Physics questions about light, a physics question about light

The approximate process is as follows:

1. Multiply the two liquids into two square glass cups, paste a plastic whiteboard on one side of the glass, and pull a thin line on the other side, so that the light source raised by the laser pointer can be on the same horizontal line.

2.First, the two glasses are irradiated vertically with a laser. Use a marker pen to record two points on a plastic whiteboard.

3. The laser is incident at an angle on the same thin line, and the two points produced are recorded on two plastic whiteboards respectively.

4. Connect the two points generated by the second step and the third step respectively, take the two points generated by the second step as the origin, make the Cartesian coordinate axis, and then connect the incident point of the laser and the two points generated by the third step on the whiteboard.

Use a protractor to measure the angles as b1 and b2 respectively

So n1=tana tanb1;

n2=tana/tanb2

Not sure if my answer will work for you.

Anyway, his principle is to use the principle that if the density is high, the refractive index is large.

I don't know which province you're from.

Question types like this are generally found in mock exams at school, and are unlikely to appear in college entrance exams. Good luck.

Do you have a question or do you need exercises to do? Tell me your doubts, and I'll help you solve them, hi contact.

1.The intersection of the incident ray and the reflective surface.

A dashed line perpendicular to the reflective surface.

The angle between the reflected rays and the normals.

The angle between the incident ray and the normal.

2.Law of light reflection: coplanar, separated, equigonal.

The reflected rays, incident rays, and normals are in the same plane, and the reflected rays and incident rays are located on either side of the normal, and the angle of reflection is equal to the angle of incidence.

1。No, the candle flame itself is a light source, and it is the light emitted by the light source itself that reaches your eyes. Objects that do not emit light can be seen as diffuse reflection.

2。No, if the distance between AB and the glass is equal, there is no need to ignite B, and it will coincide. Because, A will produce a dotted line behind the glass. If you put B in the virtual image and look at it from A, it's as if B is on fire.

The first problem, seeing a candle flame, is not a reflection, but a direct propagation of light.

The second question should be that the conclusion is what is the relationship between the object and the distance from the image to the glass plate.

1.It is not diffuse reflection, it is the propagation of light in a straight line in a homogeneous medium.

2.No, because at this time, the image in the mirror is a virtual image, and it doesn't matter if it coincides or not. When b is in a position about the symmetry of the glass, it is consistent with the position of the virtual image of the glass.

Positive solution: (1) Straighten the straw for later use;

2) Turn on the laser pointer, put it in the straw at one end of the straw, and aim the other end of the straw at the wall, you can see the laser on the wall.

Counter-solution: (1) bend the straw at an angle of 90° or less for standby;

2) Turn on the laser pointer, put it in the straw at one end of the straw, aim the other end of the straw at the wall, and find that the laser is not visible on the wall.

From above, it is proved that light travels in a straight line in the air.

C Yes, the reflection in water is the imaging of the plane mirror, the principle of the plane mirror imaging is the reflection of light a, and the principle of the formation of shadows is that the light travels along a straight line.

B, the light emitted by the lighthouse is the light emitted by the light source, which is the incident ray D, and the light spot on the ground is a small hole imaging, and the principle is that the light travels along a straight line.

c, a linearity, blocked.

b I can't tell clearly, there is refraction and reflection.

dDiffraction another question d

aDiffraction or direct irradiation.

bThe straight line is blocked.

cRefraction of transparent objects.

The answer is c Reflection is formed by reflection.

A term shadow is the propagation of light in a straight line.

Item B is also a straight line propagation.

Item D is for small hole imaging.

Previous question: Because the surface of the sea and the surface of the water are like a mirror! The lights from the lighthouse and the reflection of the trees in the water are all virtual images formed by reflection! It's all a straight line of light!

Next question: D, the reason is the same as above! A: I don't know! B: Straight line propagation of light! c: Refraction of light.

Ca is the linear propagation of light, B is the linear propagation of light, C is the reflection of light, the water surface is like a mirror, and D is the imaging of small holes, which is the linear propagation of light.

I should choose C.

A and B should be considered as light propagating in a straight line, but D is not so clear, and the dense foliage is diffraction.

=h· (Light energy = Planck constant multiplied by frequency) h=

Choose BC The greater the photon frequency, the higher the energy ...... independent of light intensityThe ground state energy level of the hydrogen atom is so in order to ionize it must be irradiated by photons of the above energy

bc light energy e=h h is Planck's constant is the frequency of light, and the energy of photons is only related to the frequency of light.

The following statement is true: a

a.To BWrong, because it reflects all colors.

c.Clothing is red because it can only reflect red light.

d.The object is black because it cannot reflect any light.

ab.The clothes are white because they can reverse all colors of the honor roll.

c.Clothing is red because it reflects all light with wavelengths close to red (or absorbs green light).

d.An object is black because it does not reflect all color light (absorbs all color light).