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Place a button and 2 textboxes in the form, enter information in text1 during runtime, and see the output result in text2 after clicking the button.
private sub command1_click()dim sfor i = 1 to len(text1)n = asc(mid(text1, i, 1))if n >= asc("a") and n <= asc("z") then s = s & chr(n - 32) else _
if n >= asc("a") and n <= asc("z") then s = s & chr(n + 32) else s = s & "*"
nexttext2 = s
end sub
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Just add a textbox
Then you can type it directly in it to see the effect.
private sub text1_keypress(keyascii as integer)
if keyascii >= 97 and keyascii <= 122 then
keyascii = keyascii - 32elseif keyascii >= 65 and keyascii <= 90 then
keyascii = keyascii + 32elsekeyascii = 42
end if
end if
end sub
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Try mine! Add a text control to the form and write the following under its keypress event
private sub text1_keypress(keyascii as integer)
select case keyascii
case 97 to 122: keyascii = keyascii - 32 'lowercase to capital
case 65 to 90: keyascii = keyascii + 32 'capital to lowercase
case else: keyascii = asc("*") 'else all out "*"
end select
end sub
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Add a text box.
dim m, i, n as stringprivate sub text1_keypress(keyascii as integer)
m = cstr(keyascii)
if m >= 65 and m <= 90 thenm = m + 32
n = chrw(m)
print n;
elseif m >= 97 and m <= 122 thenm = m - 32
n = chrw(m)
print n;
elseprint "*";
end if
end if
end sub
If you don't understand, or can't come to me. )
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Help me write a program! It's urgent!!
Bounty Points: 30 - 14 days and 23 hours until the end of the question.
Write an automatic conversion program for uppercase and lowercase letters, which will automatically convert to uppercase letters when entering lowercase letters, automatically convert to lowercase letters when entering uppercase letters, and display "*" when entering other characters
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I'm still doing my homework so late.
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Solution: Let a be x, then b is 40 x.
There are two schemes: 7x 3 (40 x) 226 and 4x 10 (40 x) 250
From equation 1: x, that is, the wild mill sum is 26 whole pieces, and the tomato needs 224kg A and 244kg B;
From Equation 2: x 25, A needs 226kg, B 250kg;
That is, the solution of A26 pieces and B14 pieces is good, because the task is completed and the raw materials are saved, and the cost will be low.
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