Knowing the 3rd degree of F x AX bx 8, and f 4 10, then f 4 ?

f(-4)=a*(-4)^3+b*(-4)-8=-(4^3*a+4b)-8=10

4^3*a+4b=-18

f(4)=4 3*a+4b-8=-18-8=-26 hope it helps you.

If you have any questions, you can follow up.

Thank you.

Let g(x)=ax +bx

f(-4)=10

g(-4)=18

g(-x)=-ax -bx=-(ax +bx)=-g(x), so g(x) is an odd function.

So g(-4)=-g(4)=18

g(4)=-18

f(4)=-18-8=-26

Student: The "=" in your question should be "+" or "-"!

First of all, if your "=" is "+", you know that f(x)=x 5+ax 3+bx+8, so that g(x)=x 5+ax 3+bx

Since f(-2)=10, g(-2)=f(-2)-8=10-8=2 is obviously an odd function of g(x), so g(2)=-2

So f(2)=g(2)+8=-2+8=6

If your "=" is "-", you know f(x)=x 5+ax 3+bx-8, so g(x)=x 5+ax 3+bx

Since f(-2)=10, g(-2)=f(-2)+8=10+8=18 is obviously an odd function, so g(2)=-18 so f(2)=g(2)+8=-18-8=26

f(x)=x^5+ax^3+bx+8

Let g(x)=x 5+ax 3+bx

f(x)=g(x)+8

f(-5)=10, then g(-5)=2

It also collapsed to imitate the beam g(5)=-g(-5)=-2

So the bridge f(5) = 6

Note f(-x)=-x 5-ax 3-bx=-(x 5+ax 3+bx)-8

Because f(x)=x 5+ax 3+bx-8, f(x)+8=x 5+ax 3+bx

Then f(-x)=-f(x)+8]-8=-f(x)-16, i.e. f(2)=-f(-2)-16=-26

Because f(x)=a +bx-b, f(-4)= a -4b-b=a -5b, and because f(-4)=10, a -5b=10, i.e. a = 5b+10

Which line starts with f(4) = a +4b-b=5b+10+3b=8b+10

f(2)=-10 add 4 to both sides of the original equation, and write g(x)=f(x)+4=ax to the third power + bx, then g(x) is an odd function, and you should understand the solution later. This type of problem does this by moving the constant term to the other side of the equal sign and then doing it according to the parity of the function.

Solution: x=-2 substitution of the function equation:

2) 4+a(-2) 3+b(-2)-8=10 finishing.

8a+2b=-2

x=2 substituting the function equation:

2^4+a(2^3)+2b-8

8a+2b+8

6. It is a mistake to say that a function is an even function.

f(-2)=f(2)=8a+2b+2

f(2)=10

You'll find that this function is an even function, so the answer is all the same!

Substitute -2 into the original formula, find the relation about it, and then substitute 2 into the original expression, sort it out, and find the answer as six.

Let g(x)=x 5+ax 3+bx

Then f(x)=g(x)+8, g(x) is easy to obtain a singular function of percolation, so the cluster (x)=g(x)+8, that is, f(-2)=g(-2)+8=10

So g(-2)=2, then g(2)=-2 f(2)=g(2)+8=-2+8=6 should be the concedent.