Elementary School Math Problem Stunned Solve 5

1, Pleasant Goat shared (20a+5x) yuan.

2, Meiyang Yang spent (15b+5y) yuan, you know that Meiyang Yang bought alfalfa (15 kg) and rye grass Y kg.

3. Lazy sheep bought (100th of a) kilograms of Mexican corn grass.

4. If a=5, b=4, x=15, y=5, then Pleasant Goat has a total of 20 times 5 + 5 times 15 = 175 yuan, and a total of 20 + 15 = 35 kg of grass. Meiyang Yang used a total of 15 times 4 + 5 times 5 = 85 yuan, and bought a total of 15 + 5 = 20 kg of grass. The lazy sheep spent a total of 100 yuan to buy a total of 20 kilograms of grass.

Therefore, the beautiful goat uses the least money, and the pleasant goat buys the most.

1.(20a+5x) yuan.

kg alfalfa, y kg ryegrass.

3.(100 a) kilograms.

b=4, x=15, y=5 are substituted for :

Meiyang Yanghua is the least, using 15x4 + 5x5 = 85 yuan. The maximum amount of grass that Pleasant Goat buys is 20 + 15 = 35 kg.

kg of alfalfa, y kg of ryegrass.

kg of Mexican corngrass.

15b+5y=85, so the beautiful sheep spend the least money and the most joyful sheep.

1. Pleasant Goat spent a total of 20a+5x

2. Meiyang Yang bought: 15 kg of alfalfa, Y kg of rye grass.

3. Lazy sheep bought 100 a kilogram of Mexican corn grass.

4. Pleasant Goat spent 20 * 5 + 5 * 15 175 yuan Grass weight: 20 + 15 35 kg.

Meiyang spent 15 * 4 + 5 * 5 85 yuan grass weight: 15 + 5 20 kg.

Lazy sheep sheep spent 100 yuan Grass weight: 100 5 20 kg.

The beautiful sheep and sheep have the least flowers, and the pleasant goat buys the most grass.

1. Pleasant Goat goes (20a+5x) yuan.

2. Meiyang bought 15 kilograms of alfalfa and Y kilograms of ryegrass.

3. Lazy sheep bought 100 a kilogram of Mexican corn grass.

4. Pleasant Goat spent a total of 175 yuan, Meiyang spent a total of 85 yuan, and Lazy Goat spent 100 yuan;

Therefore, Meiyang Yang spent the least amount of money.

Pleasant Goat bought a total of 20 + 15 = 35 kg of grass, Meiyang bought a total of 15 + 5 = 20 kg of grass, and Lazy Goat bought 100 5 = 20 kg of grass;

So the Pleasant Goat buys the most grass.

1, Pleasant Goat shared () yuan.

A: 20a 5x

2, Meiyang Yang spent (15b+5y) yuan, do you know how many kilograms of alfalfa and ryegrass each Meiyang Yang buys?

Answer: 15 kg of alfalfa and y kg of ryegrass.

3. Lazy sheep sheep bought () kilograms of Mexican corn grass.

Answer: 100 a

4. If a=5, b=4, x=15, y=5, then which of the three of them spends the least money? Who buys the most grass?

Pleasant Goat: 20 5 5 15 Meiyang Sheep: 15 4 5 5 Lazy Goat: 100 yuan.

100 75 = 60 25 100 5 = 20 kg 175 yuan = 85 yuan

20 15=35 kg 15 5=20 kg Answer: Meiyang sheep uses the least money, and Pleasant Goat buys the most grass.

Mexican corngrass alfalfa ryegrass amount.

Unit price a b 5

Pleasant Goat 20 x=15 20a+5x =20*5+5*15=175Lazy Goat 100 a=100 5=20 100 Meiyang 15b 5y 15b+5y=15*4+5*5=85Answer: 20a+5x

15 y(5)

100 A beautiful sheep spend the least money, and the pleasant goat buys the most grass.

The beautiful goat uses the least money, and the pleasant goat buys the most.

The formula for the dividend, divisor, quotient, and remainder is as follows:

1. Dividend divisor = quotient.

2. Quotient = divisor.

3. Divisor quotient = dividend.

4. Divisor = (Dividend - Remainder) quotient.

5. Quotient = (dividend - remainder) divisor.

The arithmetic nature of division. 1. The dividend expands (shrinks) n times, and the divisor remains unchanged, and the quotient also expands (shrinks) n times accordingly.

2. The divisor expands (shrinks) n times, the dividend remains unchanged, and the quotient shrinks (expands) n times accordingly.

3. The dividend-being divided by two divisors consecutively is equal to the product of the two divisors.

Give the results first:

12+78 90, or 18 72 90;

90 36 54, or 90 56 34.

Let's solve it in detail.

Let the first row be a single digit, the second row a single digit b, the third row ten digit a c, the third row a single digit d, the fourth row ten digit an e, the fourth row a single digit f, and the fifth row ten digit g g.

From the meaning of the title, it is clear that C can only be 8 or 9, if C 8, then D 6, i.e. D 6, or 9, if D 6, then F 2, then A B 6, then A or B 2 or 4, so that there is a duplicate number, so D 6 can be excluded, then, D 9, then A≠1, 2, 4, 5, 7, 8, A 3 or 6, F 5, so E 2, G 6, or E 6, G 2, but there is a repeated 6, in summary, C ≠ 8.

Then there is only c 9, so a b 10, if d 0, then a 2, b 8;or A8, B2, F6, E3, G5;or E 5, G 3.

In the remaining case, if a b 12, then there must be a 6 in a and b, but it can only be 8, but if it is 8, then the remaining one in a and b is a 4, but 4 repeats again, so a b≠12;

If a b 13, then there will be f 9, which is a repeat of c 9, so it should also be excluded, obviously a b≠14, 4 is a repeating number, if a b 15, then it will be f 1, 5 1 4, but 1 is a repeating number, if a b 16, then a 7, b 9, or a 9, b 7, both of these numbers are repeating numbers, based on the above situation, it can be known that the number filled in is .

A2, B8, or A8, B2, C9, D0, F6, E3, G5, or E5, G3.

This question can be deduced from the back to the front: the difference is 4 subtracted and the subtraction can be, according to the meaning of the number can not be repeated, so the number can be , and then a group of tests, the end should be 12 + 78 = 90 36 = 54.

Fill in the left border first, then think about the right.

The last number in subtraction is 4, and the number cannot be repeated, so it is 10-6, and the addition is equal to 10, which requires the number 8 to be combined with 2, then 1+7+1 9, and finally the remaining 3 and 5 are complete.

This problem is unsolvable, and it will inevitably be repeated if you fill in a few numbers other than , so if you ask not to repeat this problem, it is unsolvable, and there is no such difficult math problem in elementary school.

From top to bottom, you can fill in 6 in the box in the first row, 0 in the box in the second row, 86 in the box in the third row, 2 in the box in the fourth row, and 3 in the last box.

Solution: or: 12 78 90

Similarly, the position of 2 and 8 can also be swapped.

There are many ways to answer this, such as 15+72 87 63 24

<> there may be multiple answers, and I'm not the only one who answers correctly.

2.Solution: Let the playground be 3xm long and 2xm

Then there is (3x+2x)*2=600

The solution is x=60, and the length is 180m, the width is 120m, and the area is 180*120=21600m2

A total of 600 trees were planted 10 = 60.

3。Solution: Let's say there are x people in the car right now.

(x-3)*(1-1 4)+15=x

The solution is x=51

1:1 51 (one in fifty).

2: 21,600 square meters, 58 trees.

3: 72 people.

One: The ratio of sugar to sugar water is 20:1

Two: 600 divided by 2 equals 300

3 plus 2 equals 5 300 times three fifths equals 180 300 times two fifths equals 120

180 times 120 equals 216 (square meters) A: The area of this playground is 216 square meters.

600 divided by 10 plus 1 equals 61 (trees) Answer: A total of 61 saplings are needed.

Three: (15 minus 3) divided by a quarter equals 48 (person) 48 times (1 minus a quarter) plus 15 equals 51 (person) Answer: There are 51 people in the car right now.

(1).1:50 sugar is 200 sugar water is 10000 10000 divided by 200 = 50

2）.600 divided by 2 = 300 (m) 3 + 2 = 5 (parts) 300 divided by 5 = 60 (m) Length: 3x60 = 180 (m) Width: 2x60 = 120 (m).

Area: 120x180 = 21600 (square meters) Second question: 600 divided by 10 = 60 (trees).

3）.15-3 = 12 (people) A quarter of the number of known seats is 1212x4=48 (people) 48+3=51 (people).

1 1:51

2 Because the circumference is 600 meters, one side and one strip length are 300 meters, and the aspect ratio is 3; 2, add 2 with 3, and divide 300 by 5 to get a portion, multiply by 2 and 3 respectively to get the length and width.

3 Because a quarter of the passengers have gone, 15 more people have boarded the bus, and 3 people have no seats, indicating that 12 people are a quarter of the total number, multiply 12 by 3, plus the extra 3 people, and this is the current number.

1 question is 1 to 6 2 questions are 86,400 square meters, and 59 seeds need to be planted.

1. 1:51

2.600*3 3+2=360 360 2=180 600*2 3+2=240 240 2=120 180*120=21600 square meters.

600 10 = 60 pieces.

3.Solution: Let's say there were x passengers on the bus at the beginning.

x-1/4x+15=x+3

3/4x-x=3-15

1/4x=-12

x=48 There are now 51 passengers on board. （48+3=51）

One: 200: 210

2: 600 divided by (3+2)*2=60 Length: 60*3=180 Width: 60*2=120 Area=180*120=21600

Tree planting: 600 10-2=58 (not so sure) Three: Treat the passengers in the car as a unit one.

When arriving at station B: 1-1 4=3 4

15-3=12 These people are equivalent to a quarter of the car.

The total number of people is: 12 divided by a quarter = 48 (people) plus those who have no place to sit = 48 + 3 = 51 (people).

Whistleblowing Question 1 20:21

The second question is 180*120=21600,600 10=60, and the third question (15+3)*4=72 people.

Column equations are also OK.

2.Set the length to 3x and the width to 2x

6x+4x=600 x=60

The length is 180 and the width is 120

Question 1 20:21

The second question is 180*120=21600, 600 10=60

Question 3 (15+3)*4=72 people.

1 just happens to be ** culture 200 to 1200 The ratio of sugar to sugar water is 1 to 6

I'll just ask the first question, hehe.

Hello mermin:

Outer diameter: 21 cm m.

Tube wall thickness: cm m.

Streams per second: cubic meters).

Can flow: cubic meters).

It is necessary to find the area of the inner tube: the radius of the inner tube is 21 cm) and the area of the inner tube is 10 (square cm²).

Then the square centimeter is converted to square meters: 314 square centimeters = square meters The flow rate is equivalent to the height of a cylinder, and finding how much water flows through is equivalent to finding the volume of a cylinder: The height is 5 (60 10) = 3000 (meters).

Volume is: cubic meters).

The outer diameter is 21 pipe wall thickness, so the inner diameter is 20cm radius 10cm = cross-sectional area r 2 = water velocity 5m s water flowing per second 10 minutes flowing water cubic meter.

Solution: The inner radius of the water pipe is: (, then: the water that can flow through this water pipe in 10 minutes is cubic meters).

The inner radius of the water pipe is:

Water pipes flow water in 10 minutes

The area of the shaded part is the area of the empty trapezoid below. Because it's all about the big triangle minus the small triangle.

The upper bottom of the trapezoid is 12-4=8, the lower bottom is 12, and the height is 3, so the area is (8+12) 3 2=30.

Take a look below and click to enlarge: