A math problem with a slightly more complex equation for fifth grade

Set x tons of scalpers, 10x+ tons of elephants, and 25 (10x+ tons) of blue whales.

10x+10x=

x = scalper = ton.

Blue whale = ton.

1000 kg = 1 ton, 400 kg = ton.

Cattle weight: (t) ;

Blue whale weight: 50 25-10=1250-10=1240 (tons). Scalpers and blue whales can't be so heavy.

400 kg = tons.

Solution: Suppose the weight of the scalper is x tons.

10x+10x=

x = solution: Suppose the weight of the blue whale is y tons.

y=25x50-10

y=1240

A: The weight of the yellow whale is tons, and the weight of the blue whale is 1240 tons.

Cattle: Let the weight of the cattle be x,400 kg = tons, and the weight of the cattle is 10x+,x=

Blue whale: 25x50-10=1240

50 tons = 50,000 kg; The weight of the cattle = (50000-400) 10 = 4960 kg.

The weight of the blue whale = 50 * 25-10 = 1240 tons.

3x+6=18

3x=18-6

3x=12x=4

Let's take this as an example. Noisy.

Just like this number, plus + plus = sum.

Then sum - addition = another addition.

The other addition is with x, and then as mentioned above.

3x=12 divided by 3 on both sides at the same time, it can also be solved as a multiplier x multiplier = product (3 times x), then the product multiplier = another multiplier.

According to the law, you should be able to know.,I wish you a good result.,If you can't do it, you can ask me again.。

The difference subtracted from the subtracted number is equal to the subtraction x=360

The second grade donated x yuan.

3x-x=860

2x=860

x=430 6th grade: 430 3=1290 yuan.

Donate x yuan for the second grade.

860+x=3x

x-3x=-860

2x=-860

x=4303x=1290

430 yuan for the second grade and 1290 yuan for the sixth grade.

Untie; The second grade donated x yuan.

From the meaning of the title; x+860=3x

2x=-860

x=430 yuan.

Therefore, the donation amount for the sixth grade is 3x = 1290 yuan.

Answer; The second grade donated 430 yuan, and the sixth grade donated 1,290 yuan.

The second grade donated x yuan.

3x-x=860

2x=860

x=430 6th grade: 430 3=1290 yuan.

Good luck!

Solution: The second grade will donate x yuan, and the sixth grade will donate 3x yuan.

3x-860=x

3x-x=860

2x=860

x=860÷2

x=4303x=430 3=1290 (yuan).

A: The second grade donated 430 yuan, and the sixth grade donated 1,290 yuan.

Solution: The second grade will donate x yuan, and the sixth grade will donate 3x yuan.

3x-x=860

2x=860

x=860÷2

x=430 6th grade: 430 3=1290 yuan.

A: The second grade donated 430 yuan, and the sixth grade donated 1,290 yuan.

Solution: If the second grade donates x yuan, then the sixth grade donates 3x yuan 3x-x=860

2x=860

x=860÷2

x=430 6th grade: 430 3=1220 (yuan).

A: The second grade donated 430 yuan and the sixth grade donated 1,220 yuan.

Solution: Merge homogeneous terms 2x+1=2

Shift 2x=2-1=1

x=

Let the ball in the box be x

The original first box x+2

The original second box X-2

The original third box x 2

The original fourth box x*2

It adds up to (x+2)+(x-2)+(x 2)+(x*2)=45x=10

The original first box is 10 + 2 = 12

The original second box 10-2 = 8

The original third box 10 2 = 5

The original fourth box is 10*2=20

Think of the third box as a standard quantity, 45 (2+2+1+4)=5 for the first box: 5*2+2=12

The second box: 5*2-2=8

The third box: 5

The fourth box: 5*4=20

Solution: There are a total of x boxes of oranges in the fruit store.

12x+4=400

12x=400-4

12x=396

x = 396 divided by 12

x=33A: The fruit store has a total of 33 boxes of oranges.

Why is this a 6-year-old solution to the equation? . . Is it a challenge?

Solution: There are a total of x boxes of oranges in the fruit store.

12x+4=400

12x=396

x=33A: The fruit store has a total of 33 boxes of oranges.