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1 "When Tom continues to read the remaining half" - Tom reads 1 3 again
2 "When Xiao Ming continued to read the remaining half, Xiao Qiang read exactly half of the whole book" - Xiao Ming 2*1 3 is equal to Xiao Qiang's, Xiao Ming 1 3 is equal to Xiao Qiang's 1 4,3 "When Xiao Ming read 1 3, Xiao Qiang has 90 pages left unread" -Xiao Qiang's 3 4 is 90 pages, so the whole book is 120 pages.
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From "Xiao Ming continued to read the remaining half", Xiao Ming read the whole book again and got (1-1 3) 1 2 1 3, which also shows that Xiao Qiang's "two stages" read the same number of pages, so the book has a total of 90 (1-1 2 2) 120 (pages).
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360 pages, Xiao Ming reads the remaining (2 3) half is 1 3, and Xiao Ming can read 90 when he reads 1 3, and now Xiao Ming has read a total of 2 3 and Xiao Qiang is just half of 2 90 pages, that is, 180 times 2 = 360
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It's Wrong It's 120 90 pages are 3 4 I'm really sorry, my brother is out of sight, it's really 120 pages, and I seriously support this ......
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Harry Meteor - The Magician.
Do you want to see the topic first? There are 90 pages left unread. Rather than reading so much. Agree with joyceguting - probationary period level 1 for the same answer. 120
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According to the meaning of the title, we can get the equation relationship Chang Du is (Xiao Gang-1)-(Xiao Ming +1)=2. Therefore, it is possible to get Xiao Gang-Xiao Ming = 2 + 1 + 1 = 4, that is, there are 4 more books than him.
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According to the meaning of the problem, the equation is bumper (Xiao Gang-1)-(Xiao Ming-1)=2. Therefore, we can calculate Xiao Gang Xiao Ming as having four more books than he laughed at the spine.
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Solve the cover chain: set up a small just stuffy imitation x book, Xiao Ming y book.
x-1=y+1+2
x-1=y+3
x-y=4 Answer: Xiao Gang has 4 more books than Xiao Ming. Pure grandson.
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Summary. Hello classmates, the answer to this question is 9 books.
I'm Xiao Ming, Xiao Gang and I have read more than 4 books this year, we have read a total of 13 books, how many books Xiao Ming has read.
Hello classmates, the answer to this question is 9 books.
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40 (Ben) 40 4 = 10 (Ben).
Answer: Xiao Ming 40 copies, Xiao Gang 10 copies.
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If Xiao Ming gives all the books to Xiao Qiang, then Xiao Qiang has 27 more books than Xiao Ming, and Xiao Qiang's pants bring Xiao Ming 1 book, and Xiao Qiang has more books than Xiao Ming (27-1*2) = 25 books, so Xiao Qiang should give Xiao Ming (27-5) 2=11 books, so Xiao Ming gives 27-11=16 books.
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Xiao Gang gave Xiao Ming 1 book, and Xiao Gang had 2 more copies than Xiao Ming. We can solve this problem using an algebraic equation.
Assuming that the number of books in Xiao Ming's hand is x, then the number of books in Xiao Gang's hand is x+1, because Xiao Gang gave Xiao Ming 1 book.
According to the description of the title, Xiao Gang has 2 more books than Xiao Ming. Therefore, the number of books in Xiao Gang's hand should be 2 times the number of books in Xiao Ming's hand plus 1, that is, 2x+1.
We can set up an equation to represent this relationship:
2x+1=x+1
We can solve this equation to find the value of x, and thus get the number of books in Xiao Gang and Xiao Ming's hands.
Move x to the side of the equation and get:
2x-x=1-1
After simplifying, you get:
x=0, which means that the number of books in Xiao Ming's hand is 0. According to the description of the title, Xiao Gang has 2 more books than Xiao Ming, so the number of books in Liang Xiaogang's hand is 2.
Therefore, Xiao Gang has 2 more books than Oak Zhong Jian Xiaoming. Xiao Ming doesn't have any books in his hand, Pei Crack and Xiao Gang have 2 books. <>
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Summary. Xiao Ming A+9-2 A+7 Xiao Gang A+2
Xiao Ming has 9 more books than Xiao Gang, and if Xiao Ming gives Xiao Gang 2 books, Xiao Ming will have a few more books than Xiao Gang.
You know, teacher.
Dear, hello, it's a pleasure to tutor you in your study Xiao Ming has four more books than Xiao Gang.
How do you figure it out?
It's more than five Benha.
One person gives two copies, and the other person has 2 more, so the difference is 4 copies.
Then, 9-4=5 so there are five more.
I don't understand the teacher, can you be specific, an analogy is also OK, <> pro, this topic can be used as an analogy, for example, Xiao Gang is a book, then Xiao Ming is A+9 Xiao Ming A+9-2 A+7 Xiao Gang A+2
a+7-a-2=5
Dear, now I can understand.
I see.
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The book has a total of x pages.
The first time: When Xiao Qiang reads 1 4 of the whole book, Xiao Ming still has 240 pages left to read, so Xiao Ming finished reading page X-240.
The second time: When Xiao Qiang finished reading the remaining 4 5, that is, he finished reading (1-1 4)*4 5x pages, and Xiao Ming still had 8 25 left to read, then Xiao Ming read (1-8 25)x-(x-240) pages(1 4x): [1-1 4)*4 5x]=(x-240):[1-8 25)x-(x-240)]
Solution x = 300 pages.
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Hello: Xiaoqiang read it for the second time: (1-1 4) 4 5 = 3/5 is the first time: 3 5 1 4 = 12/5
Xiao Ming reads twice: 1-8 25=17 25
Xiao Ming read it for the first time: 17 25 (12 5+1)=1 5 This book is total: 240 (1-1 5)=300 pages, I wish you good luck!
If you have any questions, please ask, please adopt in time if you understand! (*
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This book has X pages, and Xiao Qiang and Xiao Ming's reading speed remains the same.
When Xiao Qiang read 1 4 of the whole book, Xiao Ming looked at the X-240 and read (1-1 4) 4 5 = 3 5 for the second time, which is 3 5 divided by 1 4 = 12 5 times the first time. Xiao Ming should have looked at 12 times 5 times (x-240) for the second time. Xiao Ming read 17 5 times (x-240) twice as the whole book (1-8 25), ie.
17/5 × x-240)=(1-8/25)xx=300
A good book is really from thick to thin and then from thin to thick in repeated reading. If we want to get to the bottom of it, we have to work hard. is also looking at the Three Kingdoms and the Dream of Red Mansions, and you can often see different connotations every time. That's where the joy of reading comes in.
Calculate according to the proposition (18+25) 2+18
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