Urgent! Urgent! Urgent! Difficult math questions, good answers are a plus!

Question: There is a flock of sheep on the mountain, there is a flock of sheep under the mountain, one sheep on the mountain, there are as many sheep on the mountain as there are sheep under the mountain, one sheep on the mountain is twice as many as there is under the mountain, ask how many sheep are there on the mountain and under the mountain?

30 large sheep, 4 medium sheep, 4 small sheep. Question: There is a flock of sheep on the mountain, there is a flock of sheep under the mountain, one sheep on the mountain, there are as many sheep on the mountain as there are sheep under the mountain, one sheep on the mountain and twice as many as there are under the mountain, how many sheep are there on the mountain and under the mountain?

There are 5 sheep on the mountain and 3 sheep on the mountain.

Question: There was a woman who went to buy pork, she told the boss not to be skinny, not fat, not to have bones and thighs, not to have a head or tail, not to go into the water, the boss gave it to her, she asked how much, the boss said 123 321 1234567 7+8 8+7 9+10+11 The woman checked out the bill, and asked her what kind of meat she wanted and how much money she gave?

Insufficient conditions.

The number of large horses, medium horses, and small horses is abbreviated as large, medium, and small respectively: the analysis is as follows: large + medium + small = 100, 3 large + 2 medium + small = 100

So 6 big + 4 medium + small = 200, the comparison can be obtained: 5 big + 3 medium = 100, so large + medium = 20, large = medium, so, the number of horses is a multiple of 5, not more than 20, the horse takes a multiple of 5 and then counts the number of horses, and finally counts the number of horses: so the answer is as follows:

Big 20 out of 0 small 80, big 17 out of 5 small 78, big 14 out of 10 small 76, big 11 out of 15 small 74, big 8 out of 20 small 72, big 5 out of 25 small 70, big 2 out of 30 small 68In a total of 7 cases, the first may not meet the requirements of all three types of horses.

There are 5 sheep on the mountain and 3 sheep on the mountain.

Answer: She asked for pigskin, and gave 100 yuan, adding up the numbers mentioned by the boss.

Question 1. If there are x horses in big horses, y horses in horses, and small horses (100-x-y).

According to the title: 3x+2y+

5x+3y=100

This is an indefinite equation).

The special solution is: x0=2, y0=30

The general interpretation is x=x0-bt

y=y0+at

x=2-3t

y=30+5t

t is any integer).

Because x and y are both greater than 0, 2-3t is greater than 0, and 30+5t is greater than 0, and the solution is greater than -6 and less than 2 3

So t = 0, -1, -2, -3, -4, or -5 is substituted. x1=2 ； x2=5 ； x3=8 ； x4=11 ； x5=14 ； x6=17

y1=30 ； y2=25； y3=20 ； y4=15 ； y5=10 ； y6=5

To explain x0, y0 represents the special solution.

x1, y1 represents the first solution, x2, and y2 represents the second solution ......So the ponies have (omitted and denoted by z) z1=68;z2=70；z3=72；z4=74；z5=76；z6=78

By the way, criticize the upstairs and don't know, don't say that the problem is not rigorous.

Question 2. Set x on the mountain, y on the mountain, according to the title.

x-1=y+1

x+1=2（y-1）

The solution is x=7;y=5

Question 3. Khan, this is called a riddle, not a math problem.

She wants pig's blood (not meat at all), that's for sure.

It should be 100 (the numbers add up), if not.

How much money can you ask the Buddha, I won't guess the riddle.

Answer 1: Malaysia 8, Malaysia 20, Pony 72

A2 : Malaysia 11, Malaysia 15, Pony 74

A3 : Malaysia 14, Malaysia 10, Pony 76

A4 : Malaysia 17, Malaysia 5, Pony 78

7 sheep on the hill and 5 sheep on the hill.

|x-2|，|y-1|All are non-negative.

If it adds up to zero, it can only be 0, otherwise it is greater than 0.

So x=2, y=1

Find x+y to get the value of 5??? Check the questions.

|x-2|+|y-1|=0

Because the absolute value comes out as a positive number.

So only when.

x-2=0y-1=0 before the original formula can hold.

So x=2, y=1

The next drop will be calculated by yourself.

Let the trimmed triangle be cut to an edge length of x

So 2-2x = under the root number (square of x + square of x) to solve x=?

Then the side length of the octagon = under the root number (square of x + square of x) = 2-2xx=

Then the side length =

That is, the side length of the bar square is divided into three equal parts, and one of them is the side length of the octagon.

So the total side length of the octagon is.

12 phases, number of terms 2 tolerance = 126

Tolerance = 3 so yes.

xn should represent the meaning of the sum of the first n terms, sn is this meaning to analyze, s(n-2) = s(n) = -126, s (n + 1) = 126 is an increasing series, the first n terms and the impossible version from positive to negative, can only be in the (n-1) to n terms is x becomes positive, x(n+1) = s(n+1)-sn, x(n)+x(n-1)=s(n)-s(n-2), you can find the tolerance and the series, I don't know if this is the case, a little bit I don't understand the question.

But it's like bai

Upstairs said due to x1>x2

Knowing that it is a decreasing sequence of du, so the sum of the first n-2 terms should be dao126, the sum of the first n+1 terms is -126, and xn-1+xn=0, let the tolerance be d, the first term is a, and get three accommodating equations, from xn-1+xn=0, a can be represented by d, substituted by the other two equations, and d is moved to the side, and the range of n can be deduced from d<0 is n<4, but the first two equations will find n=5 2It's contradictory, so could it be that the topic is wrong? , because it is said that x1 xn is known to be an equal difference series, but there is also (xn+1).

If you change it to know that the absolute value of xn-1 = the absolute value of xn = the absolute value of (xn-3) = 126, there is no answer.