Which has a higher probability of occurring 1 1 or 10 3?

In the case of ten-1 and ten-3, of course, the probability of 10-3 is a little higher, because the probability of time three is 30%.

Then these conditions should be 1 10, and the probability of happening is higher, because it is easier to happen.

If the probability of 10-1 and 10-3 occurs, if it is based on the normal value, the probability of 10-3 will be much higher than the probability of 10-1.

Hello this friend, if you understand it according to its performance, this general situation is the first to happen with a high probability of occurrence.

10-3 is bigger because his odds are greater.

I think 10-1 is a little bit more likely to happen than 10-3.

If the power is high, I think the probability is slightly larger, it should be ten bars, and the probability of this happening is relatively large.

1 in 10 or 3 out of 10, which one has the highest probability of happening? It must be 3 10, because 3 10 is three points, and 1 10 is only one point short.

Hello, this time it depends on what the specific thing is, according to the normal situation, it should be 10:3, and the probability of occurrence is high.

10-1.and 10-3. Which has a higher probability of happening?

You only give this number and don't know what probability you are referring to. So I can only help you analyze one, that is, the probability of the occurrence of Shiguan Mountain is high.

10-1 = 9, 10-3 = 7, both of which are very common numbers, and the probability of occurrence is about the same.

Or the probability of the former happening is higher, because this situation is not easy to happen, so this phenomenon will occur in this regard.

That's it.

There are no other conditions.

Then the probability of both is equally high.

These two numbers should be 10-3 at first glance, and the probability of occurrence is greater.

: Let the probability of occurrence be a, then the probability of not happening is 1-a, and the probability of not happening three times is (1-a) 3, so the probability of occurrence is 1-(1-a) 3.

When will you get home? It must be that.,It must be that 3 10 probability is relatively large.。

From 1 to 10, the total number of solutions to choose 3 numbers is c(10,3) =10!/3!/(10-3)!120 pcs.

The sum of the sum of the three numbers is 1+2+3=6 at the minimum and 10+9+8=27 at the maximum

Without arguing about the sum value of the same number, it can only be enumerated, and the programming calculates it, and the probability of the corresponding sum value is as follows:

Attached: fortran**.

Summary. Hello, dear, a 10% probability means that there is a 10% probability that an event will happen, or a 10% chance that this event will happen. In other words, the probability of this event occurring in all possible outcomes is 1 in 10.

Kissing, specifically, if there are 100 repeat trials, the number of times the event occurs is about 10. Although this probability is not very high, it is still a situation with a certain chance of happening. In the concept of statistics and probability, 10% can be seen as a relatively small probability, but it is still a possibility that cannot be completely ignored.

What is the 10% probability?

Hello, dear, a 10% probability means that there is a 10% probability that an event will happen, or a 10% chance that this event will happen. In other words, the probability that the previous event of the chain will occur in all possible early calls is 1 10. Kissing, specifically, if there are 100 repetitions of the trial, the number of times the event occurs is about 10.

Although this probability is not very high, it is still a situation with a certain chance of happening. In the concept of statistics and probability, 10% can be seen as a relatively small probability, but it is still a possibility that cannot be completely ignored.

What does the probability of hepatitis B progressing to cirrhosis between 5% and 10% mean?

Hello dear, this sentence is describing the probability range of hepatitis B (hepatitis B lead cracking) patients developing cirrhosis. The specific explanation is as follows: Hepatitis B:

Hepatitis B is a liver disease caused by hepatitis B virus (HBV) infection. In people with hepatitis B, some may experience varying degrees of disease progression, including recovery, chronic hepatitis B, cirrhosis, etc. Cirrhosis:

Cirrhosis is a disease in which liver function is severely impaired due to long-term chronic inflammation and fibrosis of the liver. If hepatitis B continues to worsen, it may eventually develop cirrhosis. Probability Range:

This phrase refers to the fact that in patients with hepatitis B, the probability of developing cirrhosis is about 5% to 10%. This means that about 5% to 10% of people with hepatitis B will eventually develop cirrhosis. It is important to note that this probability range is only a rough estimate and does not apply to all people with hepatitis B.

The risk of developing cirrhosis is influenced by a variety of factors, including the time of infection with hepatitis B, the virulence of the hepatitis B virus, the individual's immune response, lifestyle, dietary habits, and more. It is important for people with hepatitis B to have regular medical monitoring and follow their doctor's recommendations for treatment closure to reduce the risk of developing cirrhosis.

The probability of hepatitis B progressing to cirrhosis is between 5% and 10%, which means that between 5% and 10% of hepatitis B patients will eventually develop cirrhosis and hail defeat.

That's not what I mean.

It only means that the probability of hepatitis B developing into cirrhosis is between 5% and 10%, but it does not mean that hepatitis B patients between 5% and 10% will eventually develop cirrhosis.

This probability is relatively small.

Summary. A 10% probability indicates a 10% probability that an event will occur. In other words, when you are faced with a 10% probability, you have a 1 10 chance that the event will occur, i.e., 1 out of 10.

This probability is not very high, so the probability of the event occurring is low.

What is the 10% probability?

A 10% probability indicates a 10% probability that an event will occur. In other words, when you are faced with a 10% probability, you have a 1 10 chance of the event happening, i.e. 1 out of 10. This probability is not very high, so the probability of the event being less sensitive.

How long does it take for fatty liver to become cirrhosis? The onset of liver cirrhosis is insidious, the development is relatively slow, and it generally takes more than ten decades, which means that it takes more than ten decades for fatty liver to develop into cirrhosis, is this correct? Please write the answer correctly or not frankly correct.

That's right. It usually takes more than a few decades for fatty liver to develop into cirrhosis.

How long does it take for fatty liver to become cirrhosis? The onset of liver cirrhosis is insidious, and the development of phase is slow, and it generally takes more than ten decades, which means that it generally takes more than ten years for fatty liver to develop into cirrhosis, is this meaning correct? Please write whether the answer is correct or incorrect.

That's right. It usually takes more than a few decades for fatty liver to develop into cirrhosis. Fatty liver disease refers to the accumulation of excess fat in the liver, and if you do not take timely measures to reverse the fatty liver, it may gradually develop into cirrhosis.

Cirrhosis refers to structural changes that occur after long-term damage to the liver, including the death of hepatocytes and the proliferation of fibrous tissue basilica. This process is relatively slow, usually taking more than a few decades, depending on the individual's lifestyle, eating habits, disease control and other factors. Therefore, for most people with fatty liver, if effective ** and life adjustment measures are taken in time, Boxiang can avoid or delay the process of fatty liver developing into liver cirrhosis.

The possible schemes from 1 to 10 add up to 11 are 2+9, 3+8, 4+7, 5+6, 6+5, 7+4, 8+3, 9+2, a total of 8 types. Since each number is equally probable, the probability of calculating these 8 schemes is the total hypothetical potential, that is, the combination number c(10,2) of 2 out of 10 numbers. Therefore, the probability of occurrence of these 8 schemes is 8 c (10, 2), i.e., 8 45, which is approximately equal to retaining 3 decimal places).

Therefore, the probability that 1-10 adds up to 11 is approximately , ie. Bad luck.

There is only one kind of love bend rent that 1-10 adds up to 11, that is, 1 and 10 are added, otherwise it cannot be equal to 11. Therefore, this probability can be carefully calculated using the combinatorial formula, i.e., 2 numbers from 10 are selected so that they add up to the number of schemes equal to 11. It is expressed by c(10,2), that is, the combination of 2 numbers from 10 numbers is 45.

And out of these 45 combinations, only 1 plus 10 equals 11, so the probability of this case is 1 45, which is approximately equal to the probability of being buried , i.e., about or . It is important to note that this probability is not universal for this particular problem.

There is only one case where 1-10 adds up to 11, which is 3+8. Therefore, the probability of randomly selecting two numbers from 1-10 to add up to 11 is 1 45, i.e., 1 divided by the number of all possible cases. Because in 1-10, there are 10 blind numbers, so the first number has 10 choices, and the second number can only be chosen from the remaining 9 numbers, so the total number of cases is 10 x 9 = 90.

There is only one case where two randomly selected numbers from 1 to 10 add up to 11, so the probability is 1 45.

There is only one case where 1-10 adds up to 11, which means that the finch is 5+6=11. Since the additive range is 1-10, the probability of each additive occurring is the same, i.e., 1 10. Therefore, finding the probability that 1-10 is equal to 11 can be transformed into finding the probability that two numbers are randomly selected from 1-10 and the sum of these two numbers is equal to 11, which can be solved by the method of combining numbers, that is, the combined number of 2 numbers in 10 numbers is (10, 2)=45, and there is only one combination of the full and sufficient conditions, so the probability is 1 45.

Therefore, the probability sought is approximately, i.e., approximately.

There are two possible combinations in 1-10 that add up to 11 buried by God:

Therefore, the number of combinations that meet the conditions is 2, and the number of possible combinations from 1 to 10 is 10. Therefore, the probability of satisfying the condition is 2 10 or simplified to 1 5, which is a 20% probability. That is to say, the probability that the two numbers randomly taken between 1 and 10 are added to the width of the knot and the blind result is equal to 11 is 1 5, which can also be understood as 1 out of 5 random times to meet the condition.

This probability can be solved by a simple combination problem, but the calculation of probability should pay attention to the strict constraints and randomness of the conditions.

There are several types of pies that add up to 11 from 1 to 10:

There are 10 cases, and the probability of each case is 1 100, because after choosing a number from 1 to 10, only one dust guess number can add it to equal 11, so the probability of each case is 1 10 * 1 10 = 1 100. So the probability that the additive state of 1-10 is equal to 11 is 10 100 or 1 10 or 10%.

There are two possible combinations between 1 and 10 that add up to 11, 1 and 10, and 2 and 9. So, that's a total of two possible combinations. The probability is 2 55, i.e. 2 divided by 11 10 2, where 11 is the total number from 1 to 10, and 10 2 is only 10 hail numbers available because each combination is only counted once.

So the answer to this question is 2 55, which is about or.

does not exist"1-10 plus plexus beats equals 11", so the probability is 0. There are a total of 10 numbers, and if you add any two numbers, you can get a number between 2 and 20. Since 11 precedes these numbers, it is not possible to add up the numbers from 1 to 10 to equal 11.

Therefore, when two numbers are randomly selected from 1 to 10 and added together, the probability of getting 11 is zero.

The combination of 1-10 that adds up to 11 has the following types of empty energy:

Therefore, the number of combinations that meet the requirements is 5.

The total number of combinations is 10, that is, 1-10 can be selected or not selected for each number state, so the total number of combinations is 2 to the power of 10 = 1024.

Therefore, the general blindness rate is 5 1024, which is about or about.

Mathematically, the number of permutations and combinations from 1 to 10 and 11 is , , four types, a total of 4 cases. Therefore, the probability that the sum of the integers from 1 to 10 is 11 is 4 55, that is, the probability of selecting one of the four cases, and then dividing it by the number of all cases 10x9x8x7x6x5x4x3x2x1=3,628,800, and the probability of selling is 4 55.