Who knows there s the latest 5th grade word 5

1.Because there are as many caring people who adopt 2 or 3 orphans, then if there are x caring people who adopt 3 orphans, then the orphans adopted by the caring people who adopt 2 or 3 orphans are (2+3)*x=5x, and 5x should be less than 27, so x is 5 at most; While 27-5x should be less than 16-2x, there is an x minimum of 4. So there is:

1) There are 5 caring people who adopt 2 and 3 orphans, 2 who adopt 1 orphan, and 4 who do not adopt orphans;

2) There are 4 caring people who adopt 2 and 3 orphans, 7 people who adopt 1 orphan, and 1 person who does not adopt orphans.

2.If the car is still x meters away from the sound wall when the echo is heard, it is 340*, x = 700 meters. Be careful to convert the car's speed to meters and seconds.

3.Let there be x pieces, and white pieces * 5 = black pieces * 3, white pieces = 3 5 * black pieces, then white pieces = 3 8 * x, black pieces = 5 8 * x. Let the number of times be n, then there are: 1) 7*n+13=5 8*x

2）5*n+3=3/8*x

This gives us x=88

4.There are a total of 21 buckets, divided equally among 3 people, each person should be divided into 7 buckets, and there are honey 7+7*, each person should be divided into honey buckets, so it should be the first person to divide 3 buckets of full barrels of honey + 1 barrel and a half barrel of honey + 3 empty buckets; The second person should divide 2 full barrels of honey + 3 and a half barrels of honey + 2 empty barrels; The third person should divide 2 full barrels of honey + 3 half barrels of honey + 2 empty barrels.

1。5 people 27 divided by the sum of 3+2 = 5 surplus 2 then only 2 people are adopted by the remaining 6 people.

The speed on the first day (60 + 6 * 50 (8-5) = 30 km/h.

On the first day, 30 * 8 = 240 km.

The next day, we traveled (30 + 6) * 5 = 180 km.

Let the original speed be x kilometers per hour.

8x-60=5(x+6)

8x-60=5x+30

3x=90x=30kmh.

Day 1 = 8 * 30 = 240 km.

Day 2 = 5 * (30 + 6) = 180 km.

It took more than 5 hours to travel 30 kilometers.

The original speed is 3 hours, you can go 60+30, and the speed on the first day is 30 kilometers h

Day 1: 240

Day 2: 180

If the speed of the first day is x km, then the speed of the second day is (x+6) km, 5 (x+6) + 60 = 8x, and the solution is x = 30, then the first day of sailing is 8x = 240 km, and the second day is 240-60 = 180 km.

Let the speed on the first day be x, then the distance traveled on the first day is 8x, and the distance traveled on the second day is 5*(x+6).

If you want to reduce the two-day journey to 8x-5*(x+6)=60, the solution is x=30, so the distance traveled on the first day is 8*30=240 kilometers.

The second day covered a distance of 180 km.

Solution: Set x kilometers per hour on the first day.

8x-5x(x-6)=60

x = 30 (km-h).

8x30=240 (km) 36x5=180 (km) Answer: 240 km on the first day and 180 km on the second day.

Set the first day of sailing at a speed of x km h

then 8x km was sailed on the first day

The next day sailed (x+6)*5 km

Therefore, 8x=(x+6)*5+60

x=30 km h

30*8=240km on the first day

240-60 = 180km the next day

In the future, it will be convenient to analyze the questions like me.

Suppose the speed on the first day is x kilometers per hour.

Day 1: l=

Day 2: l'=(x+6).5

l=l'+60

Find x, find l, and l'