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1) 5 looms can weave 192 meters of cloth in 3 hours, in this way, how many hours can 9 looms weave rice?
2) There are two ropes with a total length of meters, and it is known that the length of the first is 4 times the length of the second minnow. How many meters are each of the two ropes?
Establish. The length of the second strip is x x + 4x =
5x=x=2 meters long, 26 meters long 1.
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1.192 2 5 9 m).
2.Article 1: m).
Article 2: m).
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Needless to say, the first question will be explained: this is a typical sum multiple problem, knowing the sum of two numbers, and also knowing the multiple relationship between two numbers, then just divide the sum by the total multiple.
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Divide 192 by 5 by 3 to calculate the workload of a small loom in one hour and divide by 9 to calculate how many hours!
Think of the 2nd rope as one part, the first one is 4 parts, divide by (4+1) to get the second rope, divide by (4+1) by 4 is the first!
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1. Lay an underground cable on Zhongyuan Road, 34 have been laid, and there are still 250 meters left without paving. How many meters is the total length of this cable.
2. Repair a section of the road, the first day of the repair of the total length of 1 4, the second day of the repair of 90 meters, at this time there are still 150 meters left to repair. How many meters is this section of the road?
3. There is a pile of yellow sand at the construction site, and 23 tons were used, and exactly 60 tons were used. How many tons of yellow sand were there in this pile?
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Question 1: Calculate how many meters each loom can weave:
192 2 5 192 (2 5) = m).
Then calculate how many meters of cloth can be woven by 9 identical looms:
m) Question 2: Article 1: m).
Article 2: m).
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A wrong question shall not be deducted 9 points and then 3 points will be deducted 12 points, and a wrong question will be deducted 12 points.
The total score was 13 9 117
The demerit is 117 84 33
The number of wrong questions is 33 12 ??
The data in you is wrong?
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Xiaolan read a book, read 24 pages on the first day, accounting for 1/5 of the book, and read the whole book on the second day, how many pages did the book read? How many pages are left unread?
I'll help you out.
24 1 5=120 (pages) Answer: There are 120 pages in this book.
120 pages) 120 24 9=87 (pages) Answer: There are 87 pages left unread.
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How high is your score I'll help you with a short answer:
According to the fact that when B reaches the top of the mountain, A just goes down halfway up the mountain, we can divide the distance that A has climbed into 3 sections, and B only climbs 2 sections The distance ratio is 3:2 Speed ratio = 3:2 Then B climbs the remaining 60 meters A should climb 60 2 3 = 90 meters to return to the 60 meters that have been climbed 90 + 60 = 150 meters 150x2 = 300 meters The mountain is 300 meters high.
Assuming that A does not return and continues to climb the mountain, the 60 meters of the descent are folded into the uphill is 60 meters 300 + 40 = 340 meters and 1 hour = 60 minutes.
Then 340 60 = 17 3 meters is the speed of A going up the mountain, and 17 meters is the speed of A going down the mountain.
300-60) 17 2=minutes = hours 1+hours.
A: The mountain is 300 meters high, and it will take you a few hours to return to the starting point.
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Assuming that the velocities of A and B are a and b respectively, and the high position of the mountain is h, then h a+60 a*; h-60)/b=1; h/b=h/a+;
then h=360, a=400; b = 300, so it takes 360 400 + 360 600 = hours.
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Let the speed of A be x, B be y, and the mountain height be h(h-60) y=h x+60 (solve h=360x=420 and share 360 420+360 (hours.)
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It should be 600 meters, right? That's what makes it realistic.
Solution: If A does not go down the mountain and advances at the same speed, then 600 meters down the mountain is equivalent to 400 meters up the mountain, that is, the speed difference between A and B in 1 hour is 600 + 400 = 1000 meters.
A walks half the way down the mountain, which is equivalent to walking 1 3 distance at the speed of going up the mountain, that is, B goes up the mountain and walks a whole way, and A goes up the mountain and walks a whole distance of 1 1 3.
From this, it can be seen that the speed ratio of A and B is 4:3, and it is known that A walks 1000 meters more than B per hour, so the speed of A going up the mountain is 4000 meters per hour, and the speed of B going up the mountain is 3000 meters per hour, the total length of a single trip is: 3000 + 600 = kilometers, and the time taken by A to return to the starting point is: hours).
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It lasted for hours. I'm more complicated, if it's really a primary school student, I don't understand. 60 meters is also right, the height of the mountain reaches 360 meters.
Suppose the velocity of A is m meters per second, the speed of B is n meters per second, and the mountain is x meters high, then x-60 = n, x m + 60 , 60 n = The result of the solution is that the mountain is 360 meters high, n = 300 m = 400
Then the total time of 300=600t is the hour.
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It's hard to count, I don't want to play to see that the upstairs is similar to me.
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Because 12-5=7, the single digit of the subtraction is 5, the subtraction is actually 35 and is regarded as 55, and 55 27=82 is considered to be 82 by the subtraction, and the actual is 87, so the correct equation is 87-35=52
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km, 800-700 = 100 km.
Box tease balance, 30 150 * 100% = 20%.
Yuan. Centimeter 50*50*flat bucket cavity square centimeter.
Mountain do 4 = 105 people, 140-105 = 35 people.
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1.800*(1-7 rolling 8)=100 (m)3Yuan.
Centimeter 50*50*square centimeter.
5.If the girl has x, then x+3 4x=140, so x=80, the girl has 80 people.
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1 line 7 8 divide 800 by 8 times 7, find the reserve number out of 7 8 to get 700, imitate the first and last use 800-700 = 100 kilometers.
2 Divide 180 into 100 parts, one portion, and finally divide 30 by Lao Dou.
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I'll do this for you to see if you can understand it:
Zhi does not use the equation is like this:
dao140-140 4) specialized(1-1 4-2 5)=105 7 20
300 (basket).
In the case of equations, it is:
First of all, this fruit shop has a total of x baskets of fruits, which is derived from the title:
First analysis: subtract the first day sold from the original common x basket, and then subtract the second day, which is equal to the remainder, that is, x-95-45, and sell the remaining quarter on the third day, that is, multiply the remaining by a quarter, that is, (x-95-45)*1 4, at this time, there is still two-fifths of the total number left, and how many baskets is two-fifths, that is, multiply the total by two-fifths to be the remainder, that is, the total number minus the first day, subtract the second day, and then subtract the remainder of the third day.
Process: x-95-45-(x-95-45)*1 4=2 5xx-140-1 4x+140 4=2 5xx-1 4x-2 5x=140-140 47 20x=105
x=300A: This fruit shop has a total of 300 baskets of fruits.
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Because (1-1 4) surplus copy=2 5 total so get the remaining =2 5 total bai4 3=8 15 total.
The basket sold on the first or second day (du95+45) is zhi1-8 15 total (95+45) [1-2 5 (1-1 4)]=140 8 15=300 (basket dao).
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(95+45) divided by (1-quarter) divided by (1-2/5).
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