Seeking chemistry problems is a master, and solving chemistry problems is urgent

1) Since one mole of B contains only one mole of nitrogen atom, the structural formula of hydrochloride B of amino acid A can be expressed as, Hooc-R-NH2·HCl.

The precipitate is silver chloride, and silver chloride is moles, then b contains molar chloride ions.

So b is molar and hooc-r-nh2 is mole, so the mass of hcl in b is and the mass of hooc-r-nh2 in b is.

So MA2)10GA is molar and molar sodium hydroxide is exactly neutralized, then each a has 2 carboxyl groups.

The amount of hooc-ch2-ch2-chnh2-cooh is exactly 147-v-

The relative quantity obtained from agcl is, so the relative quantity of a is so the molar mass is 147g mol

Because it is amino acid A, H is directly attached to C, so Hooc-CH(R)-NH210GA consumes by 10 147= So there are two carboxyl groups, there are 6 kinds of H, and now there are 4 kinds, and only the hydrogen on the amino group is 2, and the others are 1, so there are 2 kinds of H in the molecule, 2 of each, and the relative amount of formula is 147, two carboxyl groups 90, amino groups 16, and hypomethyl groups 13, so the remaining only 147-90-16-13 ==28 There are 2 kinds of 4 H, So only ch2ch2 can.

So it's ch2ch2cooh

hooc-ch-nh2

1. The first part, look at the above, don't fight.

2 knows that there are two carboxyl groups in the NMR hydrogen spectrum with 6 peaks, and its area ratio is 1:2:2:

2:1:1 Knowing that there are six different types of hydrogen in this substance, I judged that the hydrogen on the carbon based on its molecular weight of 147 is one or two, because the carboxyl group has one hydrogen, and I think there are other types, and I'm thinking that it's hard to draw that amino group attached to the carbon to the left of the right carboxyl group.

-o=c-ch2-ch2-ch-c=o---oh---nh2--oh

A certain year's finals test questions. Don't ask this kind of question here, go to the Chemical Island Forum to ask, there are some very good seniors.

High School Winter Camp Level Contest Questions.

It's a pity that I've forgotten ...

NaOH relative molecular mass = 40

H2O relative molecular mass = 18

According to the conservation of mass before and after the reaction, there is: a + 40 = b + 18 so b - a = 22 choose c

naoh 40 h2o 18

The relative molecular weight difference of b a is 44-18 = 22

Choosing a CA is all about physical change.

b All are chemical changes.

d are all chemical changes (denaturation of proteins).

c There is no chemical reaction in the volatilization of gasoline, which is a physical change; Gasoline is burned to produce carbon dioxide and water, and new substances are formed, which is a chemical change.

One part sodium and one part water react to form part hydrogen, so the release of hydrogen is one gram, one part of mg, and two parts of hydrochloric acid react to form one part of hydrogen, so the release of hydrogen is 2 grams a=23-1+m b=24-2+ma=b

It is known that both water and dilute hydrochloric acid are sufficient, so Na and Mg completely react with 1mol Na and sufficient amount of water to generate m(H2)=1mol mg and sufficient dilute hydrochloric acid to produce 1mol H2 m(H2)=1*2=2g

So the mass of the solution at this time is 23+m-1=22+m 24+m-2=22+m

Since dilute hydrochloric acid is volatile, the mass should be reduced, so a>b

1. 2000*75%*70%=1050t2.The solution requires a mass of x of hematite

3co+fe2o3=3co2+2fe

x*80% 1600*(1-2%)

160/112=x*80%/1600*(1-2%) x=2800t3.The quality of hematite required for unraveling is y

3co+fe2o3=3co2+2fe

y*85% 200*(1-3%)

160/112=y*85%/200*(1-3%) y=

Give 10 points for so many questions, you can pick enough.

1. Let the mass of CO2 be X

CaCO3 == High Temperature == CAO+CO2100 44

1000* x100/44 = 1000*

x = 374 kg

That is, the mass that produces CO2 is 374 t

2. The mass fraction of Zn = 65 455 *100% = C12 H22 O14 The mass of Zn is mg = mg, that is, the mass of zinc gluconate in the oral solution is mg

1.Solution: Suppose carbon dioxide is generated xg

caco3==cao+co2↑

1000x15% x

100 441000x15% :100=x:44

x = 66g A: 66g of carbon dioxide is emitted into the atmosphere.

cabcbcc

If you're satisfied, remember!

Heating, unchanged, unchanged, unchanged, unchanged, increasing.

Cooling, getting smaller, not changing, getting smaller, getting smaller, lowering, precipitating.

Add water, unchanged, become larger, become larger, become smaller, unchanged, evaporate, become smaller, become smaller, become smaller, unchanged, unchanged, precipitate.

Add. Unchanged, unchanged, unchanged, unchanged, unchanged,