If students of a school hold a spring outing, they rent a 45 seater bus

First question: Because you rent the same number of cars, you can seat 60-45 = 15 more people per car.

The second type of car has 60 seats left in the empty car, and the first type of car has 15 fewer seats, so the number of cars to rent is (60+15) 15=5

So the number of students in the school is (5-1)*60=240.

The second question: there is a problem with the question, the rent of 45 seats should be 220 yuan, because the average of the two kinds of cars is close to each seat, and relatively speaking, the 45-seat car is cheaper, so if it is the cheapest, two conditions need to be met: 1

There are no empty seats; 2.Try to choose a 45-seater car.

Choose 4 cars with 45 seats and 1 car with 60 seats, and the required rent: 4 * 220 + 300 = 1180 yuan.

There are x students in total, x 60) + 1 = (x-15) 45

x=240 If you rent a 60-seater bus, you need: 240 60 = 4 cars, cost: 300 * 4 = 1200 yuan If you rent a 45-seater bus, you need:

240 45 = 5 + (15 45), should rent 6 cars, cost: 220x6 = 1320 yuan but: 4x45 + 60 = 240, so, 4 45-seat passenger cars, plus 1 60-seat passenger car, cost:

220 * 4 + 300 = 1180 yuan.

This last option is the most economical.

Solution: Set the number of rental cars to x.

45x+15=60(x-1)

45x+15=60x-60

45x-60x=-60-15

15x=-75

x=5, so there are 45x+15=45*5+15=240 people.

If you rent a 45-seater car, the cost is: 220 * 6 = 1920 yuan.

If you rent a 60-seater car, the cost is: 300 * (5-1) = 1200 yuan.

If you rent 4 45-seater cars and 1 60-seater car, the cost of dismantling is 220 * 4 + 300 * 1 = 1180 yuan.

Therefore, it is most economical to rent 4 45-seater cars and 1 60-seater car.

Set up to rent x penitential buses.

then 45x+15=60x-60 x=5

This school has students 5*45+15=240

Rent a 45-seater bus State Orange bus, rent 4 cars in Bijiyin.

60-seater bus, rent 1 car.

It costs exactly 220*4+300=1180

Solution: (1) Set up a passenger car with x 45 seats, and get 45x=60(x-1)-30 according to the problem to get x=6

A: The number of students participating in the spring outing at the school is 270.

2) Set up a rental of 45-seater passenger cars x cars, then rent 60-seater passenger cars (x+1) vehicles, by the title:

If you need to rent a 45-seater passenger car separately, you need 270 45 = 6 cars, and the rent is 250 6 = 1500 yuan, if you need to rent a 60-seater passenger car separately (270 + 30) 60 = 5 cars, the rent is 300 5 = 1500 yuan, then there is.

250x+300(x+1)＜1500

45x+60(x+1) 270, solution: 2 x 24 11, x is a positive integer, x=2 is to rent 2 45-seat passenger cars, 3 60-seat passenger cars, at this time the rent is: 250 2 + 300 3 = 1400 (yuan).

Let the number of cars be x, 45x+15=60*-60, get x=5, then the number of people is: 60*4=240 people.

There are x students in total, x 60) + 1 = (x-15) 45

x = 240 people.

If you rent a 60-seater bus, you need: 240 60 = 4 cars, cost: 300 * 4 = 1200 yuan.

If you rent a 45-seater bus, you need: 240 45 = 5 + (15 45), you should rent 6 cars, cost: 220x6 = 1320 yuan.

But: 4x45 + 60 = 240, so, 4 45-seat buses, plus 1 60-seat bus, cost: 220 * 4 + 300 = 1180 yuan.

This last option is the most economical.

1) If there are 45 ground cars x cars, then 60 seats will be obtained from the question and there will be (x-2) cars 45x+30=60*(x-2).

Get x = 10 so there are 480 people on the first day of junior high school, and the original plan is to use 10 cars with 45 seats 2) Set up 45 seats with ground rent x cars and 60 seats y cars, and the total rent w yuan is required 45x + 60y = 480

w=220x+300y

When x=8 y=2, w has a minimum value of =2360

（1.Set 45 seats for x cars.

45x-30=（x-2）*60

x=6 for 45x-30=240 people

2）.Three methods:

1.All 60 seats: 240 60 300 = 4 300 = 1200 (yuan) 2

All 45 seats: 240 45 = 5 (cars)...15 (persons), 6 cars:

5+1) 220=1320 (yuan).

3 Mixed: 1 car 45 seats 4 x 60 seats (not possible) becomes: all 60 seats (as above) 2 x 45 seats 3 x 60 seats:

2 220 + 3 300 = 13403 45 seats 2 60 seats: 3 * 220 + 2 * 300 = 12604 cars 45 seats One 60 seats: 4 220 + 300 = 11205 cars 45 seats 1 car 60 seats:

5 * 220 + 300 = 1400 A: 4 cars with 45 seats and one car with 60 seats are the most cost-effective.

1) If there are 45 ground cars x cars, then 60 seats will be obtained from the question and there will be (x-2) cars 45x+30=60*(x-2).

Get x = 6 (cars).

6-2) 60=240 (person).

2) All 60 seats: 240 60 300 = 4 300 = 1200 (yuan) All 45 seats: 240 45 = 5 (vehicles).15 (person) (5+1) 220=1320 (yuan).

Mixed: 4 cars with 45 seats, one 60 seats, 4 220 + 300 = 1120 (yuan) Answer: 4 cars with 45 seats, one 60 seats The most cost-effective.

(1) Set up to rent x vehicles.

45x-30=60x-120

90=15x

x = 6 six cars.

6 45-30 = 240 (person).

2) All 60 seats: 240 60 300 = 4 300 = 1200 (yuan) All 45 seats: 240 45 = 5 (vehicles).15 (person) (5+1) 220=1320 (yuan).

Mixed: 4 cars with 45 seats, one 60 seats, 4 220 + 300 = 1120 (yuan) Answer: 4 cars with 45 seats, one 60 seats The most cost-effective.

1...Let the 45-seater car be x, and the title will give 45x-30=(x-2)*60 x=6, and the number of people will be 45x-30=240

2...45 passenger cars 6 60 passenger cars 4 The price of 45 by the question is 1320 yuan 60 The price is 1200 yuan So 45 passenger cars should be rented.

1.The number of students is 480,, 10 cars.

2.The first option rents 10 45-seater buses at a cost of 2,200

The second type rents 8 60-seater coaches and costs 2400Obviously, the first option is more cost-effective.

There were a total of 240 people, and they originally planned to rent 6 taels. Rent 4 taels of 45 seats, a 60 seats is the most cost-effective.

Number of car rentals: (60+15) (60-45).

5 (car) students have: (5-1) 60

240 (person).

As can be seen from the rent, it will be cheaper to rent a 45-seater coach as much as possible:

So it is most cost-effective to rent 4 45-seater buses and 1 60-seater bus:

1180 (yuan).

A: There are 240 students in this school. (2) It is most economical to rent 4 45-seater buses and 1 60-seater bus.

Number of car rentals: (60+15) (60-45).

5 (car) students have: (5-1) 60

240 (person).

As can be seen from the rent, it will be cheaper to rent a 45-seater coach as much as possible:

So it is most cost-effective to rent 4 45-seater buses and 1 60-seater bus:

1180 (yuan).

A: There are 240 students in this school. (2) It is most economical to rent 4 45-seater buses and 1 60-seater bus.

Solution: Set up this school to rent x cars.

45x+15=60x-60

15x=-75

x = 55 45 + 15 = 240 people.

A: There are 240 sixth-grade students in this school.

Renting 4 cars with 60 seats requires a rent of 300 4 = 1200 yuan.

Renting 6 cars with 45 seats costs 220 6 = 1320 yuan. Therefore, it is most economical to rent 4 cars with 60 seats.

If there are x cars with 45 seats, there are 15 people without seats.

45x+15=60*(x-1)

15x=75

x=5x=5, number of people: 45 * 5 + 15 = 240220 45 =, 300 60 = 5 >, try to rent more 45 passenger cars cost-effective.

60 * 1 = 240, renting 4 45-seater buses, 1 60-seater bus is the most economical.

The total number of people is 240

4 buses with 60 seats are required to rent a capital of 1200

Rent 3 60-seater buses, 2 45-seater buses, capital 900 + 440 = 1340 rent 2 60-seater buses, 3 45-seater buses, capital 600 + 660 = 1260 rent 1 60-seater bus, 4 45-seater buses, capital 300 + 880 = 1180 rent 0 60-seater buses, 6 45-seater buses, capital 1320 with 1 60-seater bus, 4 45-seater buses, capital 300 + 880 = 1180 is the most economical.

What are you asking for? If that's what I'm thinking.

Solution: There are x buses.

60x-60=45x+15

60x-45x=15+60

15x=75

x=5 students: 5x60-60=240

Passenger cars are: (60 + 15) (60-45) = 5 (units).

Students have: 45*5+15=240 (people).