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Let the number of wins be x, the number of losses be y, and the number of draws be z, where x, y, and z are 0 respectively.

then x+y+z=total number of games, 3x+0y+1z=score.

This question x+y+z=4,3x+0y+1z=6.

So there is: 6-4=2=3x+z-x-y-z=2x-y. y=2x-2.

6+4=10=3x+z+x+y+z=4x+y+2z。y=10-4x-2z.

So, y=10-4x-2z=2x-2. Launched, z = 3x-6.

Replace "z=3x-6" with "3x+0y+1z=6", that is, 3x+0+3x-6=6, and get x=2.

Then substitute x=2 into "z=3x-6" to get z=0.

Then replace x=2 and z=0 with "x+y+z=4" to get y=2.

Therefore, two wins, two losses, and zero draws.

Set wins, losses, and draws for x, y, and z games.

Then: 3x+z=6, x+y+z=4

Because there are 6 points in 4 games, X can only be 1 or 2

x=1, then z=3, y=0

x=2, then z=0, y=2

If you don't understand, ask again.

x+y+z=4,3x+y=6, so y=6-3x, bring in the previous equation, z-2x=-2, z=2 (x-1) so x can only be equal to 1, x=1, y=3, z=0

Have you ever learned binary equations in your first year of junior high school?

Let C be the place where Xiao Ming and Xiao Hua first met, and D is the place where Xiao Hua caught up with Xiao Hua for the first time on his way back to B on a motorcycle from A (Figure 54). As can be seen from the title, it took Xiao Ming 60 minutes to ride a bicycle from A to C. Another 20 minutes of riding from C to D.

Since 60 20 = 3, the distance between A and C is three times the distance between C and D. After the two met for the first time, Xiao Ming rode a bicycle to CD, and Xiao Hua rode a motorcycle from C to Zhikong A, and then from A to D to catch up with Xiao Ming, a total of 2 distances between A and C and a distance between C and D, that is, 3 2 + 1 = 7 times the distance between C and D. Therefore, it can be concluded that Xiao Hua's speed on a motorcycle is 7 times the speed of Xiao Ming's bicycle.

Xiao Ming traveled the whole journey between A and B by bicycle, and Xiao Hua rode a motorcycle for 7 A and B places. Of the seven journeys between A and B, 4 were from B to A, and 3 were from A to B. Xiao Hua will inevitably catch up with Xiao Ming 1 times on the way from A to B on a motorcycle, so Xiao Hua will catch up with Xiao Ming 3 times on the way from A to B on a motorcycle.

Answer: On the way from A to B on a motorcycle, Xiao Hua caught up with Xiao Ming 3 times.

1) By the meaning of what you say.

The daily fuel cost of a modified vehicle accounts for two-fifths of the fuel cost of an unmodified vehicle.

So. The average daily fuel cost per vehicle after the modification is three-fifths lower than the fuel cost before the modification.

This is equivalent to 60% (if the question is correct, it should be like this) 2) The cost in the second question should be 4100 times 4000 = 16400000, if the fuel per car per day is also the cost.

The cost also needs to be added x times 4100 times 80 times 2 5 = 131200xx days after the fuel cost per car is saved.

4100 times 80 times 3 5 times x = 196800x fuel cost = cost, then the equation can be listed.

16400000=196800x or 16400000+131200x=196800x (this equation takes into account the cost of fuel per day).

The corresponding answers are x= or x=250, respectively

The first question is not specific and cannot be expressed. Question 2: Set @ days to recover costs @*4000*80=16400000+80*2 5*@ 320000@=16400000+32@ days.

Can't tell. Insufficient conditions. The one on the upper floor is also wrong, and I checked it.

When a+1>0, the solution set is x>1, which does not meet the requirements.

When a+1<0, the solution set is x<1, which satisfies the requirements of the problem, i.e., a+1<0, and the solution is a<-1

(a+1)x>a+1

X>(A+1) (A+1) (A≠-1) When A+1>0, X>1 When A+1<0, X<1 takes A+1<0, A<-1.

The solution set of inequalities x<1

So the range of a is (- 1).

If the move is (a+1)*(x-1)>0, then there is a+1>0 and x-1>0, or a+1<0 and x-1<0.

Because x<1, the former case is rounded off, and we get a+1<0, a<-1.

(a+1)x>a+1

A+1 on both sides of the unequal sign

Get x<1

A+1 is negative.

Therefore, the value range of a is a -1

Observe inequalities.

Explain that both sides are the same as the first A+1. . . The inequality has changed signs.

Description a+1<0

i.e. a<-1