Is the front wheel of a bicycle long or the rear wheel long? Why?

It's definitely different when you turn the bay.

You'll know when you actually ride the bike. Before you are slowing down, with the handlebars to the left (or right), let the bike turn in a circle. At this time, the front and rear wheels are basically concentric circles without considering the disturbance when you are driving unsteadily.

The front wheel is an outer circle, and the rear wheel is an inner circle. The linear velocity of the outer circle is significantly greater than that of the inner circle. But if you talk about angular velocity, it should be the same, if it's not the same, you fall.

Therefore, the angular velocity is the same, the linear velocity is the same, the stroke is different, and the stroke of the front wheel is greater than that of the rear wheel.

What is this title? So strange.

From the point of view of not turning, the distance, angular velocity, and linear velocity of the front and rear wheels are the same (provided that the front and rear wheels are the same).

If you turn a corner, it is not very clear, it should be the distance of the front wheel is larger than that of the rear wheel, and the linear speed and angular velocity should still be the same.

Since the rear wheels take a slightly smaller curve every time they turn, the front wheels must have taken a longer route.

As for angular velocity and linear velocity, if the front and rear wheels are the same size, due to the different distances traveled by the two wheels at the same time, of course, the angular velocity and linear velocity are not the same.

The linear speed is equal, but when riding, you need to constantly correct the direction to ensure balance, and the front wheel actually goes farther than the rear wheel.

In fact, the angular velocity is not the same. I don't remember how to analyze it, but there is rigorous scientific proof that in addition to static friction, the power of the bicycle is the energy generated by the angular velocity difference.

Hello! In the case that the front and rear wheels do not slip, the linear velocity of the front and rear wheels of the bicycle is the same, which is equal to the speed of the bicycle.

In fact, it is more correct that the speed of the bicycle is equal to the speed of the front wheel.

Because the rear wheels are the driving wheels, the driving wheels are easy to slip when the resistance is high. At this point, the speed of the bicycle is certainly not equal to the speed of the rear wheel.

The front wheels are passive wheels, and there is generally no slippage (except when braking), so the linear speed of the front wheels is equal to the speed.

It only represents a personal opinion, don't spray if you don't like it, thank you.

Because the chain of the bicycle is connected to the rear wheel, the speed of the rear wheel is calculated because the rear wheel is controlled when riding.

The number of front wheel revolutions of the bicycle is fixed, and the distance traveled is proportional to the circumference of the wheel.

1 is proportional 2 is inversely proportional 3 is not proportional 4 cannot be determined.

Solution: The distance traveled = the number of front wheel revolutions of the bicycle x the circumference of the wheel.

Then, the number of front wheel revolutions of the bicycle = the distance traveled The circumference of the wheel, because the number of front wheel revolutions of the bicycle is certain, therefore, the ratio of the distance traveled to the circumference of the wheel is certain. Under the premise of the same number of front wheel revolutions, the circumference of the front wheel is different for different bicycles, and the distance traveled is proportional to the circumference of the wheel.

If you don't understand, you can ask.

Because the circumference of the bicycle wheel is certain, the number of revolutions of the front wheel of the bicycle is certain, and the distance traveled is not proportional to the circumference of the wheel.

The front and rear wheels are the same big drop, that's the same 40 weeks, and if you want to ask how many centimeters this journey is, it should be.

28*40=centimeters are approximately equal to meters...

If you want to ask how many laps you need to walk on the rear wheel to walk a distance of 40 meters. That's 40*100 equals about 45 and a half laps.

3750 meters.

This is a variant of an engineering problem, and the topic should be understood as follows: bicycle tires can travel 5,000 meters when installed on the front wheels of Xiaoyan, and 3,000 meters when installed on the rear wheels. The ergonomics of the rear wheel is 1 3000, the ergonomic efficiency of the front wheel is 1 5000, and the two wheels cooperate to complete two projects, which is 2 (1 3000 + 1 5000) = 3750 (m).