Organic and Inorganic Chemistry in High School Chemistry!!

Of course, there is hope, inorganic chemistry and organic chemistry are two branches of chemistry, inorganic talks about some basic and elemental knowledge, organic talks about the properties and reflection mechanism of organic compounds, etc., you can learn well, I hope you inorganic will also keep up.

There is a certain connection, but the connection is not big, it doesn't matter if it is inorganic, as long as you learn it organically, you can still learn well.

Basically, there is no connection, the organic in high school is very simple, as long as you listen carefully to the lectures, remember the relationship between several organic substances, you can learn well, once my inorganic was also very poor, but when I learned organic, I learned very well, and then it was just as simple to see inorganic.

The main reason why inorganic chemistry is bad should be the lack of interest in memorizing substances and reflections in inorganics.

Although organic chemistry is not much related to inorganic chemistry at the intellectual level, organic chemistry needs more memorization. Moreover, it is not only the reactants, but also the reaction conditions and reaction by-products.

So, organic is still not easy for you.

However, by repeatedly reading books and writing questions, you can generally reach the level of coping with the college entrance examination.

It's certain that there is a connection, it's not very big, but it's not a lot either. There is still hope in your situation. Organic chemistry is mainly concerned with the relationship between chemical bonds and their transformation.

There is a certain relationship, but it is easy to overcome if you work hard, don't give up, my classmates are in the second year of high school and feel that they are not very good at inorganic and did not seriously learn organic, and now they regret that they did not do a good job in organic in the third year of high school, and they can get a high score in organic if they are very inorganic!

The connection is very small, organic at the beginning of learning may feel a little difficult, after entering the door, it will be easier and simpler to learn, don't worry, as long as you learn seriously, there is absolutely no problem.

Although both are chemical categories, there are still great differences in research fields and methods, organic is more intuitive than inorganic, and the knowledge is more understandable The key is the basic conceptual problem, as long as it can be clearly mastered, it is much easier to learn after organic In addition, organic knowledge in high school is the most primary. It's not difficult, I believe you can learn it well

There is a little connection, but the impact is not too big, and the difference in the midterm is quite large. So, there's hope.

Basically, there is not much connection, and if there is a disconnect in chemistry, it is difficult for other parts to be good! ~

There is very little contact, don't worry, learn hard, organic chemistry is mainly about back reactions.

I don't think it has much to do with it, and after I've learned organic ones, I'm not familiar with inorganic anymore. Organic and simple.

High School Organic Elective Chemistry.

The organic score of the exam is all in the selection of questions.

No more than 10 points

Personally, I don't think it's too difficult

But the molecular structure is the simplest.

Look at it.

Organic chemistry is more annoying, and there are many things to remember.

I think the 2 are a bit connected.

As long as you listen to the class and do the exercises, you won't. Difference. Hehe.

The organic question is simple, there are fewer things to remember, there are not more inorganic things, but to be able to use it, this is the key.

It's very simple, it's just a functional group.

Methane: CH4 + 2O2 = ignition = CO2 + 2H2O ethylene: 2C2H2 + 3O2 = ignition 2CO2 + 2H2O benzene:

2C6H6+15O2==Ignition==12CO2+6H2OC6H6+Cl-CH3=C6H5-CH3+HCl, the catalyst is FeCl3C6H6+BR2=C6H5br+HBR, and the catalyst is Febr3 ethanol:2Na + 2C2H5OH=2C2H5O2 + H2 2CH3CH2OH+2O2 --2CH3CHo+2H2O2Cu+O2===2Cuo CH3CH2OH+cuo===ch3cho+cu+h2o

I'm only in the first year of high school, so I only know the equation for the first year of high school.

go on！

If it's not the college entrance examination tomorrow, I think you should still pick up the high school textbook and copy it by hand, while copying, while remembering, knowing his conditions (the conditions of organic equations are very regular, as long as you write more, remember more, you will naturally understand, I can't say), and the principle, etc.。。。

The method is very good!! I think it's more qualitative than if you directly find a ready-made equation that saves time !! Believe in the people who have come ...

There are many things that are only deeply impressed when you have experienced them.

I hope you will be patient and understand ...

y111uan, sisters or brothers, you are too strong.

heating).

cyclohexane) first with concentrated nitric acid and then with concentrated sulfuric acid.

Cool to room temperature before adding benzene.

Water bath] The thermometer is inserted into the beaker.

Remove mixed acid, heat and pressurize).

CH3CH2OH ethanol

Hno3 (concentrated H2SO4.), bonus +

3h2→（ni,60℃）→

no2h2o

Concentrate. And many more. ：naoh

Nitrobenzene: a colorless, oily liquid.

Insoluble bitter almond flavor.

Poison 1...3. Substitution - sulfonation (concentrated sulfuric acid) +

H2SO4 (concentrated).

70 80 degrees).

so3hh2o

2...heating).

ch3ch3

Ethane CH2 = CH2

H2O (catalyst CH4

CL2 (light).

ch3cl(g)

hclch3cl

CL2 (light).

ch2cl2(l)

hclch2cl

CL2 (light).

chcl3(l)

hclchcl3

CL2 (light).

ccl4(l)

hclch2=ch2

br2ch2brch2br

ch2=ch2

HCl (catalyst).

ch3ch2cl

ch2=ch2+h2

Catalyst.

Question 1: Because both gases can make the clarified lime water turbid, according to the common gases, these two gases are SO2 and CO2, which form CaSO3 and CaCO3 precipitates, respectively.

Reaction equation: C + 2 H2SO4 (concentrated) == CO2 + 2 SO2 + H2O (You remember to mark sulphur dioxide and carbon dioxide behind!) ）

Identification of these two gases cannot be done with (a).

SO2 is reducible, which can fade potassium permanganate solutions, but carbon dioxide cannot.

SO2 has bleaching properties and can fade magenta solutions, but carbon dioxide cannot.

When SO2 is introduced into an acidified Ba(NO3)2 solution, a redox reaction undergoes a redox reaction to produce a barium sulfate precipitate.

Carbon dioxide does not react with acidified Ba(NO3)2 solutions.

I think the second question is a bit problematic, first of all, the title does not say the properties of c and d, I can't infer which is carbon dioxide and which is sulfur dioxide, give you the equation for the reaction of sulfur dioxide and carbon dioxide with NaOH solution, respectively, refer to it yourself:

SO2 + 2 NaOH == Na2SO3 (sodium sulfite) + H2O (in case of insufficient SO2).

In the case of a sufficient amount of SO2, it will continue to reflect the equation that is.

SO2 + Na2SO3 + H2O == 2 NaHSO3 (sodium bisulfite).

The equation for the reaction of CO2 with NaOH solution is similar to the above two cases, and you just need to replace all the s in the above equation with c (......I really don't want to fight .........

The second question: The red metal element is copper, which should be a reaction between copper and dilute nitric acid.

The oxidizing nitric acid (i.e., the reduced nitric acid in the question) is 2mol, and according to the equation, it can be seen (let's find the equation yourself) 1mol of reduced HNO3 corresponds to 1mol of NOs gas, so 2mol of gas is generated

Yes. Question 3: With the increase of water temperature, the solubility decreases generally only Ca(OH)2, and the non-metallic element is Cl2

J has a bleaching effect is calcium hypochlorite Chemical formula Ca(clo)2 d should be calcium chloride Electronic formula write it yourself This is really hard to .........

The fourth question a is HCL to test Cl ions with silver nitrate and dilute nitric acid, first take a small amount of liquid to be measured, add silver nitrate to it to produce a precipitate, and then add dilute nitric acid, if the precipitate does not dissolve, it means that it is chloride ions.

This is my own doing, not necessarily to you, to criticize and accept the words, all of them are typed by yourself, for the sake of so many words, give me a few more points! Thank you.

1 question, 2H2SO4 (concentrated) + C===CO2 +SO2 2H2O A D 2 can produce precipitation.

4CO2 +5NaOH===3NaHCO3+Na2CO3+H2O2 Question, 3Cu+8Hno3=3Cu(NO3)2+2NO+4H2O The gas is.

Question 3, because it's CaCl2 (I can't express it electronically, I'm sorry) 2Cl2+2Ca(OH)2=CaCl2+Ca(CLO)2+2H2O4 questions, use litmus if it turns red.

C+2H2SO4 (heating) = CO2 + 2SO2 + 2H20A) BaCl2, the phenomenon is to produce white precipitate first, and then disappear and become clear b) carbon dioxide gas does not react, sulfur dioxide will have black precipitate to produce c) sulfur dioxide gas will make the magenta solution fade, which is the bleaching of sulfur dioxide, and carbon dioxide has no obvious phenomenon.

d) Sulfur dioxide will be oxidized by acidified barium nitrate solution into sulfate ions, resulting in white precipitate, and carbon dioxide has no obvious phenomenon.

1molnaoh+

2）3cu+8hno3=3cu（no3）2+2no+4h2o2/3*2*

3) a is ammonium chloride. The method of testing chloride ions is to add a silver nitrate solution dropwise to the solution, resulting in a white precipitate that is insoluble in strong acids.

(1) C+H2SO4=CO2+SO2+H2O (From left to right, the coefficient is:

Choose A5NaOH 4CO2 == Na2CO3 3NaHCO3 H2O

2)2l3）cl*ca*cl

4) Slightly heat a solution containing anions in a, and then test with blue litmus paper, if it turns red, it means that it contains this anion.

The weight of the anhydrous calcium chloride drying tube is increased, that is, the generation of H2O is, and the precipitation is obtained by clarifying lime water by 14g, that is, the generation of calcium carbonate is 14g, so the amount of CO2 containing substances is.

The organic vapor has been converted to the standard condition) is , that is, the mass is, so the relative molecular mass is 108

The organic matter is, the molecular formula is cxhyoz, and the combustion reaction:

CXHyoz + MO2 ==XCo2 + Y 2H2O (M can be determined by XYZ and is not useful for solving here, so omitted).

1 x y/2

The solution is x=7 and y=8

That is, the molecular formula is C7H8oz, the molecular weight is 108, and the solution is Z=1

So the molecular formula is C7H8O

2) This organic matter is purple in color with FeCl3 solution, containing a benzene ring with a hydroxyl group attached to it. May be o-, inter, p-tolophenol. (three).

Chemistry is a liberal arts subject in the sciences, so memorization is required. For organic chemistry, high school is still relatively shallow, and for organic chemistry, it may feel difficult at first, but once you get started, you will feel that it is the easiest.

For the beginning, you have to memorize the structure and model of simple organic matter, and for the later reactions, you need to understand a later and follow the upper line. Generally, every time a new compound appears, it will take a representative one to talk about their properties, such as ethanol for alcohols, acetaldehyde for aldehydes, for each type of chemical properties have a certain commonality, for different comparisons remember the characteristics, so that you will learn organic chemistry well.

That's how I learned chemistry in high school, and I feel very effective, high school chemistry is the best of all my subjects, and my major in college is chemistry. Hope you can learn chemistry well!

As long as you figure out the four major reaction types, it's fine, substitution, addition, elimination, and aggregation.

Write the methane and chlorine reaction equations. Can write alkane hydrogen (mobile phone does not have that word) isomer. and know the physical properties.

Learn the basic knowledge well, remember the physical and chemical properties of various organic substances, and remember the chemical reaction equations, especially the reaction conditions, which is a bit empty, in short, learn hard, learn every step well, you will definitely learn well, come on!

The simplest is methane, several key functional groups in organic chemistry such as hydroxyl group, aldehyde group, ketone group, carboxyl group, as well as organic hydrocarbons, key reactions, such as addition, substitution, cracking cracking, esterification, and some compounds with special properties and the like, the following one is very right: the structure of the compound determines its properties, and it is necessary to be imaginative.