Chickens and rabbits are surrounded by 316 of the first 100 feet. How many chickens and rabbits are

Solution: Suppose there are x chickens and (100-x) rabbits.

2x+4(100-x)=316

2x+400-4x=316

4x-2x=400-316

2x=84x=42

Rabbit = 100-x = 100-42 = 58 pcs.

A: There are 42 chickens and 58 rabbits.

There are x chickens and (100-x) rabbits.

2x+4(100-x)=316

x = 42 rabbits have (100-x) = 100-42 = 58 rabbits.

Hope it helps, I hope you click"Satisfactory answer"

If there are x chickens, then there are 100-x rabbits.

2x＋4（100-x）＝316

That is, the sum of the chicken's feet and the rabbit's feet is equal to 316

Solution: Suppose there are x chickens and (100-x) rabbits. 2x+(100-x)*4=316 x is 42, (chicken), (100-x) is 48, there are 42 chickens, and there are 48 rabbits. Give a good review.

Set chicken x rabbit y chicken plus rabbit is equal to 100, two chicken plus four rabbits is equal to 316

36 4 = 144 articles.

144-96 = 48 imitations.

4-2=2 strips.

48 2 = 24 ......Chicken Void Kai.

36-24 = 12 ......Rabbit.

I hope mine can help you in your filial piety.

The rooster and the rabbit Feng Hongzi both raised one foot, and there were 86-30 = 56 feet on the ground, and then they both raised one foot, and there were 56-30 = 26 feet on the book of the silver friends, all of which were rabbit's feet, and the rabbit had 26 2 = 13, and the chicken had 30-13 = 17.

There are x chickens.

There are (100-x) sheltered rabbits.

2x+4(100-x) = 316

2x+400-4x=316

2x=400-316

2x=84x=42

So there were 42 chickens and 58 rabbits.

100x2=200 (only).

316-200=116 (only).

Rabbits: 116 (4-2)=58 (only).

Chicken or macro draft absolute ant: 100-58 = 42 (only) shirt filial piety.

Solution: Suppose there are x chickens and (100-x) rabbits.

2x+4(100-x)=316

2x+400-4x=316

4x-2x=400-316

2x=84x=42

Rabbit = 100-x = 100-42 = 58 pcs.

A: There are 42 chickens and 58 rabbits.

If there are x chickens, then rabbits have 100 x 2x 4 (100 x) 310 solutions get x 45. No equation method: (the practice in ancient Chinese mathematical works is also known as the chopping method) so that the fading of chickens and rabbits is reduced by half, so that there are a total of 155 fading, one chicken and two rabbits, so if they are all chickens, it is a hundred fading, of which one more leg is one more rabbit.

So there are 155 100 55 rabbits, and 45 chickens.

Arithmetic method: 100 times 2 = 200 (feet).

316-200 = 116 (feet).

116 divided by 2 = 58 (only).

100-58=42 (only).

Rabbits have 58 and chickens have 42

Solution: Suppose there are x rabbits and (100-x) chickens.

4x+2(100-x)=316

4x+2*100-2x=316

4x-2x+200=316

2x+200=316

2x=316-200

2x=116

x=116/2

x=58 100-58=42 (only).

A: There are 42 chickens and 58 rabbits.

Let the chicken be x and the rabbit be y

2x+4y=316 x+y=100 (2 is the chicken's foot, 4 is the rabbit's foot).

y=58x=42

Both the rooster and the rabbit have one foot up, and there are 86-30 = 56 feet on the ground, and then one foot on the ground, and there are 56-30 = 26 feet on the ground, all of which are rabbit's feet, and the rabbit has 26 2 = 13, and the chicken has 30-13 = 17.

Suppose there are x chickens and y rabbits.

According to the topic: x+y=30 x+y=30 (1) (2)--(1)formula2x+4y=86 x+2y=43 (2).

y=13 Substituting the y value into (1) x=17Answer: There are 17 chickens and 13 rabbits in the cage.

Set chickens x and rabbits (30-x).

2x+（30-x）×4=86

2x+120-4x=86

2x+120=86

2x=34 chickens: x=17

Rabbit: 30-x=13

A: 17 chickens and 13 rabbits.

Using the equation to solve, there are 12 rabbits and 18 chickens.

Free 13 chickens 17 so, rabbits have 13 chickens have 17

Solution: If there are x chickens, then there are 100-x rabbits, then there are 2x chicken feet, and there are 4 (100-x) rabbit feet 2x+4 (100-x) 316

2x+400-4x＝316

2x＝84x＝42

Rabbit 100 42 58

Or maybe it's a chicken-rabbit cage problem. Assuming that 100 are all chickens, then there should be 100 2 = 200 legs, but because some of them are rabbits, they actually have 316 legs.

The extra 316-200 = 116 feet is because the rabbit (4 legs) has two more feet than the chicken (2 legs). Each extra rabbit has 2 more legs, so the number of rabbits is.

116 2 = 58 pcs.

Then the number of chickens is.

100-58=42 (only).

This question can also be set to all rabbits, then it can be columnar.

The number of chickens is. 4 100-316) 2=42.

The number of rabbits is:

100-42=58 pcs.

1.If there are x chickens, then there are 100-x rabbits, then there are 2x chicken feet, and there are 4 (100-x) rabbit feet.

2x+4×（100-x）＝316

2x+400-4x＝316

2x＝84x＝42

Rabbit 100 42 58

Or. Hypothetical method.

Let's say it's all chickens.

Number of rabbits (316-2*100) (4-2)=116 2=58.

Chicken. 100-58=42 (only).