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Need a reason?
Release an object at equal intervals If numbered 1, 2, 3, 4, 5, 6, 7....Words. Every object that is released from the ground looks like it's going to be thrown flat.
And their arrangement. Because the spacing time is the same. They are evenly spaced in horizontal positions.
The spacing in the vertical direction corresponds to the spacing of the free fall movement. So, taken as a whole, they form a parabola. It takes space for you to imagine that it shouldn't be difficult.
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The answer is b, d
I've considered A before you asked me, but the key point is that the word "arrangement" is ambiguous. The original option is "Arranged on a parabola", but in fact it is more accurate if it is "evenly arranged parabola".
"Aligned on a parabola" can be understood to mean that several objects are on the same parabola, which is wrong. Because each object is a separate parabolic trajectory, and these parabolic trajectories are evenly arranged. So I think A is wrong.
The description of the content of the question is not accurate, and it is difficult for students to determine whether it is the wrong choice or a different way of understanding.
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B and D are selected because after the object leaves the aircraft, it is thrown flat relative to the ground after the air resistance is not considered. The velocity of the object in the horizontal direction is equal to the speed of the aircraft, so the object will always remain relatively stationary with the aircraft in the horizontal direction. They are in the same straight line (and the line is perpendicular to the ground).
a, c exclusion.
The thrown object has a horizontal initial velocity relative to the ground, and is only affected by gravity, so it moves flat relative to the ground observer. Pick B
The thrown object has zero initial velocity in the horizontal direction relative to the aircraft, and only gravitational force is used, so it is in free fall relative to the aircraft. Pick D
So the answer is b, d
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Choose D because the object has inertia.
The airplane and the object begin to move together in a uniform linear motion, suppose the airplane releases an object 1 at position a, and when the airplane flies to position b, the object 2 is released, but at this time, object 1 still maintains its original motion state because of inertia, and object 1 also moves below position b, and so on.
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d I did this question in high school.
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Select b vertical displacement difference 1:3:5:7 horizontal uniform motion.
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Option B has the same velocity as the airplane in the vertical direction, so it moves horizontally synchronously.
In the vertical direction, the distance between two adjacent balls satisfies 1:3:5....
There is a certain difference in velocity between adjacent balls, so there will be a distance difference.
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After the ball is released, the speed of the aircraft is maintained in the horizontal direction of inertia, so after the release of each ball, it is done.
Flat throwing motion, the trajectory of which is:
Parabola.; The balls released successively are all directly below the plane, so their connection in the air is a straight line, c is correct.
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The ADA plane has a constant velocity, the time interval is equal, and the distance between the throws of each ball is also equal, so the landing should be equal to the Zen.
D small ball by gravity, plus the dust speed falls, at a certain moment, the first thrown ball falling speed is higher than the last falling ball rolled, the ball connected into an arc.
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Answer C Ideas and skills: Because the iron ball still maintains its original horizontal velocity after being released, it is synchronized with the plane in the horizontal direction, always directly below the aircraft, but due to the different times of the release of the 4 balls, the first release is below, and the later release is above, and the 4 balls are arranged in a vertical straight line under the aircraft, according to the judgment result, we exclude the two options of A and B, and only need to consider the iron ball in the horizontal direction to do a uniform linear motion between C and D, so the distance passed in the same time is equalSince the time interval between the release of the iron balls is 1 second, then the distance from their landing point should also be equal, and we exclude d
Comment: To answer this question, you need to master the following knowledge:
1) After the iron ball is released, it will move freely in the vertical direction, and the distance falling in the equal time interval is unequal (because it is a uniform acceleration motion), but the sub-motion state in the vertical direction will not affect the sub-motion state in the horizontal direction
2) The iron ball originally walked with the airplane and had the same horizontal velocity as the airplane After the iron ball was released, although it was separated from the airplane, it still continued to move in a horizontal uniform straight line with the same horizontal velocity as the airplane in the horizontal direction due to inertia, and the distance of horizontal motion in the same time interval was equal (because it was a uniform motion).
3) The time of the iron ball landing is determined by the height, but the horizontal distance of the landing is determined by the horizontal initial velocity and time Therefore, the iron ball that is released first lands first, and the iron ball released later lands later, but the distance between their landing points is equal (should meet the law of uniform linear motion in the horizontal direction).
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The problem is to look at the relative position of the four balls, not the trajectory of the individual balls. Their minute velocity in the horizontal direction is the same as that of an airplane. You can make up the scene of the bomber dropping the bomb in the Anti-Japanese War movie. The bombs were all lined up in a straight line.
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The partial velocity in the horizontal direction of each ball is equal to the velocity of the aircraft. So it looks like it's connected in a straight line.
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C test question analysis: an airplane flies horizontally at a constant speed, and an iron ball is released from the plane every 1 second, and the movement law of each ball is a flat throwing motion, therefore, in the airplane, it is always lined up in a vertical straight line directly below the plane at any time in the air, because an iron ball is released at an interval of 1s, so the interval between the landing points in the horizontal direction is equal, so the answer is c
Comments: This question examines the knowledge of flat throwing motion: the horizontal direction is a uniform linear motion, and the vertical direction is a free fall, which is solved according to the regular column.
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Answer C After the ball is released, because the inertia horizontally maintains the speed of the aircraft, after the release of each ball, it does a flat throwing motion, and its trajectory is parabolic; The Qingshenna balls released successively are all located directly below the plane, so their connection in the air is a vertical straight line, and the C answer is not correct.
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