x 1 x 3 x squared ax b, then the value of ab is

x 3+ax 2+1) (x+1)=x 2-bx+1x 3+ax 2+1=x 3-bx 2+x+x 2-bx+1x 3+ax 2+1=x 3+(1-b)x 2+(1-b)x+1x 2 coefficients are equal to Lu Zheng: 1-b=a

The x-term coefficients partner equally: 1-b=0

b=1a=0

Solution: From (x-3)(x+1)=x 2+ax+b, x 2-2x-3=x 2+ax+b

The coefficients comparing the two sides of the above equation are: a=-2 b=-3

b^a=(-3)^(2)=1/9

Solution: The original equation is deformed to be: x -2x-3=x +ax+b then a=-2, b=-3

So b to the power of a = -3 to the power of -2 = 1 9

(x 2-1) = a + b (x-2) + c(x-3) The right side of the equation is divided:

The denominator is consistent with the left side of the equation, and comparing the numerator to the left side of the equation yields:

a=1-5a+b+c=0

6a-3b-2c=-1

Solution: a=1, b=-3, c=8

(x 2-1) (x-2)(x-3)=a+b (x-2)+c (x-3), through, get:

x 2-1) (x-2)(x-3) = [a(x-2)(x-3)+b(x-3)+c(x-2)] (x-2)(x-3), the denominator is the same, then the numerators are equal, so.

x 2-1=a(x 2-5x+6)+b(x-3)+c(x-2)=ax 2+(-5a+b+c)*x+(6a-3b-2c), the coefficients of the polynomial correspondence are equal, so.

a=1,5a+b+c=0,6a-3b-2c=-1, solution: a=1,b=-3,c=8.

x+3)(x-2)=x, such as squared + ax+bx squared + x-6=x square + ax+b

a=1，b=-6

Just read the personal opinion of the accompaniment.

Hello, Melbourne de miss:

Solution: a x + b x = 3 (1-x).

a²+b²)x=3-3x

a smile+b ) x+3x=3

A Qingzao is ruined + b +3) x = 3

x=3/(a²+b²+3)