F2 has a strong oxidizing capacity????

Fluorine has the highest electronegativity, ionization energy is electron volts, is the most reactive element in non-metals, has a strong oxidizing ability, and can react with most hydrogen-containing compounds such as water, ammonia and all chemicals in liquid, solid, or gaseous state. The reaction with water is complex, with mainly hydrogen fluoride and oxygen, as well as smaller amounts of hydrogen peroxide, oxygen difluoride and ozone produced, and other non-metallic elements can also be displaced in the compound. It can react violently with all non-metallic and metallic elements to form fluoride and combust.

It is extremely corrosive and toxic, and special care should be taken when operating, and it should never be allowed to come into contact with its liquids or vapors with ** and eyes.

Yes, it is the most oxidizing of all elements.

As the most non-metallic element, it has a strong oxidizing ability.

Yes, the most oxidizing element.

It is a redox reaction.

The oxidizing agent is F2 and the reducing agent is H2O

Fluorine gas is the most oxidizing element, and it is very easy to replace O2 from H2O

2h2o+2f2==4hf+o2。

Here's a little bit of college knowledge.

In fact, the reaction between F2 and H2O is divided into many simplest primitives, and this kind of reaction that can be done in one step without redundant reaction steps is called primitive reaction, and the reaction principle of F2 and H2O is as follows

f2== light energy or heat = =2f (fluorine atom).

2F+H2O==2HF+O (oxygen atom) (which contains a two-step reaction) 2O=O2 (primitive reaction).

O2 + o = O3 (primitive reaction).

O+2F = of2 (two-step reaction).

O+H2O=H2O2 (primitive reaction).

In fact, these substances can be more or less measured in experiments, because O2 is relatively the most stable among these products, and the tendency to form O2 is generally the greatest.

So there is also 2F2+2NaOH (2%) ===of2+2NaF+H2O

In the seventh main group, f2>cl2>br2>i2

The above is elemental, but the oxidation of the compound is stronger.

Lewis acid refers to a substance that can accept electrons or provide protons, and if it is strong, it is no more powerful than a cup full of protons, of course, it does not exist.

And oxidation refers to the ability to compete for electrons, which is active, and can only be found in the laboratory, which exists for a short time, and has become other substances in an instant, indicating that his ability to compete for electrons is extremely strong, and I have heard of it before, it is bismuth acid.

In addition, aqua regia is formulated with a ratio of nitric acid and hydrochloric acid massage to 3:1, and the reverse is 3, and it can dissolve gold because gold can form a complex in aqua regia, dissolve in water, and then ionize in a positive direction in equilibrium. Substances that are absolutely insoluble in water are not available in the wide bar.

This is what I was influenced by my teacher, who said that if you take a cup of acid, there must be negative ions, and you think of it.

The standard standard electrode potential is calculated by comparing the hydrogen ion activity of 1 (approximate concentration) with other potentials, and the potential of hydrogen is 0. The highest electronegativity is fluorine.

Hydrofluoric acid is a weak acid, but it can dissolve glass, indicating that acidity and oxidation (or solubility) are not necessarily related, magic acid can dissolve wax in the candle high alkanes, but it is not the alkane in the c, h side into the best valence carbon dioxide and water, indicating that the oxidation is not very high, just from the fact that it can dissolve candles and other advanced alkanes can not show that it is acidic... I personally think, hehe).

Hydrofluoric acid is a weak acid, because the electronegativity of fluorine is very high, hydrogen bonds are formed in the solution, and the hydrofluoric acid molecule attracts a long snake array from beginning to end, so it is a weak acid. The radius of fluoride ions is very small, second to hydrogen ions, which can penetrate many substances, and can also penetrate if it comes into contact with it, so it is very itchy and turns red.

The second floor but it hurts ......O3 is not as oxidizing as F2, and F2 is the most oxidizing element:

O3 + 2H+ +2E = O2 + H2O, E=F2 + 2H+ +2E = 2Hf, E=3 Floor also hurts ......Hof can only exist at low temperatures (in ice, decomposes at 0°C), and F2 reacting with ice needs to be diluted with N2.

Back to the owner, the reaction between F2 and H2O is actually very complicated, and at room temperature, not only O2 will be released, but also Of2, H2O2, O3 and other substances will be generated

f2 + h2o = 2hf + o

2o = o2

3o = o3

o + h2o = h2o2

o + f2 = of2

The reaction of F2 and the base is also related to the concentration of the base:

2F2 + 2OH- (dilute, 2% of the skin) 2F- +OF2 + H2O2F2 + 4OH- (concentrated) =4F- +O2 + 2H2O In addition, F2 has strong oxidation, and the products of the reaction with H2O are also strong oxidizing substances, so it will break the molecular structure of the litmus and make the litmus fade ......

The reaction between F2 and H2O produces HF and O2: 2F2 + 2H2O ==4HF + O2, and is OF2.

F2 reacts with NaOH solution to form OF2

If O3 will not be generated, only O2 will be generated

The passage of F2 or the purple litmus test solution will fade because the strong tung oxide caracity of F2 causes the litmus to be bleached.

2f2 + 2h2o ==4hf + o2

O3 is more oxidizing than F2, so it does not produce O3

F2 is a strong oxidizing agent, which directly bleaches the stone and carries the Min Yan.

2F2+2H2O=4HF+O2 This reaction is the only one in secondary school chemistry where H2O is only used as a crude reducing agent.

That's all. F2 is a strong oxidizing agent that directly bleaches litmus Hf is a weak acid, but you don't know your concentration, and you can't calculate its pH.

But you can think about it.

Carbon clear acid is a weak acid, acidic, and purple litmus test solution will turn purple litmus red.

The discoloration range of litmus is pH=

Generally speaking, HF>H2CO3>HCl>C5H5OH, so F2 can be passed into the purple litmus solution to fade the color of the purple litmus solution.