriate way to cultivate children's interest in mathematics, which is conducive to cultivating children's active exploration of mathematics.

Because the game can comprehensively exercise children's sense of rules, execution ability and strategic awareness.

There are rules for the game, and children must understand the rules, obey the rules, and at the same time achieve the goal; When the rules change, they have to change their strategies accordingly.

This process is not enough to memorize knowledge points, it actually exercises children's comprehensive ability to apply knowledge flexibly.

2. Enlightenment of mathematical thinking through picture books.

There is no child who doesn't like stories, this enlightenment method makes the originally boring mathematical content vivid and interesting, and while listening to the story, you can unconsciously absorb the knowledge.

The whole picture book is not boring at all! Listening to the mathematical knowledge like a book from the sky, you can find a basis in real life in picture books.

In the way of scenario substitution, children are first integrated into the story, and then the mathematical problems are discovered from the story, and then dissected and analyzed.

The most important thing in mathematics learning is to understand the thinking method behind knowledge, after all, knowledge is fixed, and the thinking method behind it is the most valuable.

3. Watch cartoons for thinking enlightenment.

Children's animation series, the little characters in the film love mathematics, use mathematics to solve obstacles in daily life, integrate the knowledge of patterns, numbers and shapes into animation, the content is full of interaction, and help children solve daily life problems with mathematical methods.

Children can master the understanding of numbers, mathematical skills, and develop children's thinking skills.

Use language that children can understand, interesting topics and games, from concrete to abstract, and really cultivate children's mathematical thinking! Let every child love math!

1. Method 1: Set up three (2) classes is 1 copy, three (1) classes are 1 part more than 4 3rd grade 2 copies more than 4, and 4th grade total 2 copies more than 21

Therefore four (1) classes are 1 part more than 8, four (2) classes are 1 part more than 13, and three (1) classes are 9 fewer than four (2) classes.

Method 2: Let three (1) classes give three (2) classes 2 people, and the third grade will be the same.

Let four (2) classes give four (1) classes 2 people, and then expel 1, and the fourth grade will be just as much.

At this time, there are 17-1=16 more students in the fourth grade than in the third grade.

16 more per class 2 = 8 people.

Class three (1) and class four (2) respectively asked those two people back, or 8 people short.

If the fourth (2nd) class calls back the expelled 1 person, there are 9 more people than the third (1) class.

2. Equal substitution.

162 = 2nd class + others.

143 = one class + other.

Therefore 162 + 143 = 1st class + 2nd class + 2 other.

And 87 = one class + two shifts.

Therefore, 2 Other = 162 + 143-87 = 218 Other = 218 2 = 109

Second shift = 162-109 = 53

There are 53 books in the second class.

3. What kind of diagram should I fill in?

0+1+2+……9=45, so the sum of the numbers filled in at the intersection is 55-45=10, and the rest depends on the figure ......

Hello, I'll only have two! The first course: if the Trinity class is X, the third and second classes are X-4, and the third grade is 2X-4.

If the 41 class is Y, then the 42nd class is Y+5, and the 4th grade is 2Y+5. And because there are 17 fewer students in the third grade than in the fourth grade, y-x=14 can be obtained from y+5+y-x-x+4=17, which is the difference between the three and four one, so the difference between the three and four is that 5 is added on both sides, which is (y+5)-x=14+5=19, so the difference is 19.

Two, I'm too late, I can only give the answer It's 53 copies. Thank you.

How is the first floor calculated? y+5+y-x-x+4=17 How to get y-x=14 It should be 4! Then calculate that the answer is 9.

Question 2 (143+162+87) 2=196, is the total, 196-143=53 is the second class.

Step 1 Fill 9 liters to a full capacity.

Step 2 Pour 9 liters into a 4 liter bucket, and the remaining 5 liters.

Step 3 Pour out 4 litres of water, pour 5 litres of 9 litres bucket into a 4-litre bucket, and leave 1 litre.

Step 4 Pour 4 litres of water again, pour 1 litre of 9 litre buckets into 4 litre buckets.

Step 5 Re-focus on the closure of Daxin and fill 9 liters of state inspection.

Step 6 Pour 9 litres into a 4 litre bucketThe remaining 6 litres (this is due to the 1 litre of water on the vertical side of the 4-litre barrel).

Calculation formula: 9 2-4 3=6

Many students in the third grade of primary school may have already started to study the Olympiad, but not everyone has the opportunity or ability to study in depth. Normally, students need to have a certain mathematical foundation and logical thinking ability to better understand and apply the knowledge of Olympiad mathematics.

Learn the basics of mathematics: First of all, you need to master the basic knowledge of primary mathematics, such as basic operations and concepts such as addition, subtraction, multiplication and division, decimals, as well as logical thinking and graphic cognitive skills.

It should be noted that learning Olympiad requires patience and perseverance, and it is necessary to choose the appropriate learning method and content according to your actual situation and ability. At the same time, we should not overemphasize the sensitivity of grades and competition, but should pay attention to cultivating students' mathematical thinking and innovation ability.

The sum of 32 people and 13 people double-counted 5 people who did both kinds of work, and the third grade class had a total of them.

32 + 13 - 5 = 40 people.

Answer: Those who only clean are: 32-5 = 27 (people) and those who only report on the blackboard are: 13-5 = 8 (people).

There are 5 people who clean and publish blackboard reports.

In total: 27 + 8 + 5 = 40 (people).

The six logarithms are:

Each number is matched 3 times with the other numbers, so the sum of the 4 numbers is (24 26 30 34 38 40) 3 64 The average of the original four numbers is.

The sum of ABCDs = (12 + 13 + 15 + 17 + 19 + 20) multiplied by 2 divided by 3 = 64 (the average of the six logarithms multiplied by two equals the sum of the four numbers multiplied by three); Mean = 64 divided by 4 = 16

Solution: According to the question formula: Because the number of girls is half that of boys, the number of boys is twice as large as that of girls.

41 2 + 35) (2 + 1) = 117 3 = 39 (kg).

A: The average weight of all students is 39 kg.

The division of two numbers by quotient 3 is more than 4

then the dividend is equal to 3 divisors more than 4, that is:

The sum of the 3 divisors, 4, and the divisor is 43

Obviously divisor = (43 - 4 - 3 - 4) (3 + 1) = 8

Dividend = 8 3 + 4 = 28

The sum of the divisor, divisor, quotient and remainder is 43

Dividend + divisor = 43-3-4 = 36

The dividend divisor has a remainder after division, so 36-4=32 is a 4 times divisor, the divisor = 8, and the dividend is 3*8+4=28

Known: Dividend -4 = Divisor x 3 = > Dividend = Divisor x 3 + 4 Known: Dividend + Divisor +4 + 3 = 43

divisor x3 + 4) + divisor + 4 + 3 = 43

The divisor x4+11=43

The divisor x4 = 32

Divisor = 8 Dividend = 8x3 + 4 = 28

[Dividend=28, divisor=8].

The dividend should be (3 divisor + 4), the quotient and the remainder are combined to be 7, 43-7 = 36, 36 = dividend + divisor = 4 divisor + 4

32 = 4 divisor, divisor = 8, dividend 43-4-3-8 = 28

From the known conditions, the sum of the divisor and the dividend is 36, so that the divisor should be less than 9, so the dividend and divisor are 28 and 8, respectively.

Let the dividend be x and the divisor y to solve the system of equations.

x= y×3+4

x+y+4=43

The solution gives x=121 4, y=105 12 or the dividend is 121 4 (, and the divisor is 105 12 (. I read the above questions they did wrong.

If the dividend and divisor are set to a and b respectively, then a = 3b + 4 and a + b + 3 + 4 = 43

Solve a, b is divided by the dividend a=28

The divisor b = 8

The divisor is a and the dividend is b a=3*b+4 a+b+3+4=43 by calculating a=28 b=8

Upstairs is correct, I won't copy it.

What kind of algorithm is this? It seems that primary school doesn't learn, even the teachers in college don't talk about algorithms, is it helpful for children?