Find a three digit number so that it is the least than the sum of its digits

In ABC, BC is certain, x=(100*A+10*B+C) (A+B+C)=(100*A+100*B+100*C-90*B-99*C) (A+B+C)=100-(90*B+99*C) (A+B+C), the smaller A, the smaller X, so A=1

c in 1bc is certain, x=(100+10*b+c) (1+b+c)=

10+10*b+10c+90-9*c)/(1+b+c)=10+(90-9*c)/(1+b+c)

a, b, and c are numbers from 1 to 9, so all positive numbers in parentheses. Then the larger b is, the smaller x is, so b=9

In 19c, x=(190+c) (10+c)=(10+c+180) (10+c)=

1+180 (10+c), the larger the c, the smaller the x, so c=9

To sum up, the three-digit number is 199(abc is a hypothetical three-digit number, and x is its ratio to the sum of its digits).Thank you.

This number is 248, and its hepdigimal representation is 503 and the nine-decimal representation is 305

The C language program for calculating the above figures, along with the notes, is as follows:

main(){

int i,i71,i72,i73,i91,i92,i93;

for (i=100;i<=999;i++) *look for *in all three digits*

i71=i%7;i72=(i/7)%7;i73=(i/49)%7;A three-digit number in the heptalic form of *i

i91=i%9;i92=(i/9)%9;i93=(i/81)%9;A three-digit number in the nine-decimal form of *i

if (i73>0 &&i93>0 &&i73<7 &&i93<9 *The hepdigcimal form and the nine-decimal form are both three-digit numbers*

And in reverse order*

printf("%d\t%d%d%d\t%d%d%d",i,i73,i72,i71,i93,i92,i91);*Outputs this number, as well as the hepdigcimal and nine-decimal forms*

Hope...

Let the three-digit numbers be x, y, z (0--9 integers, x is not 0), then it becomes a find.

100x+10y+z) (x+y+z). When x=1, y=9, z=9, take the minimum value. The minimum value is approximately equal to.

199 is the minimum ratio, and Billy is:

As long as it's an integer hundred.

Solution: Knowing that the sum of the digits of the three digits is 3, then the three digits are composed of one or several numbers.

To make the three-digit number the largest, the hundredth digit is 3, and the three-digit number is 300;

To make the three-digit number the smallest, the hundred-digit digit is 1, and the three-digit number is 102.

A: Among the three digits, the maximum is 300 and the minimum is 102.

The sum of each digit is 3, then the largest number is to make the hundred as large as possible, so easy to think of as 300, try to give the hundred, the smallest, the hundred can not be zero, so it can only be 1, then the rest of the number as much as possible to give a single digit, that is, 102.

Answer: If you know a three-digit number, the sum of its digits is 3, so that the largest of the three-digit numbers is 210 and the smallest is 102.

The sum of the three digits is 3, and the three digits are made up of one or more of them. To make the three-digit number the largest, the maximum number in the hundredth place is 3, and the three-digit number is 300; To make the three-digit number the smallest, the hundred-digit digit is 1, and the three-digit number is 102. A:

Among the three digits, the maximum is 300 and the smallest is 102.

The largest of these three digits should be 300 and the smallest is 102.

Because the sum of the numbers is 3, but the number of hundreds cannot be 0, it is possible to be 300, 210, 201, 120, 102, so the maximum is 300 and the minimum is 102.

The solution, as the title suggests, is that the sum of the numbers is 3So there is.

The largest is that the number in the hundred place is 3, and the number in the single and tenth places is 0So this maximum number is 300

The smallest three-digit number can only be 1 in the hundreds, 0 in the tens, and 2 in the single digitsSo the minimum is 102Hope!

A three-digit number is known, and the sum of its digits is three.

Then the number can only be 0123.

So what is the maximum number of three digits? What is the minimum?

We can take a closer look and the maximum is 300 and the minimum is 102.

The largest number is 300 (3+0+0 3).

The smallest number is 102 (1+0+2 3).

Solution: It can be known from the question:

The largest number is 300 and the smallest number is 102.

The maximum number of hours on the hundred place is the largest, so the maximum is 300, and the smallest number of hours on the hundred place and the maximum hours on the single place is the smallest, so the minimum is 102.

So how can we think of a good solution to this problem? I'm playing on my phone outside.

Answer: Najin and Minxun are 1000, and the difference is 998

So the answer is: 1000,998

Summary. The smallest three-digit number, the hundred-digit number cannot be zero, should take 1, the ten-digit number should also be relatively small, you can take 0, then the single-digit number is 2.

Knowing a three-digit number, the sum of its digits is 3, so what is the largest of the three-digit numbers? What is the minimum?

Wait a minute! I'll give you an answer right away, wait a while, it's not complicated.

In such a three-digit number, the maximum is 300 and the minimum is 102

How did this come about.

I don't understand. Didn't understand the question.

Here's how to put it this way: the largest three-digit number is 999, and the smallest three-digit number is 100.

And this question has a limit: if the sum of the digits of a three-digit number is 3, then the largest number should be a hundred digits, and the maximum is 3

The smallest three-digit number, the hundred-digit number cannot be zero, should take 1, the ten-digit number should also be relatively small, you can take 0, then the single-digit number is 2.

The largest three-digit number is 999, and the smallest two-digit number is 10,999+10=1009,999-10=989,1009-989=20, so the sum of the largest three-digit number and the smallest two-digit number is 1009, the difference is 989, and the sum is 20 greater than the difference

So the answer is back to mold: 1009,989,20

Test Point: Addition and Subtraction of Whole Numbers Topic: Text Narrative Questions Analysis:

According to the arrangement law of natural numbers, the largest three-digit number is 999, and the smallest two-digit number is 10, then the difference between the largest three-digit number and the smallest missing two-digit number is 999-10=989 999-10=989Answer: The largest three-digit number is 999, and the smallest two-digit number is 10, and their difference is 989 Therefore, the answer is a search: 999,10,989 Comments:

Determining the value of the largest three-digit number and the smallest two-digit number is the key to completing this problem

The largest two-digit number is 99, and the smallest three-digit number is 100, which is 100-99=1;

Therefore, the answer is: only key game 99,100, finger pin 1

The smallest three-digit number is 100, and the largest two-digit number is 99, the difference: 100-99=1

Answer: The number of digits of the most Yu Sen with the small Sanchun Qing is 1 more than the largest double digit

So the answer is: 1

If you know a three-digit number, the sum of its digits is 3, and the largest of these three-digit numbers is 300 and the smallest is 102.

Hope it helps!