A chemical trimming problem, a balancing chemical equation problem

Dizzy, you wrote it all wrong, and the back is n2o

We've just done this question, and I've memorized it all.

24 30 8 8 3, the h2o coefficient at the back, you can calculate it yourself.

The trim chemical formula is very simple, keep two things in mind:

1.Conservation of mass, that is, the total number of elements before and after the reaction is the same;

2.The valence is conserved, that is, the total valency before and after the reaction is the same.

This formula: 3FeSO4+4HNO3=FE2(SO4)3+FE(NO3)3+NO+2H2O

3feso4+4hno3=fe2(so4)3+fe(no3)3+no+2h2o

Just count whether the number of molecules of each element at both ends is the same.

Chemical Equation Trim Problem – Classic Example Problem.

1. Trim AL + FE3O4 FE + AL2O3

Step 1: Trim oxygen atom AL + 3FE3O4 FE + 4AL2O3

Step 2: Trim iron and aluminum atoms 8AL + 3FE3O4 9FE + 4AL2O3

Step 3: The chemical equation for the trim: 8AL + 3FE3O4 = 9FE + 4AL2O3

2. For example: Fe2O3 + CO - Fe + CO2

Therefore, 1 Fe2O3 should give 3 "O" to 3 CO respectively, so that it becomes 3 CO2.

i.e. Fe2O3 + 3Co – Fe + 3CO2

Observe the above equation again: there are 2 Fe (Fe2O3) on the left, so the coefficient of Fe on the right should be 2.

i.e. Fe2O3 + 3Co ==2Fe + 3CO2

This gives the chemical equation for the trim, note that the "-line" becomes the "== sign".

i.e. Fe2O3 + 3Co ==2Fe + 3CO2

3. Example: trim H2O + Fe Fe3O4 + H2

Step 1: Trim oxygen atom 4H2O + Fe Fe3O4 + H2

Step 2: Trim hydrogen atom, iron atom 4H2O + 3Fe Fe3O4 + 4H2

Step 3: The chemical equation after trimming: 4H2O + Fe ==Fe3O4 + 4H2

The charge is conserved, and the brackets are filled with hydrogen ions.

Atoms are conserved, chromium ions with 2, water with 4, hydrogen ions with 8

Dichromate ion + bromine ion + 8 hydrogen ion = = 2 chromium ion + bromate ion + 4 water check the three major conservations, no problem.

2kmNO4+16HCl (concentrated)=2KCL+2MnCl2+5Cl2+8H2O

10feso4+2kmno4+8h2so4=5fe2(so4)3+k2so4+2mnso4+8h2o

The age of Kai buried in the annual test is different, and there are fewer repetitions.

Once these three are paired, there will be no big problem.

Reaction of ferric tetroxide and dilute nitric acid.

Reaction of ferrous iodide and the same amount of chlorine.

Reaction of ferrous bromide and equal amount chlorine.

Turn left|Turn right (remember to adopt it).