Easy Senior 1 Physics Questions, Simple Physics Questions Senior 1

Can't see what the inclination is, so.

Let the inclination angle be , the gravitational acceleration is g, and the initial velocity v0 throws an object flat, and the object falls to the hillside at time t.

According to the flat toss, there is (,g=(2v0*tan ) t

Then according to the centripetal force formula, let the velocity be v1 and the radius r we have mg=(mv 2) r

v=√(gr)

At the same time, according to the gravitational formula, there are mg=gmm r 2, g=g*m r 2=(2v0*tan ) t

r=√[(g*m*t)/(2v0*tanθ)]

Finally, we get v= (gr)=v= [(g*m r 2)*r]== (g*m r)=

[g*m*2v0*tanθ)/t]

Surface gravitational acceleration: gm r = g, hillside fall distance: h=1 2gt, hillside horizontal flight distance:

s=v0 t, the relationship between the distance and the angle: h s=tan( ) the relationship between the velocity of the first universe and the acceleration of the gravitational acceleration on the surface: v r=g

Solution: v=((2 g m v0 tan( ) t) (1 4).

x=v0t y= y=x tan is solved to get a=(2v0tan ) t

gm=r 2 a solution r=root number under ((gmt) (2v0tan )).

v=ar under the root number, just bring it in.

As can be seen from the title, first use the relationship between the terminal velocity and the angle in the horizontal direction to find g, then find the radius of the celestial body according to the mass of the celestial body and g, and then find the first cosmic velocity of the celestial body according to the relationship between the first cosmic velocity, that is, the initial velocity at the time of ejection.

Analysis: When going downhill, the speed of closing the throttle is unchanged, and the car does not close the throttle without the resistance of the component force of the inclined plane sliding, and the initial velocity is V, which can be obtained from the kinetic energy theorem.

Answer: pt = m (2v) square 2-mv square 2 i.e. pt + 1 2 * mv 2 = 1 2 * m * (2v) 2 solution v square = 2pt 3m

That is, v is equal to (2pt 3m) open root number.

When the throttle is closed when going downhill, the speed remains the same, and the work done by gravity cancels out the work done by friction, then when the throttle is opened, it is equivalent to only traction doing work, and the power is p, then pt+1 2*mv 2=1 2*m*(2v) 2

then v=pt (6m) 3m

Select C (provide ideas).

From Coulomb's law formula f=k*(q1*q2) r 2, the Coulomb force on the two balls is equal (regardless of whether the two balls are charged or not).

It can be found that the tensile force received by the two ropes is equal, and since the angle between the rope and the vertical direction is equal, it can be concluded that the gravitational force of the two small balls is equal, that is, the mass is equal. So choose C.

Senior high school seniors inspect....

En, the landlord has a future, is this a high school student, and the upstairs formula is wrong, it's a shame, whatever, whatever? The answer is as follows.

Solution: Because both Jupiter and the Earth revolve around the Sun.

Therefore, (a 3) (t 2) = (a wood 3) (t wood 2) = k substituting the relevant data.

A ground a wood = 144 (1 3).

Both Jupiter and the Earth revolve around the Sun.

Kepler's third law.

a-wood t-wood = k

A T = K

Solution: awood aground = 12 3

Kepler's third law.

The square of t is proportional to the cubic of r.

So it's 8 times.

One misstep becomes a thousand years of hatred The last step is reversed Change the vest and correct it Don't mislead the younger brothers and sisters It's a wood A land 144 (1 3) You must adopt it.

Because it is a distance and not a displacement, it should be discussed on a case-by-case basis.1 If the journey is in the ascending phase.

s= v=38m/s

2.If the journey includes an ascent and descent phases.

There are 2=65 v=gt=10tt=3s or 2s

v = 30 ms or 20 ms

C and D are the same answers to this question. I guess C and D are both correct.

d: Yes, the antenna suddenly breaks off (if there is no external force to interrupt it), of course, it still joins the satellite together (it does not fly outside the orbit of the satellite, because they all have the force of centripetal acceleration towards the Earth).

C is right, because what the satellite does is free fall, it keeps falling towards the earth but never lands on the ground, because the earth is round.

d right. The gravitational pull of the Earth on the satellite maintains the centripetal force of the satellite's motion around the Earth. From the formula gmm r2 = mv2 r, (gravitational force equals centripetal force) can be approximated to m, that is, it has nothing to do with the weight of the satellite itself.

Therefore, the antenna is broken, although the mass is reduced, but it does not affect its motion law.