ABC is three different three digit numbers, and their sum is 567, where A is 189B, and what is the m

Knowing that ABC is three different three-digit numbers, and a=189, so b+c=567-189=378, it can be concluded that when c is the minimum value, b is the largest, and because abc is a three-digit number, so only when c is the smallest is 100, b can be the maximum.

So b=378-100=278

So the maximum value of b is 278

Comprehensive formula: 567-189-100=378-100=278<>

According to the title, b +c = 567-189 = 378 because all three digits are three-digit numbers, and the smallest three-digit number is 100. So.

b =378-100=278

So the number b is up to 278.

Because ABC is three different three-digit numbers, A is 189, and 567-189 = 378, 378 is the sum of B and C, so when C is at least 100, B is the largest.

b=378-100=278

So the maximum value of b is 278

Comprehensive formula: 567-189-100=378-100=278<>

Because a+b+c=567 a=189

Then b+c=378

If all three numbers are integers, and they are different numbers, then b is up to 377

2886=222(a+b+c)a+b+c=13。

abc-cba=495。

abc=742。

a=7，b=4，c=2。

The order of operation of the four operations:

1. If there is only addition and subtraction or only multiplication and division, calculate from left to right.

2. If there is a first-level operation and a second-level operation at the same time, the second-level operation will be calculated first.

Addition in Abstract Algebra:

Vector addition:

a, b, c can be composed of 3 digits: abc, acb, bac, bca, cab, cba, all the numbers are disassembled as follows: abc=a*100+b*10+c

The sum of all 3 digits is 2886, that is.

abc+acb+bac+bca+cab+cba (break all the numbers apart).

a*200+b*200+c*200 + a*20+b*20+c*20 + a*2+b*2+c*2

a+b+c)*222

Simplify to get a+b+c=13

The difference between the largest and the smallest number is 495, i.e., abc - cba = 495

a*100+b*10+c - c*100+b*10+a)

a-c)*99=495 simplification yields a-c=5

Now we get 2 formulas: a+b+c=13 and a-c=5, and the conditions a, b, and c are 3 unequal numbers from 1 to 9, and a>b>c

Assuming c=1, then bringing in the above two equations gives a=6, b=6, which does not satisfy a>b>c

Assuming c=2, then bringing in the above two equations gives a=7, b=4, and the conditions are satisfied.

Assuming c=3, then taking in the above two equations gives a=8, b=2, which does not satisfy a>b>c

Below c = 4, 5, 6 ......You don't have to make it up, you must not meet a>b>c, so a=7, b=4, c=2

The sum of ABC is 756, and C is 168, then the sum of AB is: 756-168=588, C>B, and B are three digits, then the minimum is 100, and A is: 588-100=488, and the maximum of A is 488.

Since c is 168, then a+b=756-168=588

Because a c b, when b is the smallest three-digit 100, the maximum value of a is 588-100=488

A+B+C 756, and C 168

So A+B 588

When b is the smallest three-digit number, a is the largest.

The smallest three-digit number is 100

So a maximum is 588-100 488

The maximum three digits of the number sum is 26, and the maximum three-digit number composed of these three Huaishi numbers is 998

A: The maximum number is 998

Therefore, c

Solution: Treat b as an unknown.

A is 7 larger than b, then a can be expressed as b+7.

B is 5 larger than C, then C can be denoted as B-5.

According to "the sum of the three numbers of abc is 106", the following equation can be listed:

a+b+c=106

b+7)+b+(b-5)=106

3b+2=106

3b=104

b=104/3

c=104/3-5

Hello, the question can be changed as follows:

From the title: a+b+c 106

a＝b+7b＝c+5

a＝c+5+7

c+5+7+c+5+c＝106

3c+17＝106

c＝（106-17）/3

According to the fact that A is 7 larger than B and B is 5 larger than C, it can be seen that A is 7+5 larger than C 12.

This is a 'matter of harmony and difference'.

Smaller number (c) (sum-difference) 3

29 and 2 3

a+b+c=106

A is 7 larger than b, then a = b+7

b is 5 larger than c, b = c+5

So a+b+c=b+7+c+5+c

c+5+7+c+5+c

3c+17=106

c=89/3

Judging from the title, the hundredth digit of a must be 6, the single digit can be 2 or 3, if the single digit is 2, subtract the single digit 6 to get the single digit 6, if it is 3, subtract 2, 3, 6 will not get 6 (it can only be 1, 0, 7), so the single digit of a is 2, the ten digit is 3, and a is 632. From the above analysis, the single digit of b is 6, and the number of hundreds can only be 2, so b is.

A can form 236,263,326,362,623,632b can form 236,263,326,362,623,632 because a-b = 396, let a be 100a+10a1+a2b is 100b+10b1+b2

100a+10a1+a2-100b-10b1-b2=300+90+6100a-100b=300

a-b=3a is 623 or 632 (a-hundredth can only be 6), a2-b2=6

b is 236 or 326 (a can only be 2, b can only be 6). 632-326 = 306 (discarded) Answer: a, b equals 632, 236 respectively

a: There are any of the following possibilities

bThe following possibilities apply:

Next, you have to conclude that the number a-b is equal to 396 is relatively large, so you use the maximum value of a to start finding the minimum value of b, and try them one by one. If you do more, you can change the arrangement directly according to the meaning of the topic like I did.

The possible a-b in the first question of this question is = 396

So A is 632 and B is 236.

a-b＝396

A and B are made up of 236, then.

The last digit of a is 2 and the last digit of b is 6

The first digit of A is 6 and the first digit of B is 2

ab middle numbers are consistent, so.

a-b＝662-266＝396

a-b＝632-236＝396

a-b＝622-226＝396

Hello landlord.

ABC+ACB+BCA+BAC+CA+CBA=100A+10B+C+100A+10C+B+100B+10C+A+100B+10A+C+100C+100A+B+100C+10B+A=222A+222B+222C=222 (A+B+C), if A+B+C=15, then 222 (A+B+C)-3194=222 15-3194=136=ABC, It doesn't fit the title, because 1+3+6≠15. If a+b+c=16, then 222 (a+b+c)-3194=222 16-3194=358=abc, which is in line with the topic, because 3+5+8=16. If a+b+c=17, then 222 (a+b+c)-3194=222 17-3194=580=abc, which is not in line with the title, because 5+8+0≠17.

If a+b+c=18, then 222 (a+b+c)-3194=222 18-3194=802=abc, which does not fit the title, because 8+0+2≠18. After that, 222 (a+b+c)-3194 is not a three-digit number, let alone a three-digit number, so this three-digit number is 358

Hope you're satisfied.

Because a+b=c, a+b+c=32, we get 2c=32, c=16

And because a=, so b=