Can anyone help me with this chemistry problem?

1) The most metallic is potassium (K) of group ia in the fourth period, and the most active non-metal is fluorine (f) of group VIIA in group 2.

2) The most acidic oxide hydrate is perchloric acid (HCO4), which is not visible later, and it is guessed that it is the most basic compound, which is potassium hydroxide (KOH), and the electronic formula is k+[:o:h]- (roughly so, the outer shell of the oxygen atom has 8 electrons, and it shares two electrons with hydrogen).

3) It is nitrogen, and the elemental substance formed is nitrogen, and the structural formula is n n.

4) Hydride: H·+:F:·=H:F:::and Compounds:Na·+:Cl:·=Na+[:Cl::].

1) CaCO3+2H+=Ca2++H2O+CO2, and white gelatinous precipitate is generated in device C.

2) The function of device B is to remove the volatile nitric acid in A.

3) Nitric acid, carbonic acid, silicic acid, non-metallic N>C>Si.

26 questions? First of all, you need to lock the elements represented by 1 and 10. They are:

n f na mg al si cl ar k br。

1) If you have the strongest metallicness, look at the lower left corner of the periodic table, so it's k. The most reactive non-metals are in the upper right corner of the VIIA group, f.

2) The most acidic is HCO4. The most alkaline is koh.

3）；2na+cl2=2nacl。

Let's just draw it electronically.

I can't see it clearly, can I find another one?

I can't see clearly, how can you let me help you??

In order to avoid trouble, I use Chinese characters, forgive me! ）

Join. Silver nitrate solution.

Precipitation is.

Sodium chloride equation you should know it! ）

In this way, sodium chloride is identified!

3) Add barium chloride.

Precipitation is.

Sodium sulfate does not react to sodium nitrate! ok

Hope it helps!

False False, must be similar in structure.

False, naphthenes and monoolefins are isomeric to each other, and the hydrocarbon ratio may be the same, but not homologues Falsely, the two organic substances that are isomers of each other are different substances, and the chemical properties will not be the same, but will only be very similar.

Pick A, all wrong.

The mass of 50mol ki is 1 20*332=2ki+cl2=2kcl+i2

x y x= y=

Since the front and rear mass is equal, there is no problem of overload. So the amount of the substance of ki in the original solution is c(ki)=

n(cl2)=

The volume required for the complete reaction is exactly the introduction of cl2 (chlorine) under standard conditions.

It's a simple question. The last remaining substance is KCl, then the amount of matter is according to the conservation of the material, and the original Ki also has so the molar concentration is.

The rest of the question should not be answered, good luck

I'm just going to tell you how to do it. Chlorine completely oxidizes iodine to iodine elemental matter and potassium chloride. Burning, iodine element volatilization.

So it is the mass of potassium chloride that pushes out the amount of potassium substance. 1 to understand the amount of potassium to push chlorine. In the conversion of a volume at a time.

What do you mean by KL? Did you make a mistake in the title?

1. A2, the density of each substance is different, and the mass fraction and volume fraction are not the same.

The total mass of the product obtained by burning 12 grams of magnesium in air is 20 grams; Oxygen.

Since HCN is a weak acid, ionization requires energy absorption, h==

Expressed as an endothermic reaction.