Isothermal, isobaric, equal mass H2, D2, T2

Updated on Car 2024-04-22
11 answers
  1. Anonymous users2024-02-08

    The ratio of protons is 1:1:1

    The ratio of neutrons is 0:1:2

    These two are for the H2, D2, T2 molecules alone. Since the number of molecules is 6:3:2, the ratio of the total number of protons of these gases is 6:3:2 and the ratio of the number of neutrons is 0:3:4.

    Density ratio 1:2:3

    The ratio of volume is 6:3:2

    This is true only when it is considered to be an ideal condition, in a gaseous state.

  2. Anonymous users2024-02-07

    Upstairs: The ratio of protons to the number of neutrons is miscalculated!

    Answer] Let h2, d2, t2 have the mass of m, then n(h2) : n(d2) : n(t2) = m 2 : m 4 : m 6 = 6 : 3 : 2.

    1)d(h2) :d(d2) :d(t2) = m/6 : m/3 : m/2 = 1 : 2 : 3。

    2) The ratio of the number of protons = 2*6 : 2*3 : 2*2 = 6 : 3 : 2.

    3) Ratio of neutrons = 0*6 : 2*3 : 4*2 = 0 : 3 : 4.

    4)v(h2) :v(d2) :v(t2) = n(h2) :n(d2) :n(t2) = 6 : 3 : 2

  3. Anonymous users2024-02-06

    Density ratio 1:2:3

    The ratio of protons is 1:1:1

    The ratio of neutrons is 0:1:2

    The ratio of volume is 6:3:2

  4. Anonymous users2024-02-05

    Nitrogen is considered an ideal gas.

    The amount of N2 is n=, the pressure P1=P2=1ATM=101325Pa, the initial volume v1=Nrt1 P= , T1=300K The final state volume v2=2V1=, T2=P2V2 (NR)=101325*Isobaric expansion, the pressure is constant, then the work done by nitrogen w=-p*δv=-101325* (the internal energy of an ideal gas is only related to temperature, the molar isocapacitance heat capacity of a diatomic rigid gas molecule cv,m=

    So the change in internal energy is δu=ncv, mδt=

    According to the first law of thermodynamics, q=δu-w=

  5. Anonymous users2024-02-04

    n=, t1=300k, p=1atm= pa, v2=2v1, r= j/mol/k, cv=5/2r

    v1=nrt1 p= m 3, w=p(v2-v1)= *v1 j isobaric process v1 v2=t1 t2,t2=600kdeltau=n(cv)deltat= r(600-300) j,q=n(cp)deltat= r+r)(600-300) j, which can also be calculated by q=deltau+w.

  6. Anonymous users2024-02-03

    d.The molar mass (g mol) of the three substances is h2:2, d2:4, t2:6;

    The inscription says: If there are three gases of equal mass H2, D2, and T2, then this mass can be set to be 12g

    Then the quantities of H2, D2 and T2 are 6, 3 and 2 mol. respectively

    According to Avogadro's law: isothermal, isobaric silver milling, the ratio of the quantity of the gas = the volume ratio.

    Therefore, the volume ratio is staggered.

    The proton number of the two of the equal mass is the same, so the proton number of H2, D2, and T2 of the same mass is paired.

    The number of neutrons is 0, 1, 2, so the ratio of the number of neutrons is 0 6:1 3:2 2 = pairs.

    Density = m vSince m have the same beat, the density ratio = the reciprocal ratio of the volume = 1:2:3, a pair.

  7. Anonymous users2024-02-02

    H2 relative molecular mass = 2, proton number = 2

    D2 relative molecular mass = 4, proton number = 2

    T2 relative molecular mass = 6, proton number = 2

    At the same temperature and pressure, the amount of H2, D2, and T2 of the same substance is equal (Avogadro's law).

    So the ratio of the number of protons = 1:1:1

    Ratio of masses = 2:4:6 = 1:2:3

  8. Anonymous users2024-02-01

    Nitrogen is considered an ideal gas.

    The amount of N2 is n=, the pressure p1=p2=1atm=101325Pa, and the initial volume v1=nrt1 p=

    t1=300k

    The final state volume v2=2v1=, t2=p2v2 (nr)=101325* isobaric expansion, the pressure does not change, then the work done by nitrogen w=-p*δv=-101325* (the internal energy of an ideal gas is only related to temperature, the molar isocapacitance heat capacity of a diatomic rigid gas molecule cv, m=

    So the change in internal energy is δu=ncv, mδt=

    According to the first law of thermodynamics, q=δu-w=

  9. Anonymous users2024-01-31

    Set all of them to 1 gram.

    Then H2 is 1 2mol, D2 is 1 4mol, T2 is 1 6mol density ratio is the reciprocal of the volume ratio, that is, the reciprot ratio of the molar ratio, and the proton number ratio is 1:2:3 in the same potato round type as 1:2:3

    The neutron ratio is 0:3:4 (simplified from 0:1 2:2 3).

  10. Anonymous users2024-01-30

    Ideal gas equation: PV = NRT. There are 4 variables in this equation:

    p refers to the pressure of the ideal gas, v is the volume of the ideal gas, n represents the amount of gaseous substance, and t represents the thermodynamic temperature of the ideal gas (unit Kelvin), r is a constant and can be ignored, both sides of the equation are multiplied by , that is, mp=nt *r, so when p and m are the same, n is inversely proportional to , let o2, o3, n2h4 mass is 96g, that is, o2, o3, n2h4 substances are 3mol, 2mol, 3mol, so the density ratio is 2:3:2, Because the mass is the same, then the volume ratio is 3:

    2:3, the ratio of protons to 1:1:

    1, the ratio of neutron numbers is 8:8:7 (hydrogen atoms have no neutrons), pure hands to fight tiring. Hope.

  11. Anonymous users2024-01-29

    Under the same conditions, the ratio of density is equal to the ratio of relative molecular mass, and the ratio of H2D2T2 gas of equal mass is 1H2 and 2H2

    And. H2 three gases, the ratio of the density of the gas is = 2:4:6 = 1:2:3, so it is correct;

    If the isomass is assumed to be 2g, then h2d2t2

    Amount of gaseous substance = 2

    6:3:2, the number of protons in the molecule is the same, so the ratio of the number of protons is 6:3:2, so it is correct;

    The equal mass is assumed to be 2g, and the jujube guess is h2d2t2

    Amount of gaseous substance = 2

    6:3:2, the number of neutrons is , so the number of neutrons in the three substances of equal mass is 0 6:3 2:2 4=0:3:4, so it is correct;

    If the mass of the stool is assumed to be 2g, then h2d2t2

    Amount of gaseous substance = 2

    6:3:2, under the same conditions, the ratio of the volume of the gas particle is equal to the ratio of the amount of matter = 6:3:2, so it is correct;

    So choose A

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