Elementary questions about C programming

First determine whether the year is a leap year (divisible by 4) according to the number of years, and then determine which array to use:

const int leap_year[12] = ;Leap years from January to December The number of days per month.

const int normal_year[12] = ;The number of days in each month from January to December in a common year.

Then calculate the day based on the number of months and days entered.

Attached is the full procedure:

#include

const int leap_year[12] = ;Leap years from January to December The number of days per month.

const int normal_year[12] = ;The number of days in each month from January to December in a common year.

main()

int i = 0;

int result = 0;

int temp = 0;

int week = 0;

int offset = 0;

int day,month,year;

int *p;

printf("Please enter the year");

scanf("%d",&year);

printf("Please enter a month");

scanf("%d",&month);

printf("Please enter a day");

scanf("%d",&day);

if(!(year%4))

p = leap_year;

elsep = normal_year;

for(i=0;i<(month - 1);i++)

temp += *p;Count all the days in the previous months.

p++;result = temp + day;Add the number of days in the month at the end and you're the final result.

if((result%7)>=2)

offset = 1;

elseoffset = 0;

week = result/7+offset;

printf("Today is the %d day of the %d year, the %d week",year,result,week);

Is this needed? It's easy, right?

Easy? Junior? Tell me what week is April 8, 1954?

This software should be able to add up the years, months and days in the week, seven days a week, calculate the first day of a year is the day of the week of the first week, and then divide the number of days by seven, and then choose according to the remainder.