Knowing that a is a part of 8, try to find the value of a to the fourth power minus a to the fourth

a+1/a=8

After squaring. a²+1/a²+2=64

a²+1/a²=62

a²+1/a²-2=60

i.e. (a-1 a) = 60

a-1/a=±2√15

A to the fourth power minus a fourth to the power.

a²+1/a²)(a+1/a)(a-1/a)

a+1/a=8

Square on both sides, get:

a^2+2+1/a^2=64

a^2+1/a^2=62

Then squared, get:

a^4+1/a^4+2=3844

a^4+1/a^4-2=3840

a^2-1/a^2)^2=3840

a^2-1/a^2=±16√15

a^4-1/a^4

a^2-1/a^2)(a^2+1/a^2)

a-1/a=3

Square on both sides: a +1 a -2 = 9

a²+1/a²=11

Flat sellers on both sides:

a^4+1/a^4+2=121

a^4+1/a^4=119,7,a-1/a=3a-1/a)²=9

a²+1/a²-2=9

a²+1/a²=11

a²+1/a²)²121

A to the 4th power + 1 to the 4th power of a + 2 = 121

1 of the 4th power of A + 4 times of the 4th loss of A = 119,0,

a+1 returns to a=2

The square gives a 2+1 a 2+2=4, so a 2+1 a 2=2 and then squares to get a 4+1 a 4+2=4

So silver hunger a 4+1 a 4=2

It is known that a+a/a = 2

Square on both sides. (a+1/a)^2=4

a^2+1/a^2+2=4

So a 2 + 1 a 2 = 2

2)a^2+1/a^2=2

Square on both sides. （a^2+1/a^2)^2=4

a^4+1/a^4+2=4

So a 4+1 a 4=2

This is the solution for this type.

Another way to solve this problem is to solve a.

It is known that a + a part = 2 and both sides multiply a

a^2+1=2a

a^2-2a+1=0

a-1)^2=0

So a = 1, so a square + a square one = 2

A to the fourth power + a to the fourth power = 2

The answer is 76, and the detailed process is written on the paper.

a+a/a = 4

Both sides are squared and get.

a^2+2+1/(a^2)=16;a^2+1/(a^2)=14;Again both sides squared, get.

a^4+1/(a^4)=14^2-2=194

a^2+1/a^2=(a+1/a)^2-2=14

A to the power of 4 + a to the power of 4 = (a 2 + 1 a 2) 2-2 = 14 2-2 = 194

a+1/a=4

The square of both sides yields a 2+2+1 a 2=16

a^2+1/a^2=14

Then square a 4 + 2 + 1 a 4 = 196

a^4+1/a^4=194

You can directly go both sides to the fourth power at the same time.