Unary 2nd order equation, don t know how to solve it, help down!

x(x+80)=18000

x squared + 80x = 18000 (resquared).

x+40) = 19600 (open squared).

x+40 = plus or minus 140

So x1 = 100 x2 = -180

Get x2 + 80x - 18000 = 0

Multiplication of crosses yields (x+180) (x-100)=0

So x1 = -180 and x2 = 100

x(x+80)=18000

x^2+80x-18000=0

x+40)^2=18000+1600

The absolute value of x+40 is 140

This yields x=100 or -180

1).5x²-1-4x=0,(5x+1)(x-1)=0,x1=-1/5,x2=1 5(x^2-4/5x)=,x-2/5)^2=9/25,x1=-3/5+2/5=-1/5,x2=3/5+2/5=1,(2)x²+2x+1=4,x²+2x-3=0,,(x+3)(x-1)=0,x1=-3,x2=1 (x+1)^2=4,x1=-2-1=-3,x2=2-1=1 (3).(x-3)^2=0,x1=x2=3,(4).

(-6) 2+3 4=84 0,x1=(6-root84) 6=(3-root21) 3,x2=(6+root84) 6=(3+root21) 3 (5)(x+3)(x-2)=0,x1=-3,x2=2 x +x+1 4-1 4=6 (x+1 2) 2=25 4 x1=-5 2-1 2=-3 x2=5 2-1 2=2=2, (6) Simplification: 2x 2-12x-5=0, =184 0,x1=(-1-root number 46) 2,x1=(-1 + root number 46) 2

1. (x-1)2=13 x-1=positive and negative root number13 x = positive and negative root number13+1

x2-x-2=0 (x-1)(3x+2)=0 x=1 x=-2/3

3. ( The open root number gets x = plus or minus half of the root number thirteen + 4, (x-1)2 = 3 x = plus or minus the root number three + 1

1,(x-1) 2-13=0,x=-+ root number (13)+1,2,3x 2-x-2=0,(3x+2)*(x-1)=0,x=-2 3 or x=1,(x+3 2) 2-2-9 4=0,x=-+(root number 17) 2-3 2.、

4.(x+3)(x+3-2)= or x=-1

5.(x-1) 2-3=0, x=-+ root number (3)+1