High School Chemistry Compulsory 2 Mid term Test Test 1 and 2 Chapters .

Updated on educate 2024-04-18
9 answers
  1. Anonymous users2024-02-07

    This ......The one on the first floor doesn't seem to be a compulsory two, but a lot of it is in the reaction principle elective book, and the compulsory ...... doesn't have to be so difficult

    This kind of thing, looking for it on the Internet, there is always one, spend more thought.

    Generally, what you look for yourself is the most targeted! (*

  2. Anonymous users2024-02-06

    If you take the mid-term test, you will still take the content of the elective four miles. It's not just a must???

    Find the question of "High School Chemistry Compulsory Phase II Test Questions (Self-made Intensive Questions)" on the Internet, and I feel that test is very good. . .

  3. Anonymous users2024-02-05

    Chapter tests help the process of final total revision run smoothly. The following is the test and answers of Chapter 4 of the Chemistry Compulsory 2 Compulsory Course brought by me, I hope it will be helpful to you.

    Senior 1 Chemistry Compulsory 2 Chapter 4 TestSenior 1 Chemistry Compulsory 2 Chapter 4 Test AnswersThe above is the test and answer of Chapter 4 of Senior 1 Chemistry Compulsory 2 that I shared, welcome to read it.

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  4. Anonymous users2024-02-04

    If you don't have a book, you don't know anything else, so let's do this one.

    Let the mass of calcium carbonate required for the reaction be x, and the mass of calcium chloride shall be y

    Find the carbon dioxide quality first:

    The amount of substances of CO2 gas = =

    The relative molecular mass of CO2 = 44

    So the mass of CO2 gas = 44* = 22g

    Chemical equation: CaCO3+2HC---CaCl2+CO2+H2O

    x y 22

    100/x=111/y=44/22

    x=50g,y=

    90% of calcium carbonate requirements are 50 90% =

    The amount of calcium chloride substance is n=m m=

  5. Anonymous users2024-02-03

    3.It is known that x,y is the first 20 element, and the outermost shell of x,y has n and m-5 electrons, and the subouter shell has n+2 and m electrons, then x,y is (14) and (15).

    Because the subouter shell can only be 8 electrons, there are n+2=8 and m=8

    So n=6, m-5=3

    So x,y are s,,al, respectively

    4.Aluminum, silicon, carbon The element with the largest atomic radius is ( aluminum ) Write the chemical formula of the hydrate corresponding to the three elements of the most ** oxide (in order of increasing acidity) (aluminum hydroxide, silicic acid, carbonic acid).

    The greater the number of atomic layers, the smaller the number of nuclear charges, the larger the radius, so the radius of the aluminum atom is the largest.

    The stronger the non-metallic nature, the more acidic the hydrate corresponding to the most ** oxide of the element.

    5.Knowing that the atomic number of a is x, and b2- has the same electron shell structure as a3+, then the atomic number of element b is (18).

    The number of electrons b2- and a3+ is x-3

    Because b2- is formed by b getting 2 electrons, the number of electrons in b is x-3-2=x-5

  6. Anonymous users2024-02-02

    Sodium, fluorine, the sixth main group of the third cycle,

  7. Anonymous users2024-02-01

    SO2 magenta solution (SO2+H2O==H2SO3, so there will be sulfite ions, magenta solution fades when SO2 is encountered).

    C2H4+BR2==C2H4BR2(1,2-dibromoethane) to the addition of listed ethylene. If ethylene and bromine have a substitution reaction, the product is HBR, and the solution is acidic, while the pH test paper will turn red when it encounters HBR, thus being acidic).

    It should be detailed enough!

  8. Anonymous users2024-01-31

    SO2 magenta solution.

    If ethylene and bromine have a substitution reaction, the product is HBR, and the solution is acidic.

  9. Anonymous users2024-01-30

    (1) Student B speculated that ethylene must contain a gas (SO2), which can be used (litmus reagent) to verify.

    2) The aqueous solution of SO2 is very acidic, which affects the test results.

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