What substances are both oxidizing and alkaline, and react with concentrated HCl to form Cl2

1st Floor: MNO2 is basically an acidic oxide. At high temperatures, there is.

Mno2 + 2koH(L) = (high temperature) K2Mno3 + H2OUnder this condition, K2Mno3 is very unstable and is easily oxidized by O2:

After the addition of 2K2Mno3 + O2 = 2K2Mno4, it is the first step in the industrial preparation of KMno4 using Mno2 as raw material.

2nd floor: Cu and concentrated HCl reaction does not release Cl2, thank you.

Back to the landlord, it should be clo-.

clo- is alkaline:

Clo- +H2O = (reversible) HClo + Oh- and has strong oxidation regardless of the acidity or alkalinity of the solution:

3clo- +i- +h+ = 3Cl- +HIO33clo- +i- = Cl- +io3- (basic or neutral) The above two reactions require clo- excess).

It is precisely because of this oxidation that the reaction with concentrated HCl can release Cl2:

clo- +cl- +h+ = cl2 +h2o, in fact, generally as long as hcl is not too diluted, it can be reacted)

Of course, clo2- can also be ......

Copper can be alkaline, and reacts with concentrated hydrochloric acid to produce copper chloride and chlorine gas.

Sodium hypochlorite and calcium hypochlorite are common. This thing is alkaline because of hydrolysis. And hypochlorite has strong oxidizing properties.

This is the composition of bleaching powder. Chlorine gas is produced by reacting with concentrated hydrochloric acid. There is not even a need for concentrated hydrochloric acid.

and chloride ions react under acidic conditions to form chlorine gas. So bleaching powder cannot be mixed. It is to prevent hypochlorite in different bleaching powders from reacting with chloride ions to form chlorine gas and cause poisoning.

A is a particle made up of 5 nuclei. Then it's easy to think that it could be NH4+ 10 electrons

So the reaction of A+B=C+D is likely to be the reaction of NH4+ +OH- == NH3 + H2O

d can react with most acidic oxides and basic oxides, so d can be judged to be h2o

Then c is NH3

Then b+e=2d is oh- +h3o+ == 2h2o

Water reacts with acidic oxides to obtain the corresponding acids (except SiO2).

Water reacts with alkaline oxides to obtain the right alkali (only a few alkaline oxides can be).

There is no change in chemical bonds in this reaction, Cl in Cl2O7 is +7 valence, and Cl in the resulting salt should also be +7 valence.

CO2 + 2OH - = CO3 [top right 2-] + H2O found C always +4 valence.

Similarly, CL should be +7 valence.

Cl2O7 + 2Oh- = 2ClO4- + H2O anion ClO4-

Chemical formula. cl2o7 + 2naoh =2naclo4 +h2o

The so-called acidity in chemical reactions refers to the reaction with alkali to form salts and water.

For example, Al(OH)3 reacts with sodium hydroxide and shows acidity:

Al(OH)3 + OH(-)ALO2(-)2H2O is the same way, and it reacts with acid to form salt and water, which is alkaline

Al(OH)3 + 2H(+)Al(3+) 3H2O is said to show oxidation in chemical reactions, which means that there are elements in the compound, and the valence and attitude of the modified value pose are reduced.

Such as nano2 reaction with fecl2 hydrochloric acid solution:

The valency of NO2(-)Fe(2+) 2H(+)NO+ Fe(3+) H2ON changed from +3 to +2, so it showed oxidation.

Similarly, if the chemical reaction shows reducibility, it means that the valency of the elements in the compound has increased.

For example: 5NO2(-)2MNO4(-)6H(+)2MN(2+) 5NO3(-)3H2O

where the valency of n changes from +3 to +5, so no2(-) shows reductivity.

Naclo disproportionates into NaCl and Naclo3 in a hot base, not NaCl and Naclo2, equation.

What kind of rough spelling you are wrong should be:

3naclo=2nacl+naclo3

One chlorine increased from +1 valence in clo(-) to +5 valence in Naclo3, and two chlorines decreased from +1 valence in clo(-) to -1 valence in Nacl, and the total number of electrons transferred was 4.

Thus, we can guess that Naclo2 also disproportionates into NaCl and Naclo3 in hot bases:

3naclo2

nacl2naclo3

Among them, 2 chlorines increased from the +3 valence of Clo2(-) to the +5 valence of Naclo3, and 1 chlorine decreased from the +3 valence of Clo2(-) to the -1 valence of NaCl, and the total number of transferred electrons was also 4

The Cl element undergoes a disproportionation reaction, and a part of the Cl element drops to the lowest price (it can be understood that the Cl element is lowered to +1 first, and then the Cl with +1 valence is sent to Yousensheng to tell Hongying, and the friend book is then reduced to -1).

So 3NaClO2 = 2NaCl+NaCl3

The Cl element undergoes a disproportionation reaction, and a part of the Cl element is reduced to the lowest valence (it can be understood that the friend book is lowered to +1 first, and the Cl with +1 valence is then revived, and then it is reduced to -1).

So 3NaClO2 = 2NaCl+NaCl3

Naclo disproportionates into NaCl and NaClO3 in a hot base, not NaCl and NaClO2, the equation you wrote wrong, it should be: 3NaCl = 2NaCl + NaClO3. One chlorine increased from +1 valence in clo(-) to +5 valence in Naclo3, and two chlorines decreased from +1 valence in clo(-) to -1 valence in Nacl, and the total number of electrons transferred was 4. Thus, we can guess that Naclo2 also disproportionates into NaCl and Naclo3 in hot bases:

3NaClO2 ==NaCl + 2NaClO3 where 2 chlorines rise from +3 valence in ClO2(-) to +5 valence in Naclo3, and 1 chlorine decreases from +3 valence in ClO2(-) to -1 valence in NaCl, and the total number of transferred electrons is also 4

The Cl element undergoes a disproportionation reaction, and a part of the Cl element is reduced to the lowest valence (it can be understood that it is lowered to +1 first, and then the +1 valence Cl reacts again, and then it drops to -1), so 3NaClO2=2NaCl+NaClO3

There is no violation. In this reaction, the chlorine element.

From 0 valence (Cl2) before the reaction to -1 valence (HCL) and +1 valence (HCl) after the reaction, Cl2 is a reducing agent even if it is an oxidizing agent.

HCl is a reduction product, and HCl is an oxidation product. According to the oxidation of the oxidant agent is greater than the oxidation of the oxidation product, the oxidation of Cl2 is greater than that of HCl.

in redox reactions.

When judging the strength of oxidation or reduction, it is necessary to correctly find out the oxidant, oxidation products, and reduction products.

Do not violate. Chlorine is an oxidizing agent and hypochlorous acid is an oxidation product. The oxidizing properties of chlorine gas are much greater than those of hypochlorous acid.

Analyzing the rise and fall of valence, it can be found that the oxidant and slippery reducing agent here are chlorine, and the oxidation product is hydrochloric acid, and the oxidation of hydrochloric acid is weaker than that of chlorine. Fe+2HCl==FeCl2+H2 Fe2 valence.

2Fe + 3Cl2 = Ignition = 2FeCl3Fe3 valence.

By comparing the degree of chlorine and hydrochloric acid to the degree of iron-oxygen mountain calming, we can know the degree of oxidation of the two.

The reducing product is hypochlorous acid, which is weaker than chlorine, that is, chlorine with stronger oxidation than the reducing agent.

a sodium oxide is an oxide, and the reaction with acid only produces sodium salt and water, such as the reaction with hydrochloric acid to form sodium chloride and water, which is an alkaline oxide, so a is wrong;

B Na2O2 reacts with acid to form sodium salt, water and oxygen, which is a peroxide, not a basic oxide, so B is correct;

c Sodium reacts with acid to form sodium salt and hydrogen, and sodium is a metal element, so c is wrong;

d Copper oxide reacts with acid to form copper salt and water, and it is an alkaline oxide, so d is wrong;

Therefore, choose B