Urgent!! Lines, etc!! How do you become scheming!!

Updated on society 2024-04-17
13 answers
  1. Anonymous users2024-02-07

    I advise you not to learn to be scheming, in fact, the twisted melon is not sweet, we often do not cherish the things we get by scheming, treat them sincerely, and will always live under careful pressure, afraid of being exposed. It's tiring to live like that, really. Of course, if you are too straightforward, it is inevitable to commit some people's taboos, I think you should learn to think, often people with more deep thoughts are more cautious, and they will think twice before doing things when they say and do things.

    The best way to become thoughtful is to allow yourself to think about some issues, and think deeply, such as life. In is to read a book, no matter what the book, reading is better than not reading, I personally like **poetry. In the end, you have to believe that not everyone in this world likes to live with scheming, after all, everyone yearns for a simple and comfortable life.

    We usually look at the chic people who are themselves with envy, what kind of people like what kind of people, what kind of people hate, are measured by the other party's heart, not with appearance, so I think you show your true self to make sincere friends, there are friends like this, what more can you ask for? Hehe, what do you say?

  2. Anonymous users2024-02-06

    Face both ways! I'm a boy, I've done this before, I have to be able to lie, lie in a circle, remember the lies I tell, and have to be left and right! It's very brain-training!!

  3. Anonymous users2024-02-05

    There's nothing wrong with being straightforward. You don't have to go with the flow, believe that this is not a shortcoming, and you don't have to deliberately change it, one day someone will find out your preciousness!

  4. Anonymous users2024-02-04

    It's normal for young people to suffer a little loss, and everyone actually doesn't like scheming people.

  5. Anonymous users2024-02-03

    zq52111 This guy is a badass, don't listen to him.

  6. Anonymous users2024-02-02

    1.Wrong.

    In the same plane, there is one and only one line parallel to the known line at a point.

    2.To 3This is clearly wrong.

    Two lines that intersect the same line do not necessarily intersect.

    Therefore: choose B

  7. Anonymous users2024-02-01

    The shadow area is 4 minus the distance traveled, and the bottom is 6 minus the distance 10 2 5 = 20 5 = 4 (cm).

    3 (cm) A: Translate 3 cm.

    Or: set the translation x cm.

    4-x+6-x)×5÷2=10

    10-2x)×5÷2=10

    10-2x=4

    x = 3 A: Translate 3 cm.

  8. Anonymous users2024-01-31

    Original formula = 2015a + 3tan60°-1 + (-2015a)-3 root number 3

    2015a+3 root number 3-1-2015a-3 root number 3=-1

  9. Anonymous users2024-01-30

    Quadrilateral area s=234

    Process: In RT ABC, ab=20, cb=15s abc=1 2*ab*cb=1 2*20*15=150 According to the Pythagorean theorem: AC= (ab 2+cb 2)= 20 2+15 2)=25

    In ACD, AD=24, CD=7, AC=25, and AD2CD2=AC2

    ACD is RT

  10. Anonymous users2024-01-29

    The angle b90° then ac can be found to be 25 using the Pythagorean theorem

    In a triangular ADC, the three sides are 7 24 squared + 24 squared = 25 squared, satisfying the Pythagorean theorem, so the triangle ADC is also a right triangle, and the angle d is 90°, so the area is s adc + s abc = 7 times 24 divided by 2 + 20 times 15 divided by 2 = 234

  11. Anonymous users2024-01-28

    Proof: Connect to the AC

    ab=20, bc=15, b=90°, from the Pythagorean theorem, ac2=202+152=625

    cd=7, ad=24, cd2+ad2=625, ac2=cd2+ad2, d=90°

    s△adc+s△abc=234

  12. Anonymous users2024-01-27

    a+b-c=0, so a+b=c --1)2a-b+2c=0 So Hoopey 2a-b=-2c --2)2)+(1) gets a simple trillion 3a=-c a=-1 3c: b=4 3c

    3a-2b+5c) (5a-3b+2c) = c-8 3c+5c) (5 3c-4c+2c) = -4 11 (c≠0).

  13. Anonymous users2024-01-26

    14、(1)a=2,b=1,c=3,d=2

    2) A (gas), B (solid or liquid), C (solid), D (gas).

    3) Exothermic. Solution: (1) In the same period of time of the same chemical reaction, the ratio of the quantities of the substances participating in the reaction is equal to the ratio of their measured numbers, so.

    a:b:c:d=n mol:n 2mol:3n 2mol:n mol=2:1:3:2, so the answer is: 2; 1;3;2.

    2) The pressure has no effect on the equilibrium state of the reversible reaction where the gas volume does not change before and after the chemical reaction, and according to the title, the gas volume does not change before and after the reaction.

    2A+B 3 C+2D, the product C is a solid, to make the volume of gas before and after the reaction unchanged, that is, the number of measurements is unchanged, then it can only be A, D is a gas, B is a liquid or solid, and the product C is a solid. So the answer is: gas; solid or liquid; Solid; Gas.

    3) increase the temperature and move the equilibrium in the direction of endothermy; According to the inscription, at the beginning of the reaction, the amount of substances A and B decreases, and the amount of substances C and D increases, so the equilibrium moves in the direction of the positive reaction. After increasing the temperature and reacting for a period of time, the amount of the substances of these four substances is measured to be equal, indicating that the equilibrium is moving in the opposite direction of the reaction, so the forward reaction is an exothermic reaction. So the answer is: exothermic.

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