Why is the physical bird okay, and after the plane hits the bird, why is the plane destroyed and the

The bird has a cuticle on its feet, which is very dry and has very poor conductivity, it can be considered that it is not conductive, and it does not care about the resistance of the high-voltage line or something, and there is also the problem of parallel circuits, the bird does not conduct electricity at all, does not form a potential difference, and cannot reach the loop, so there will be no current through, of course the bird will be fine, understand?

In junior high school, that's what we can understand, and that's what our teachers say, and we don't understand. The short circuit is just a way of saying that there is actually an electric current passing through it, but it is very small, not that the resistance of the bird's claw is large, but that the resistance of the bird is large, and the high-voltage wire is very thick, and the resistance is very small compared to the bird, and the current is so small that it does not electrocute the bird, and this is different from your light bulb example, it is not slightly smaller, it is much worse, and when it is not bright, the current is small, the power is not enough to emit light, not that there is no current. I believe that with the abundance of knowledge, we will understand the real cheer.

I think it's right, the resistance of the bird is about a few thousand ohms, and the wire between the feet is only a few ohms due to the length of the small resistance, the second year of the junior high school should have said, in parallel, the current with small resistance is large, and the difference in resistance is too large, and the bird basically has no current through, so the light you said does not light up (only when the resistance is far apart).

= Both are right, the bird does not stand between the live line and the neutral line, ensuring that the voltage between its legs is small. If you stand on fire, there are millions of volts. Then no matter how big your resistance is, it won't work.

It's just another way to illustrate the problem. The resistance of the high-voltage line is small. It ensures that the voltage between the legs of the bird standing on the firing line is small (series principle)...In this way, coupled with the fact that the bird itself has a large resistance, it will be fine.

The voltage between the feet of the bird is very small, and according to i=u r, because the voltage is small, the current flowing through the bird is very small, and the bird is fine. Do you think that the safe voltage of a person is not higher than 36V, how big can a bird be? Otherwise, the bird would have rolled its eyes.

This sentence is what Mr. Puppet means.

In general, it doesn't matter if the bird is not connected to the ground and does not form a "closed loop", it is the same as a person standing on a dry wooden bench and touching the line of fire. You don't understand if you talk too much.

After parallel connection, the current is inversely proportional to the resistance, if the resistance difference between the two parallel resistors is large, the bulb with the largest resistance value will not light up, because the current passing through it is too small.

I think the resistance of the bird must be much greater than that of the power line, and the resistance of the wire is almost 0 ohms, so the bird must be short-circuited. "What Our Teacher Says".

Agree with the seventh floor, there is almost no potential difference between the claws of the birds.

There is also a similar problem is the step voltage of high-voltage electricity, which should be easy to understand when your teacher talks about it).

The voltage between the bird's legs is very small.

It is advisable to find a 120-yard car on the highway and try it out, and if you are okay, the bird will be like you.

I really don't know how to think of asking such a question! It was actually destroyed by the machine!

Who says birds are okay? Poor birds are usually smashed into a piece of cake. The plane may or may not have an accident.

The bird will definitely die because it has a small force area and the impact force formed will be large.

It's a lose-lose situation, because the large force area of the plane will only hurt locally, but the poor bird will be over!

Momentum formula: fs=m(v1-v2) f is the force s is the time m is the mass v1 is the initial velocity v2 is the final velocity formula deformation f=m(v1-v2) s The mass of the bird is about , if the speed of the aircraft is 340m s and the speed of the bird is 5m s, then because they are opposite to each other, so the initial velocity of the bird is 345m s when the bird and the plane collide, and the velocity of the bird is instantly zero, so v1-v2=345m s, The instantaneous time is very short, and the above data is substituted into the formula: f= m(v1-v2) s=cow.

Airplanes are afraid of birds because the relative speed of airplanes is large, and the force after colliding with objects is greater. If it exceeds the bearing capacity of a certain part of the aircraft, it may damage the body or parts of the aircraft, and in serious cases, it will directly threaten flight safety.

Relative motion.

The plane has a lot of speed, whereas the bird has a slow speed (relative to the ground).

However, the speed of the bird is very fast relative to the aircraft, and using the kinetic energy theorem, it can be seen that the energy is so large that the aircraft is not destroyed.

The combination of mass and speed creates a tremendous amount of kinetic energy.

For example, in "Interesting Physics", it is calculated that a cubic centimeter of iron falling into the Black Sea at the speed of light can make the entire Black Sea boil.

If in a'Birds can hit pigs, so what's the shortest path? How short?

It's not good to draw, and the distance is five-eighths r+s.

Assuming that it can be played, let the initial velocity be v0, h1+h2=1 2gt0 2 find t0=from v0t=x=l1+l2 find v0=30 8 m s, and on the previous platform: 1 2gt1 2=h1 find t1=x=v0t1=<2m

So you can't hit it.

t1 = root number 2h1 t square.

x=1 2gt square.

As long as the v0 passes through the table and hits the pig.

If you can pass, then continue to count by your formula.

In addition, it is under the root number.

The bird hits the plane, which is equivalent to the plane stationary bird using the speed of the plane to collide, although the momentum change is not large, but because t is extremely short, f is extremely large. In addition, the bird is small and the pressure is strong. It's perfectly okay to punch through the plane.

Bullets can pierce airplanes. Not to mention a bird that is as fast as a bullet.

I don't think the birds will pass by in an airplane, right? The speed of the bird after hitting the plane is equal to the speed of the plane. δv is equal to the sum of these velocities (relative flight) or equal to the difference in velocities (flying in the same direction).

Relative to the speed of the airplane, the bird is very slow, so the δv is close to the speed of the airplane. And there is also the problem of short time, t is small, so f is big.

Because the mass of the bird is relatively small compared to the aircraft, it can be considered to keep the original speed of the aircraft unchanged after impact, and fly.

If the plane is not rotten, the speed of the bird is at least equal to the speed of the plane, so the force is very large, and this force is enough to make the plane perforate, so it is judged that the plane will definitely be destroyed.

That's the theory of relativity, it's the same.

From a physical point of view, it is divided into situations:

1.The aircraft is stationary or the speed (v) is less than a certain critical value (the critical velocity v1 that the bird can withstand) the bird is fine, and the aircraft is fine.

Both the bird and the plane hung up.

The bird crashes into the plane, and the relative velocity of the two is very large, so the bird is undoubtedly a missile, and because of the huge kinetic energy, it will make a big hole in the plane, and if it gets into the engine, it will cause the engine to stall.

According to the law of conservation of matter, the total mass of the bird + the plane does not change.

I will say one of the different situations:

Plane crash! The bird is dead!

Since the momentum is conserved, both the aircraft mass and the velocity are large, then the momentum is large. Set MV. The birdie has a smaller speed and a smaller mass MV. Ignoring the air resistance or something, the momentum before and after the collision is conserved.

MV-MV)=(M+M)V' (Forward direction in the direction of the aircraft)V'=(mv-mv) (m+m) visible velocity.

For birds: m(-v-v')=ft (impulse theorem) then f = -2mmv and t is very small, so f is very large! And because the bird is very small, then the pressure p=f s (the bird is small, then s is small) so p is very large!!

So the planes and birds are all hanging!