Help with these chemistry questions, and help with a chemistry problem

From condition 1, it is known that combustion generates MoH2O, MoCO2

By condition 2, the molecular weight of this hydrocarbon is 28

So, the molecular formula of this hydrocarbon is C2H4, ethylene.

1) H2C CH2 ethylene.

2) 16g3)-(CH2CH2)N-polyethylene.

Question 2 (1) 3 types of mol

2) 3 kinds.

Question 1] The meaning of the title is the mass of water, and the weight gain of lime water is the mass of carbon dioxide. i.e. water, carbon dioxide. Then the ratio of hydrocarbon to hydrogen atom is 1:2, and the relative molecular mass is 28, which is C2H4.

1) Ethylene. 2) can be added to bromine. The mass is 16g

3) There are six hydrogen substituted then bromine vapor.

4) Polyethylene, the structural formula is to open C=C.

Question 2] 1) 3 types.

C8H17Cl combustion, 2) 3 kinds. I'm so tired.

Let R be reflected with HCl, then R --- H2

10g1g, so the arithmetic mean of molar mass is 20g mol

fe--h2

zn===h2

2\3al---h2

mg---h2

Therefore, only the relative hydrogen content of Al is less than 20, and Gu must have AL

Choose C, which is actually a redox trim problem. First of all, we know that 2mol of metal loses electrons and 1mol of nitric acid gives an equal number of electrons. When the metal is oxidized.

At 1, 2, and 3 valence, they correspond to the loss of electrons of 2, 4, and 6mol, respectively, and when the electrons obtained by 1mol of nitric acid are n2o, they are 4mol of electrons and the metal is conserved when they are bivalent.

The absorption tower is CO2 + K2CO3 + H2O = 2kHzCO3

The reaction in the decomposition cell is 2khCO3 = CO2 + K2CO3 + H2O

This is equivalent to separating (absorbing) CO2 from the air and then releasing it, thus enriching the carbon dioxide.

Absorption pool CO2 + H2O = H2CO3, H2CO3 heating will hydrolyze, H2CO3 - (heating) - CO2 + H2O

The one upstairs is very tough, admire and admire, but I think the result is a little tangled.