What is the problem of using 5 kWh of electricity for a three phase 3 point motor an hour?

The actual power of the motor depends on the load, not 3kw motor output power must be 3kw, if the no-load power is not large.

The motors equipped with water pumps are relatively large, and the actual power consumption is generally smaller than the nominal one.

Using 5 kWh of electricity in an hour is a bit much, and it is more likely that there is a problem with the pump and pipeline. What does it mean to be bored, how do you know it's boring? If the water output is small, or the water pressure is small, if the water volume is large and the pressure is small, the pump head is high.

The rated power of the three-phase motor refers to the shaft power it outputs, which is the mechanical energy power, which is converted by a part of the input electrical power, and the other part is converted into wind energy (the electric fan of the motor) and thermal energy (the motor is heated when it is running), so the motor has an efficiency ( ) parameter. The efficiency of the 3kw motor is generally between 70-80%, which is related to the quality and the number of poles, and whether the voltage is normal, so the power consumption of the 3kw motor is generally between degrees when the rated load is one hour, and the power consumption of your 3kw motor is 5 degrees an hour is a bit overloaded, and it should be a little overloaded. You can measure the current compared to the rated current on the nameplate.

What does a 3-point motor mean? 3kw an hour 5kw h is normal.

You see how powerful your motor is.

The power kilowatt-hour of an electric motor is the amount of electricity consumed per hour. If your motor is 3000 watts in three phases, then, the power consumption per hour is about 3 kilowatts, if yours, the motor is in overload operation, then the power consumption can reach more than 3 degrees or even 4 degrees, it is possible, if it is a light load, then the average power consumption is less than three kilowatt-hours, even far lower than the three-way store, it is also possible.

Hope mine is helpful to you.

With a 4 kilowatt three-phase motor pumping, then in the case of full load, the output power of the motor is 4 kilowatts, but the actual power consumption should also be added to the various losses of the motor, the actual power consumption = 4 kilowatts Motor efficiency = 5 kilowatts (assuming that the motor efficiency is, that is, 5 kilowatts of electricity consumption in 1 hour.

Motor efficiency is an important performance indicator of the motor, and the national regulations must be marked on the motor nameplate.

It consumes 1 kWh of electricity per hour per kilowatt of power.

The 4 kW three-phase motor consumes 4 kWh of power per hour under rated load.

The 3kw three-phase motor consumes 3 kWh of electricity for one hour of operation, and the 4kw three-phase motor consumes 4 kWh of electricity for one hour of pumping.

If the motor is fully loaded, ikwx 1 hour = 1 kWh. 4kwx1 hour = 4 kWh.

If it is a rated load, it consumes about 4 kWh of power per hour.

If it is rated power, it is generally 4 kWh, and it will generally be smaller, and see if the pump is working in the rated state.

Hello, glad to be able to your question, one kilowatt hour of electricity is one kilowatt hour. If it's input power, and it's running at full load, that's degrees per hour. If it is its active power, and it is operating at full load, it also depends on its power factor, which may exceed the degree per hour.

If it's running below its rated load, it's going to be below the degree, I hope mine can help you.

Hello, I'm glad to answer for you, three-phase motor 1 kilowatt 1 hour with 1 kilowatt of electricity, because, the power is the power kw h, that is, the power consumption of the machine, 1kw three-phase motor in the working hour is one degree of mu disturbance electricity, its electricity sensitivity content and several phases have nothing to do with it, three-phase one kilowatt-hour, single-phase is also one kilowatt-hour, but if the rated current of the 1kw three-phase AC bridge laughing machine is, the no-load current is generally the rated current 1 3, that is, that is to say, the motor does not need one kilowatt-hour when no-load.

The amount of electricity that a three-phase 30 kW motor needs to consume in one hour depends on the voltage and current, which can be calculated by the following formula:

Electricity (kWh) = Power (kW) Time (hours) Power factor.

Among them, the power factor refers to the ratio of the active power consumed by the motor to the apparent power, usually between to.

Assuming that the voltage of the hood is 380 volts, the current is 45 amps, and the power factor is, then the power required by the three-phase 30 kilowatt motor for one hour is the answer

Electricity = 30 kW 1 hour 1000 = kWh.

Therefore, a three-phase 30 kW motor requires kWh of electricity for one hour.

The power of the three-phase 30 kilowatt electric Laochang machine is 30 kilowatts, that is, it consumes 30 kilowatts of electricity in one hour. It should be noted that the actual energy consumption of the motor also depends on its operating state and use time. If the motor runs for less than an hour, the actual amount of electrical energy consumed will be reduced accordingly.

In addition, the efficiency and power factors of the motor also affect its actual energy consumption.

Summary. Hello, the degree indicates the rated power of the motor, which means that the motor needs to consume kilowatt-hours of electricity for one hour, that is, the kilowatt-hour of electricity.

Hello, Zao Zhengweidu indicates the rated cleaning power of this motor, which means that this motor needs to consume kilowatt-hours of power for one hour of work, that is, kilowatt-hours of electricity.

The power consumption of the motor for an hour depends on the actual load driven by Dabi. If the motor runs for one hour with rated load, the power consumption will be slightly more than the degree (because the motor efficiency cannot = 1); If the actual load of the motor belt is less, the power consumption per hour will be less than degrees.

So if you're running at full capacity, it's electricity.

How much power does a three-phase motor consume per hour? The formula for calculating the power consumption of the motor.

1. The power consumption of the three-phase motor when the working voltage is 380V and the load current is 20A

P 2, the voltage is 350V, power consumption:

P 3. When the load voltage is 350V, the current is 30A, and the power consumption is:

p Lift lead wisdom 14kw h

4. When the voltage is 380V, the current is 30A, and the power consumption is:

p Three-phase power is calculated by formula p

The power factor cos is generally between, and the average value is calculated).

For AC three-phase four-wire power supply, the line voltage is 380, the phase voltage is 220, and the line voltage is the root number 3-phase voltage.

For the motor, the voltage of a winding is the phase voltage, and the voltage of the wire is the line voltage (refers to the voltage between phase a, phase b, and phase c, the current of a winding is the phase current, and the current of the wire is the line current.

When the motor is connected to the star: line current and phase current; Line voltage: 3-phase voltage. The tail wires of the three windings are connected and the electric potential is zero, so the voltage of the windings is 220 volts.

When the motor is angled: the line current is 3-phase current; Line voltage Phase voltage. The winding is directly connected to 380, and the current of the wire is the sum of the vectors of the currents of the two windings.

The power calculation formula p=root number three ui times the power factor is correct.

A clamp-on ammeter card is used to measure the line current on any line of a b c.

The power consumption of the motor is calculated using the following formula:

Degree of power consumption = (root number 3) x motor line voltage x motor current x power factor ) x power hours 1000

The rated power of the motor is 750W, using the star connection positive response method, connected to the three-phase 380 volt power supply, and the current is monitored by the inverter; I also used a clamp ammeter to measure, and measured the current of each phase as , which means that the current measured by the inverter and the clamp ammeter is the same.

Because the motor is a star-shaped connection, the residual voltage of the line current is times the phase voltage, the line current is equal to the phase current, and the actual power consumed by the motor: 380 = 724 W, so that the actual power consumed by the motor is close to the rated power of the motor.

If the motor is triangular connection, the line voltage is equal to the phase voltage, and the line current is times the phase current, and the calculation of the actual power consumption of the motor is the same.

This shows that the actual power consumed by the three-phase AC motor is equal to the line voltage and line current.

The motor is rated at 4

The unit of measurement of electricity consumption is kWh, which is the electricity consumption of an hour for a kilowatt power consumer. If it is a 1,000-watt rotten plum generator, the amount of electricity generated for one hour of operation is one kilowatt-hour of electricity. A three-kilowatt generator with a full load capacity is of course three kilowatts of electricity.