When it comes to physics, I can t figure out what to do about the specific heat capacity

This problem is not rigorous, heating together, can only show that the time is the same, because the heat absorption ability of different substances is generally different, and the quality is different, so the heat absorbed in the same time will be different, and δt will be different, and this problem cannot be calculated. So the meaning of the title is to heat the two substances together to the same elevated temperature, so that you can do it

If the volume is the same, then m = pv to get m lead: m copper = (p lead v lead) :(p copper v copper) = p lead: p copper =

q=cmδt.

Q lead: Q copper = c lead m lead δt : c copper m copper δt = c lead m lead c copper m copper = (c lead c copper) * (m lead m copper).

If you have 1 cubic meter of lead, then you have lead that absorbs heat.

If you have 1 cubic meter of copper, then you have copper that absorbs heat.

No, you didn't tell me how many degrees Celsius it was, I'll take the answer of one degree Celsius increase, and press the calculator myself.

The volume is the same, and the mass is calculated first.

m lead = density * volume = m copper = volume are set to v, g m3 to be converted to kg m3).

According to the formula: heat absorbed = specific heat * mass * temperature change and q=cm (t - t0).

q Lead = 130 J (kg.))t - t0)q copper = 390j (kg..)T - t0) The two objects are at room temperature before heating, so t0 is the same, they are heated together, the title does not say how long, it should be 100 degrees Celsius to the boiling point of water, so t is the same, so the change in temperature is the same.

Comparison of the two formulas. Q lead: q copper = (130 * 390 * 267

q=cmt, the endothermic ratio is 130*:390*, and the simplified ratio is 113:267

First of all, there are only two ways to change the internal energy, work and heat transfer, and the sand in the question is not heated, indicating that there is no heat transfer problem, and shaking the test tube is to sit on the sand, so the sand increases the internal energy by doing work. The specific heat capacity formula Q=CMΔT=920*

Then the internal energy of the sand is increased by (work), increasing (276 joules).

100 grams = kilograms.

q = cm (t-t0) = cubic cubic = 276 (joules).

1.The amount of heat absorbed by a 1kg of water with an increase in temperature1 is 4200j

2.The amount of heat absorbed by the mass of 5kg of water and the increase in temperature1 is 4200J*5=21000J

3.The heat absorbed by water with a mass of 1kg and an increase in temperature of 10 is 4200J*10=42000J

4.The heat absorbed by the temperature increase of 5kg of water by 10 is 4200J*5*10=210000J

If we know which q represents the heat absorbed by the object, c represents the specific heat capacity of the substance, m represents the mass of the object, and t0 and t are the temperature of the object before and after heating, respectively, through the above calculations, we can summarize a formula for calculating heat: q=cm(t-t0).

If you want to calculate the heat emitted by the old object when it cools down, then the formula should be q=cm(t0-t).

1 All aHeat travels from A to B.

The mass of A is 2 times that of B, so that after they respectively release the same heat, A drops less temperature from a hot object to a low temperature object.

Calculate the temperature after exothermic first.

q=cm(t at the beginning - at the end of t) Since the heat release is the same, the specific heat is the same, and the mass of A is large, so the temperature of A changes little, so the temperature of A is higher than the temperature of B after the same heat is released, so the heat is transferred from A to B.

q=cm（t0-t）

Q, C, T0 are the same, the mass of A is large, T should be large (so that T0-T is small), so the temperature of A is high after the same heat is released, and the heat transfer is transferred from high temperature to low temperature, so AThe heat is transferred from A to B correctly.

In fact, it is very simple, as long as the dust is white, the energy is conserved. The copper block is set up to release heat, and the liquid absorbs heat. Q copper = C1M1T1 = Q liquid = C2M2T2

c1=,m1=100g=,t1=100-25=75c,m2=100g=,t2=25-10=15c

So we get c2=c1m1t1 m2t2=2000j (kg*c)

q = cm (t1-t2), water mass m = pv = 1000 * 80 * 10 -6 =

The beaker is placed in the air, and a part of the heat will be lost in the air, first of all, the heat lost by the water in the air is not considered, that is, assuming that all the heat of the water is transferred to the egg, the heat transferred = 4200*, but in fact, a part of the heat must be transferred to the air, so it will not exceed 16800J at most.

Hot water at 80 degrees Celsius can be exchanged with air. Some of the heat is absorbed by the air.

The heat lost is absorbed by the air.

Analyze by the control variable method, your question, otherwise the question is inaccurate.

Under the premise that the heat absorbed by the body is equal when heated for the same time.

1. Absorb the same heat, the larger the specific heat capacity, the smaller the temperature change.

2. The larger the specific heat capacity, the longer the heating time, and the more heat is absorbed.

3. The heating time of liquid fiber is the same, and the larger the specific heat capacity, the smaller the temperature change.

Is your question correct, and the length of time that adds excitement indicates how much heat is absorbed, 2 is not the right question.

The longer the heating time, the more heat is absorbed, and the greater the temperature change [it is impossible to absorb the same heat].

Let the final temperature be t: the heat emitted by iron is equal to the heat absorbed by water.

C iron m iron. (t-t) = cwater. m water. (t-t water) to figure out the answer.

About 28 degrees. Iron first absorbs heat and then exothermic the water. Find out the amount of heat absorbed by the iron first. Then use the isometric off series of equations. Just find the temperature.

Solution: Since Q Suck = Q Release;

So, c water m water t water = c gold m gold t gold;

Namely; So, t=-10

So the answer is: -10