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A total of 15 different currencies can be formed.
Analysis: In the question, one RMB of each of the four different currency values, that is, any one, two, three, and four of the four different currency values of RMB are taken as a group and combined.
1. 1 RMB alone: 1 yuan, 2 yuan, 5 yuan, 10 yuan, a total of 4 currency values.
Zhang RMB Portfolio:
1+2=3 (yuan), 1+5=6 (yuan), 1+10=11 (yuan), 2+5=7 (yuan), 2+10=12 (yuan), 5+10=15 (yuan).
There are 6 different combinations to get 6 different currency values.
Zhang RMB Portfolio:
1+2+5=8 (yuan), 1+2+10=13 (yuan), 1+5+10=16 (yuan), 2+5+10=17 (yuan).
There are 4 different combinations to get 4 different currency values.
RMB combination: 1 + 2 + 5 + 10 = 18 (yuan).
A total of 1 different combinations to get 1 different currency value.
Add the value of the above four combinations to 4+6+4+1=15 (kinds), so there are 15 combinations in total.
This is a combinatorial problem in mathematics. Taking any of the m (m n) elements as a group from n (4 in the problem) is called a combination of m elements from n different elements. This problem of finding the number of combinations is called a combination problem.
The number of combinations can be calculated directly with the formula as:
As in the question: n=4, m are 1, 2, 3, 4 respectively.
The result of calculating m equals 1,2,3,4 is: 4,6,4,1. Add the results together to get 15. That is, there are 15 different combinations.
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15 kinds. Analysis:
There are four categories. The first category: when only one currency value is selected, there are 4 ways to take it, that is, one yuan, two yuan, five yuan, and ten yuan.
The second category is composed of two currency values: there are six ways to take it, (the column treemap can be clearly seen) The third category: three kinds of currency values are selected, there are four ways to take it, (the column treemap can be clearly seen) The fourth category:
Choosing four currency values, there is one way to take it, (which can be clearly seen in the tree diagram) from the principle of addition, and there are 15 ways to take it.
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Analysis: According to the title, one 10 yuan, one 5 yuan, one 2 yuan, and one 1 yuan are 4 different currency values;
Then from a 10 yuan, a 5 yuan, a 2 yuan, a 1 yuan, can be composed of 3 yuan, 6 yuan, 7 yuan, 8 yuan, 11 yuan, 12 yuan, 13 yuan, 15 yuan, 16 yuan, 17 yuan, 18 yuan, that is, 11 different currency values.
Solution: (1) 10 yuan, 5 yuan, 2 yuan, and 1 yuan, which are 4 different currency values;
2) And because:
1+2=3 (yuan), 5+1=6 (yuan), 5+2=7 (yuan), 5+2+1=8 (yuan), 10+1=11 (yuan), 10+2=12 (yuan).
10 + 1 + 2 = 13 (yuan), 10 + 5 = 15 (yuan), 1 Guangdu pirate decaldehyde contains 0 + 5 + 1 = 16 (yuan), 10 + 5 + 2 = 17 (yuan), 10 + 5 + 2 + 1 = 18 (yuan), a total of 11 different currency values;
Therefore, it can be composed of: 4 + 11 = 15 (kinds) of different currency values
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There are 6 combinations of 2 cards.
There are 6 combinations of 3 cards.
Choose four cards and have 1 combination.
Question: Shouldn't the word "composition" be called two or more sheets?
Choose one of each 10 yuan, 5 yuan, 2 yuan, 1 yuan Can these four also be called compositions?
Doesn't one piece make up a currency?
Composition is a combination of parts and individuals to form a whole.
Question: I'm struggling with the word now, and his question is: How many kinds of money can be composed, and if you choose 3 cards, it should be 4, right?
There are fifteen in total.
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Use 1 sheet: 10 yuan, 5 yuan, 2 yuan, 3 kinds;
2 sheets: 10 + 5 = 15 (yuan);
10+2=12 (yuan);
5+2=7 (yuan);
3 different possibilities;
3 sheets: 2 + 5 + 10 = 17 (yuan);
One possibility is a total of 3+3+1=7 (species);
Answer: A total of Fu Fu can be formed to shake Tan Hao Dian Tong to set the outline.
7 different currency values
So the answer is: 7
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Pick one out of four 4
Pick two out of four 6s
Pick three out of four 4s
Choose 115 of all four.
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Because there is no order, it belongs to the combination, so c(4,1)+c(4,2)+c(4,3)+c(4,4)=4+6+4+1=15 species.
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+5+2+1=18
There are ten dollars, five dollars, two dollars, one dollar, five different ways to buy a book worth ten dollars, and this is how it is calculated
Yuan x1 = 10 yuan.
Yuan x2 = 10 yuan.
Yuan x1 + 1 yuan x 5 = 10 yuan.
Yuan x1 + 2 yuan x 2 + 1 yuan x 1 = 10 yuan.
Yuan x1 + 2 yuan x 1 + 1 yuan x 3 = 10 yuan.
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I can make up 15 different kinds of money.
1. Choose only one, there are 4 currencies of 1 yuan, 5 yuan, 10 yuan, and 20 yuan.
2. Choose only two tickets, and there are 6 currency values:
1+5=6 yuan;
1+10=11 yuan;
1+20=21 yuan;
5+10=15 yuan;
5+20=25 yuan;
10 + 20 = 30 yuan.
3. Choose only three tickets, with 4 currency values:
1+5+10=16 yuan;
1+5+20=26 yuan;
1+10+20=31 yuan;
5 + 10 + 20 = 35 yuan.
4. Four cards are all selected, and there is 1 currency value: 1 + 5 + 10 + 20 = 36 yuan.
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can be composed. A banknote:
zhi10、dao
Two banknotes back: A: +1=3
Three banknotes +2+1=8
Four notes: 10 + 5 + 2 + 1 = 18
So there are 15 different currencies in total.
Hope it helps.
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Summary. It can be composed of 15 currency values.
A banknote can be made up.
Two banknotes can make up +1=3.
Three banknotes can make up +2+1=8.
Four banknotes can be formed. 10+5+2+1=18。
There are 10 yuan, 5 yuan, 2 yuan, and 1 yuan, how many different currencies can be composed?
It can be composed of 15 currency values. A banknote can be made up. Two banknotes can be composed of:
1=3。Three banknotes can make up +2+1=8.
Four banknotes can be formed. 10+5+2+1=18。
I hope mine is helpful to you, you can continue to ask me any questions, I will reply to you as soon as possible, I am happy to serve you, I wish you a happy life
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A total of 7 different currencies can be formed. Yuan. Yuan.
Yuan. +5 = $7.
10 = 12 yuan.
5=15 yuan.
2+5=17 yuan.
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A total of 7 types: 1) 2 yuan.
2) $5.
3) $10.
4) $7.
5) $12.
6) $15.
7) $17.
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There are 7 types: meta. Yuan.
Yuan. +5 = $7.
10 = 12 yuan.
5=15 yuan.
2+5=17 yuan.
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This question is too unlevel, not rigorous! If you talk about the composition, you should be 7, 12, 15, 17
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