Unary equation application problems, urgent to solve the master!

1.Set a daily water supply of x 10,000 cubic meters.

3x+x+1/2x+1=

x = 10,000 cubic meters A 10,000 cubic meters B.

10,000 cubic meters C.

2.Each A-type car transports x tons of earth and stone each time.

600 5 120 tons.

120-6x)/4=(120-3x)/6

x = 10 tons of type A.

120-6*10) 4 15 tons B type.

Solution: If the daily water supply of water plant A is x million cubic meters, the daily water supply of water plant B is 3x, and the daily water supply of water plant C is 1+x 2, which can be obtained according to the title.

x+3x+x/2+1=

Solution: x= 3x=3* x 2+1=

Therefore, the daily water supply of water plant A is 10,000 cubic meters, the daily water supply of water plant B is 10,000 cubic meters, and the daily water supply of water plant C is 10,000 cubic meters.

2.Solution: Each A-type car transports x tons of earth and stone each time, and each B-type car transports (600-5*6x) (4*5) tons of earth and stone each time, which can be obtained according to the topic.

3*5x+6*5(600-5*6x) (4*5)=600 solution: x=10

So (600-5*6x) (4*5) 15 Therefore, each type A vehicle transports 10 tons of earth and stone each time, and each type B vehicle transports 15 tons of earth and stone each time.

1. Let A be x, then B is 3x, and C is x 2+1, so A, B, and C are 10,000 cubic meters respectively.

2 Let a transport x tons each time, then (600-5*6x) (5*4)=(600-3*5x) (5*6).

The solution is x=10

So A transports 10 tons each time, and B transports 15 tons each time.

(1) Find the wall area that needs to be painted in each room;

30*3-40=50 (square meters).

2) Boss Zhang has 36 such rooms that need to be painted, if you ask 1 master to take 2 apprentices, how many days will it take to complete?

A master brushes a day: (50*8-40) 3=120 (square meters) An apprentice brushes a day: (50*9) 5=90 (square meters) 36*50 (120+90*2).

6 (day) 3) It is known that the daily salary of each master and apprentice is 85 yuan and 65 yuan respectively, and Boss Zhang requires it to be completed within 3 days, and asks how to hire people among these 8 people, so that it is cost-effective?

Average completion per day: 36*500 3

600 (sqm).

Two masters are hired and four apprentices are the most suitable.

1.A and B were riding bicycles and were walking in opposite directions from two places 65 km apart at the same time, and they met each other for two hours. Keep B traveling 16km per hour to find A's speed.

Solution: Set the speed of A to be x kilometers per hour.

16×2＋2x＝65

32＋2x＝65

2x＝33x＝

2.If A does a certain job alone, it takes 40 days to complete, B does it alone takes 24 days to complete, if B does it for 18 days first, and then A completes it, how many more days does A have to do to complete the whole work?

Solution: It takes X days to set up armor.

18×1/24＋x×1/40＝1

3/4＋x/40＝1

x/40＝1/4

x＝1/4×40

x＝10

1.Set the length of the team x km

x/(12-8) +x/(12+8)=

x=2.Let the distance be x km

x/3)/36 +(2x/3)/72 + = x/36x=162

3.Let B x per minute then A is 2x-3035x= 25(2x-30).

x=50A, 70m B, 50m per minute

4.Let B leave x days.

7/14 + 7-x+2/18) +2/12 =1x=35.You seem to be on the wrong topic.

1) It takes X hours for A and B to do it together, then.

Solution x = 11 5

2) After X years, the elder brother is twice as old as the younger brother.

then 15+x=2(9+x).

The solution yields x= -3

3 years ago, 3) set the height of the cylindrical bucket is xmm, then there is.

300*300*80=π*（200/2)^2*xx=720/π

1 For a job, it takes 6 hours for A to do it alone, 4 hours for B to do it alone, A does it for 30 minutes first, and then A and B cooperate, how many hours does it take for A and B to do it together?

It will take x hours.

1/6×30÷60+【1/6＋1/4】x=15/12x=11/12

x=11/5

2 When the two brothers are 15 years old and 9 years old respectively, how many years later will the elder brother be twice as old as the younger brother?

After X years, the elder brother's age is twice the younger brother's age.

15＋x=2[9＋x]

15＋x=18＋2x

x = -3, i.e. 3 years ago, the brother's age is twice the brother's age.

3 Pour a rectangular iron box filled with water with an internal length, width and height of 300 mm, 300 mm and 80 mm respectively into a cylindrical bucket with an inner diameter of 200 mm.

Let the height of the cylindrical bucket be xx

1.Set it will take x hours, then.

x+ solution, x=

2.After X years, the elder brother is twice the age of the younger brother, then.

15+x=2(9+x)

The solution yields x= -3

It should have been 3 years ago.

3.Set the height to be x mm, then.

300×300×80=100²πx

solution, x=720

1.(hours.)

x=-3 i.e. it will not be possible in many years.

4 h=720 mm.

Ergonomic ratio.

1/12: 1/8: 1/6

Typing. 60000 pcs. Xiao Wang typed.

90,000 pcs. Xiao Li typed.

120,000 pcs.

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