THERE IS A PILE OF CONICAL YELLOW SAND ON THE CONSTRUCTION SITE, AND THE CIRCUMFERENCE OF ITS BOTTOM

This is a problem in elementary school, I may have forgotten to calculate, don't laugh at me, circumference = 2 r is to get r = 2, that is, the radius of the conic is 2, and then according to the volume of the cone, it is 1 3 of the volume of the cylindrical row to calculate the volume of the cone=1 3 r 2*h =

The volume of the conical shape is obtained.

Then multiply the volume by the density Weight (t) = the final weight is , the result must be correct, the process is like this, there is no professional specification described, it can be regarded as okay, I hope it can help you.

Bottom Radius: (2*m.)

Base area: *2*2 = square meters.

Volume: (1 3) * = cubic meters.

Base area: multiplied (divided by 2) squared = square meters).

Volume: multiplied by one-third = cubic meter).

Multiply by tons).

This is a problem in elementary school, and I may have forgotten it, don't laugh at me, circumference = 2 r is to get r = 2 which is the radius of the cone is 2

Then calculate the volume of the cone=1 3 r 2*h = according to the volume of the cone, which is 1 3 of the volume of the cylindrical row

The volume of the conical shape is obtained.

Then multiply the volume by the density and you're good to go: Weight (t) =

In the end, the weight of the cavity Brother Hong is, the result must be correct, the process is like this, it is described without professional norms, and it can be regarded as okay, 10, spend a report.

yes, tomorrow, see if that's right.

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En, yes, how about the calculation, the base area: multiplied by (divided by 2) squared = square meters).

Volume: multiplied by one-third = cubic meter).

Multiply by tons), 2, bottom radius: (2 * meters.)

Base area: *2*2 = square meters.

Volume: (1 3) * = cubic meters, 2, there is a conical pile of yellow sand on the construction site, and the circumference of its bottom surface is measured to be, and the height is, if each cubic meter of yellow sand weighs tons, then how many tons are in this pair of yellow sand.

Summary. The circumference is.

The height is available for the volume is.

The specific gravity of the sand pile is.

This pile of sand is about a ton.

The construction site has a conical sand pile with a bottom circumference of meters and a height of meters. If every cubic meter of sand.

The circumference is high, it can be decent, and the accumulation of wisdom is a large pile of sand, and the specific gravity is bright, and this pile of sand is about a ton.

Take a look!

Summary. Hello dear, according to your problem description: first you need to calculate the radius of the bottom surface of the sand pile, since the circumference of the bottom surface is meters, there is:

Perimeter = 2 = 2 RR = 2 2 metersTherefore, the bottom radius of the sand pile is 2 meters. According to the volume formula of the cone: v = 1 3 r h, where r is the radius of the base and h is the height.

Substituting r = 2 m and h = 15 dm = m into the above equation, we get: v = 1 3 2 m) m cubic meter Therefore, the volume of this pile of sand is about cubic meter. I hope mine can help you, if you are satisfied with my service, please give a thumbs up (in the lower left corner of the evaluation), look forward to your like, your efforts are very important to me, your support is also the driving force for my progress.

Hello Qinqin Ridge, according to your problem description: first of all, you need to calculate the bottom radius of the sand pile, since the bottom circumference is meters, so there is: perimeter = 2 = 2 rr = 2 2 meters Therefore, the bottom radius of the sand pile is 2 meters.

According to the volume formula of the cone: v = 1 3 r h, where r is the radius of the base and h is the height. Substitute r = 2 meters, h = 15 dm = meters into the above formula, and you get:

v = 1 3 2 m) m cubic meters Therefore, the volume of this pile of sand is about cubic meters. I hope mine can help you, if you are satisfied with my service, please give a thumbs up (in the lower left corner of the evaluation), look forward to your like, your efforts are very important to me, your support is also the motivation for me to progress and overcome difficulties. Or post if you have any other questions you can continue to describe and I will try my best to help you.

Please take a look.

Bottom radius: m.

Base area: square meters.

Volume: (1 3) * = cubic meters.

Bottom radius = meters.

Volume = 2 2 cubic meters.

Thickness = m = 33 cm.

Calculate the volume first, the volume is the base area multiplied by the height divided by 3, the base area is equal to the square of the radius of the bottom surface multiplied by the "pie", the radius is 2, the area is, so the volume is, and then divide by (5x3) to get the answer:

Bottom radius: m.

Volume: cubic meters.

Weight of sand: tons.

Hello: (1) How many cubic meters is this pile of sand?

Base circumference = m)

Base area: square meters.

Volume: (1 3) * = cubic meters.

2) If you fill a sand pit with this pile of sand that is 5 meters long and 3 meters wide. How many centimeters of sand is in a sand pit?

cm) (3) If each cubic meter of sand weighs tons, how many tons does this pile of sand weigh in total? (The number of whole tons is retained) tons).

The base radius is meters.

then volume = cubic meters.

2) The thickness of the sand in the sand pit is m = cm.

3) Weight = tons 9 tons.

The volume of the cone: 1 3

]1 3, = cubic meters), the tonnage of this pile of sand: t) 11 (t).

A: The pile of sand weighs about 11 tons